International Journal of Heat and Mass Transfer 43 (2000) 3621±3632
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An analytical solution to coupled heat and moisture diusion transfer in porous materials Win-Jin Chang a,*, Cheng-I Weng b a
Department of Mechanical Engineering, Kung Shan Institute of Technology, Tainan, Taiwan b Department of Mechanical Engineering, National Cheng Kung University, Tainan, Taiwan Received 16 September 1999; received in revised form 7 December 1999
Abstract An analytical method is proposed for solving the problem of coupled heat and moisture transfer in porous materials. The coupled partial dierential equations and boundary conditions are ®rst subjected to Laