More on selectively star-ccc spaces

More on selectively star-ccc spaces

Topology and its Applications 268 (2019) 106905 Contents lists available at ScienceDirect Topology and its Applications www.elsevier.com/locate/topo...

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Topology and its Applications 268 (2019) 106905

Contents lists available at ScienceDirect

Topology and its Applications www.elsevier.com/locate/topol

More on selectively star-ccc spaces ✩ Yan-Kui Song a , Wei-Feng Xuan b,∗ a

Institute of Mathematics, School of Mathematical Science, Nanjing Normal University, Nanjing, 210046, China b School of statistics and Mathematics, Nanjing Audit University, Nanjing, 211815, China

a r t i c l e

i n f o

Article history: Received 26 June 2019 Received in revised form 28 September 2019 Accepted 29 September 2019 Available online 1 October 2019 MSC: primary 54D20 secondary 54E35 Keywords: Selectively star-ccc ccc Selectively 2-star-ccc Pseudocompact Strongly star-Lindelöf Regular closed Gδ -subspace

a b s t r a c t Bal and Kočinac in [2] introduced and studied the class of selectively star-ccc spaces. A space X is called selectively star-ccc if for every open cover U of X and for every sequence (An : n ∈ ω) of maximal pairwise disjoint open families in  X there exists a sequence (An : n ∈ ω) such that An ∈ An for every n ∈ ω and St( n∈ω An , U ) = X. In this paper, we first provide some sufficient conditions for ccc spaces to be selectively 2-star-ccc, which partially answer Problem 4.4 of Bal and Kočinac [2]. We give a Tychonoff example of a pseudocompact selectively 2-star-ccc which is not strongly star-Lindelöf, which gives a positive answer to Problem 4.8 from [2] and Question 3.11 from [16]. We also show that a regular closed Gδ -subspace of a Tychonoff pseudocompact selectively star-ccc space may not be selectively star-ccc. We finally prove that the product of a selectively star-ccc space and a Lindelöf space may not be selectively star-ccc. © 2019 Elsevier B.V. All rights reserved.

1. Introduction In 1996, Scheepers [15] started a systematic study of classical selection principles, which attracted a huge number of mathematicians to this field. Every selection principle give rise of some particular type of topological spaces, such as Rothberger spaces [14], Menger spaces [12], and star-Menger spaces [5–7]. In this paper, we use the following selection principle of the Rotheberger type. Let A and B be families of sets. Then S1 (A, B) is the selection principle: for every sequence (An : n ∈ ω) of elements of A one can select bn ∈ An , n ∈ ω, so that {bn : n ∈ ω} ∈ B. If O is the family of all open covers of a space X, then S1 (O, O) is the Rothberger covering property. If A is a subset of a space X and U is a family of subsets of X, then the star of a subset A ⊂ X with respect to U is the set ✩

The first author is supported by NSFC project 11771029. The second author is supported by NSFC project 11801271.

* Corresponding author. E-mail addresses: [email protected] (Y.-K. Song), [email protected] (W.-F. Xuan). https://doi.org/10.1016/j.topol.2019.106905 0166-8641/© 2019 Elsevier B.V. All rights reserved.

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St(A, U) =



{U ∈ U : U ∩ A = ∅}.

We also put St2 (A, U) = St(St(A, U), U). If A = {x} for some x ∈ X, then we write St(x, U) instead of St({x}, U) for simplicity. Kočinac applied this star operator in the field of selection principles and introduced and studied many selection principles using this operator (see [5–9]), which are termed as “star-selection principles theory” nowadays. Aurichi in [1] introduced and studied the class of selectively ccc spaces. Recall that a space X is a selectively ccc space if for every sequence (An : n ∈ ω) of maximal pairwise disjoint open families in X there  is a sequence (An : n ∈ ω) such that An ∈ An for every n ∈ ω and n∈ω An is dense in X. Recently, based on the notion of Aurichi’s selectively ccc spaces, Bal and Kočinac [2] introduced a star version of selectively ccc spaces. Definition 1.1. ([2]) A space X is called selectively star-ccc if for every open cover U of Xand for every sequence (An : n ∈ ω) of maximal pairwise disjoint open families in X, there is a sequence (An : n ∈ ω)  such that An ∈ An for every n ∈ ω and St( n∈ω An , U) = X. In [2], Bal and Kočinac discussed the relations between selectively star-ccc spaces and some other existing selective properties. Several examples were also given which makes selectively star-ccc spaces different from other spaces. In [16], Song and Xuan showed that there exists a Tychonoff selectively 2-star-ccc space which is neither strongly star Lindelöf nor selectively star-ccc, which gives a positive answer to a question of Bal and Kočinac [2]. Under 2ℵ0 = 2ℵ1 , Song and Xuan [16] even provide a normal example of a selectively 2-star-ccc space which is neither strongly star Lindelöf nor selectively star-ccc. It was also shown in the same paper that every open Fσ -subset of a selectively star-ccc space is selectively star-ccc. In this paper, we first provide some sufficient conditions for ccc spaces to be selectively 2-star-ccc, which partially answer Problem 4.4 of Bal and Kočinac [2]. We also give a Tychonoff example of a pseudocompact selectively 2-star-ccc which is not strongly star-Lindelöf, which gives a positive answer to Problem 4.8 from [2] and Question 3.11 from [16]. Moreover, we show that a regular closed Gδ -subspace of a Tychonoff pseudocompact selectively star-ccc space may not be selectively star-ccc. Finally, we prove that the product of a selectively star-ccc space and a Lindelöf space may not be selectively star-ccc. 2. Notation and terminology All topological spaces in this paper are assumed to be Hausdorff unless otherwise is stated. Throughout the paper, the cardinality of a set A is denoted by |A|. Let c denote the cardinality of the continuum, ω1 the first uncountable cardinal and ω the first infinite cardinal. For a pair of ordinals α, β with α < β, we write (α, β) = {γ : α < γ < β}, (α, β] = {γ : α < γ ≤ β} and [α, β] = {γ : α ≤ γ ≤ β}. As usual, a cardinal is an initial ordinal and an ordinal is the set of smaller ordinals. Every cardinal is often viewed as a space with the usual order topology. Definition 2.1. A space X satisfies the countable chain condition (abbreviated as ccc) if any disjoint family of open sets in X is countable, that is, the Souslin number (or cellularity) of X is at most ω. We note that the following property here called strongly star-Lindelöf, has different names in articles such as [10] and [18]. Definition 2.2. We say that a space X is strongly star-Lindelöf if for every open cover U of X, there exists a countable subset A of X such that St(A, U) = X.

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Definition 2.3. ([11]) A space X is absolutely countably compact if for every open cover U of X and every dense subset D of X, there exists a finite subset F of D such that St(F, U) = X. Clearly, a compact space is absolutely countably compact, and an absolutely countably compact Hausdorff space is countably compact. Definition 2.4. ([2]) A space X is called selectively 2-star-ccc if for every open cover U of Xand for every sequence (An : n ∈ ω) of maximal pairwise disjoint open families in X, there is a sequence (An : n ∈ ω)  such that An ∈ An for every n ∈ ω and St2 ( n∈ω An , U) = X. All notations and terminology not explained in the paper are given in [3]. 3. General results and examples In this section, we begin with some easy observations which look interesting. Theorem 3.1. Let X be a space which has a dense subset Y of isolated points. If for any open cover U of X there is a countable set D ⊂ Y such that St(D, U) = X, then X is selectively star-ccc. Proof. Let U be an open cover of X and let (An : n ∈ ω) be a sequence of maximal pairwise disjoint open families in X. It follows from our hypothesis that there is a countable set D = {dn : n ∈ ω} ⊂ Y such that St(D, U) = X. For each n ∈ ω, since the disjoint family An is maximal and dn is an isolated point of X, there exists An ∈ An such that dn ∈ An , and thus St(dn , U) ⊂ St(An , U). One can easily verify that X = St(D, U) = St(



An , U).

n∈ω

This proves that X is selectively star-ccc.

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The following result is an immediate consequence of Theorem 3.1. Corollary 3.2. If X is a space with a countable dense subset of isolated points, then X is selectively star-ccc. The next group of results give partial answers to Problem 4.4 of [2]. Theorem 3.3. If X is a Baire ccc space, then X is selectively 2-star-ccc. Proof. Let U be an open cover of X and let (An : n ∈ ω) be a sequence of maximal pairwise disjoint open    families in X. Clearly, An is dense in X for each n ∈ ω. Since X is Baire, it follows that D = { An : n ∈ ω} is dense in X. Since X is ccc, D is also ccc. Thus, for the open cover U of Y , there is a countable  subfamily W = {Un : n ∈ ω} ⊂ U such that D ⊂ W. Clearly, Un ∩ D = ∅ for each n ∈ ω. For each Un ∈ W, we may choose some dn ∈ D and An ∈ An such that dn ∈ Un and dn ∈ An . It follows that    Un ⊂ St(An , U), and so D ⊂ W ⊂ St( n∈ω An , U). Since D is dense in X, the set St( n∈ω An , U) is also  dense in X, which implies that St2 ( n∈ω An , U) = X. The proof is complete. 2 Theorem 3.4. If X is a ccc space which has a dense paracompact subspace, then X is selectively 2-star-ccc. Proof. Let Y be a dense paracompact subspace of X. Since X is ccc, the subspace Y has to be ccc. We claim that Y being ccc paracompact is Lindelöf. It is well known that every paracompact space with countable extent is Lindelöf, so if Y is not Lindelöf then Y must have an uncountable closed discrete subset D. Using

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the collectionwise normality of Y , D has an uncountable disjoint expansion, which contradicts the fact that Y is ccc. It was shown in [2] that every Lindelöf space is selectively star-ccc. Since Y is dense in X, we can deduce easily that X is selectively 2-star-ccc. The proof is complete. 2 Corollary 3.5. If X is a Čech-complete ccc space, then X is selectively 2-star-ccc. Proof. By a well known result of Šapirovskij [17], X contains a dense paracompact Čech-complete subspace. Theorem 3.4 does the rest. 2 Corollary 3.6. If X is a ccc space which has a dense metrizable subspace, then X is selectively 2-star-ccc. Proof. We only note that every metrizable space is paracompact. 2 Theorem 3.7. If X is a ccc space which has a dense monotonically normal subspace (hence, a dense GOspace), then X is selectively 2-star-ccc. Proof. The proof is similar to the one which was given in Theorem 3.4. We only note that every ccc monotonically normal space is (hereditarily) Lindelöf (see [4]). 2 The following example shows that a Tychonoff selectively 2-star-ccc pseudocompact space may not be strongly star Lindelöf, which answers the Problem 4.8 posed by Bal and Kočinac [2] and Question 3.11 by Song and Xuan [16]. We will use Alexandroff duplicate. Recall that A(X) is the Alexandroff duplicate of a space X if the underlying set of A(X) is X × {0, 1}; each point of X × {1} is isolated and a basic neighborhood of a point x, 0 ∈ X × {0} is of the form (U × {0}) ∪ ((U × {1}) \ {x, 1 }), where U is a neighborhood of x in X. It is evident that A(X) is countably compact if and only if X is countably compact. We also need the following lemma of Vaughan (see [19]). Lemma 3.8. If X is countably compact, then A(X) is absolutely countably compact, i.e., if for every open cover U of A(X) and every dense subset D of A(X), there exists a finite subset F of D such that St(F, U) = A(X). Example 3.9. There exists a Tychonoff pseudocompact selectively 2-star-ccc space which is not strongly star Lindelöf. Proof. Let D = {dα : α < c} be a discrete space of cardinality c and let βD be the Čech-stone compactification of D. Let Y = (βD × (c + 1)) \ ((βD \ D) × {c}) as a subspace of βD × (c + 1). Let X = A(Y ) \ ((D × {c}) × {1}). Clearly, the space X is a Tychonoff pseudocompact space, since A(βD × c) is a dense countably compact subspace of X. Next, we show that X is not strongly star Lindelöf. For each α < c, let Uα = A(({dα } × (c + 1)) \ {dα , c , 1 }.

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Then Uα is open in X and Uα ∩ Uα = ∅ whenever α = α . Let U = {Uα : α < c} ∪ {A(βD × c)}. Clearly, U is an open cover of X. Let B be a countable subset of X; then there exists β < c such that B ∩ Uβ = ∅, and thus dβ , c , 0 ∈ / St(B, U), since Uβ is the only element of U containing dβ , c , 0 and Uβ ∩ B = ∅, which shows that X is not strongly star Lindelöf. Finally, we show that X is selectively 2-star-ccc. We only need to show that A(βD × c) is selectively 1-star-ccc, since it is dense in X. To this end, let U be an open cover of X and (An : n ∈ ω) be a sequence of maximal pairwise disjoint open families in X. Let I be the set of all isolated points of c and let A = ((D × I) × {0}) ∪ {(βD × c) × {1}}. Then A be a dense subset of X and every point of A is isolated. Since βD×c is countably compact, A(βD×c) is absolutely countably compact by Lemma 3.8, there exists a finite subset F ⊂ A such that A(βD × c) ⊂ St(F, U). We can enumerate F as {xn : n ∈ ω}. For each n ∈ ω, since An is a maximal pairwise disjoint open family in X and xn is an isolated point of X, we may find some An ∈ An such that xn ∈ An , thus St(xn , U) ⊂ St(An , U). Therefore, we have A(βD × c) ⊂ St(F, U) ⊂ St(



An , U).

n∈ω

This shows that A(βD × c) is selectively star-ccc. The proof is complete.

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Bal and Kočinac in [2] pointed out that selectively star-ccc is not hereditary with respect to closed sets. We now give a Tychonoff pseudocompact example showing that selectively star-ccc even is not hereditary with respect to regular closed Gδ -subsets. Example 3.10. There exists a Tychonoff pseudocompact selectively star-ccc space having a regular closed Gδ -subset that is not selectively star-ccc. Proof. Let S1 be the space X in Example 3.9. Then S1 is Tychonoff pseudocompact. Let us first show that S1 is not selectively star-ccc. For each α < c, let Uα = A({dα } × (c + 1)) \ {dα , c , 1 }. Then Uα is open in S1 and Uα ∩ Uα = ∅ for α = α . Let U = {Uα : α < c} ∪ {A(βD × c)}. Clearly, U is an open cover of S1 . Let I be the set of all isolated points of c and let A = ((D × I) × {0}) ∪ {(βD × c) × {1}}.   Then A is a dense subset of S1 and every point of A is isolated. For each n ∈ ω, let An = {a} : a ∈ A ; then (An : n ∈ ω) is a sequence of maximal pairwise disjoint open families in S1 . Now let (An : n ∈ ω) be  a sequence such that for every n ∈ N, An ∈ An . Let B = n∈ω An ; clearly, B is countable. Hence, there

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exists β < c such that B ∩ Uβ = ∅, thus dβ , c , 0 ∈ / St(B, U), since Uβ is the only element of U containing dβ , c , 0 and Uβ ∩ B = ∅, which shows that S1 is not selectively star-ccc. Let S2 = ω ∪ R be the Isbell-Mrówka space (see [13]), where R is a maximal almost disjoint family of infinite subsets of ω with |R| = c. It is well-known that S2 is Tychonoff pseudocompact. Since ω is a countable dense subset of isolated points of S2 , then S2 is selectively star-ccc by Corollary 3.2. We assume that S1 ∩ S2 = ∅. Since |R| = c, we can enumerate R as {rα : α < c}. Let Z be the quotient space of the discrete sum S1 ⊕ S2 by identifying dα , c , 0 with rα for each α < c. Now we show that the space Z is as required. It is evident that the space Z is Tychonoff pseudocompact by the construction of the topology of Z. Let ϕ : S1 ⊕ S2 → Z be the quotient map. Then ϕ(S1 ) is a regular closed subspace of Z. For each n ∈ ω, let Un = ϕ(S1 ∪ {m : m ≥ n}).  Then Un is open in Z and ϕ(S1 ) = n∈ω Un . Thus ϕ(S1 ) is a regular-closed Gδ -subset of Z. However ϕ(S1 ) is not selectively star-ccc, since it is homeomorphic to S1 . Finally, we prove that Z is selectively star-ccc. Let U be an open cover of Z. Let E = ϕ(A ∪ ω) (note that the set A has been defined before); then E is a dense subset of isolated points of Z. Thus we only need to show that there exists a countable subset C of E such that St(C, U) = Z by Theorem 3.1. Since ϕ(S2 ) is homeomorphic to S2 , then π(S2 ) ⊂ St(ϕ(ω), U). On the other hand, since ϕ(A(βD × c)) is homeomorphic to A(βD × c) and βD × c is countably compact, thus ϕ(A(βD × c)) is absolutely countably compact by Lemma 3.8, we may find a finite subset F ⊂ ϕ(A) such that ϕ(A(βD × c)) ⊂ St(F, U). Let C = ϕ(ω) ∪ F . Then C is a countable subset of E such that St(C, U) = Z. The proof is complete.

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Note that the product of a selectively star-ccc space and a Lindelöf space may not be selectively star-ccc, as can be seen in the next example. Example 3.11. There exists a selectively star-ccc space X and a Lindelöf space Y such that the product X × Y is not selectively star-ccc. Proof. Let X = ω1 with the usual order topology. Being countably compact, the space X is absolutely countably compact. Thus X is selectively star-ccc by Theorem 3.1, since the set of all the isolated points of X is dense. Let D = {dα : α < ω1 } be a discrete space of cardinality ω1 and let Y = D ∪ {d∗ } be one-point Lindelöfication of D , where d∗ ∈ / D . Now we show that X × Y is not selectively star-ccc. For each α < ω1 , let Uα = (α, ω1 ) × {dα }. Then Uα is open in X × Y and Uα ∩ Uα = ∅ for α = α . Let V = (X × Y ) \ (



Uα ).

α<ω1

It is not difficult to see that V is open in X × Y . Let U = {Uα : α < ω1 } ∪ {V }. Then U is an open cover of X × Y . Let S be the set of all isolated points of ω1 and let D = S × D . Then D   is a dense subset of X × Y and every point of D is isolated. For each n ∈ ω, let An = {d} : d ∈ D . Then, one can easily see that (An : n ∈ ω) is a sequence of maximal pairwise disjoint open families in X × Y .

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 Let (An : n ∈ ω) be a sequence such that for every n ∈ ω, An ∈ An . Let A = n∈ω An ; then A is countable. Thus f (A) is a countable subset of X, where f : X × Y → X is the projection. Therefore, there exists β < ω1 such that f (A) ∩ Uβ = ∅. Pick some α < ω1 such that α > β. Then α, dβ ∈ / St(A, U), since Uβ is the only element of U containing α, dβ . Therefore, X × Y is not selectively star-ccc. The proof is complete. 2 We finish the paper by the following questions which still are open. Question 3.12. ([2]) Does ccc property of a topological space implies selectively 2-star-ccc property? Question 3.13. ([16]) Is there a normal example in ZFC of a selectively 2-star-ccc space which is not strongly star Lindelöf? Acknowledgements We would like to thank the referee for his (or her) valuable remarks and suggestions which improved the paper. References [1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15] [16] [17] [18] [19]

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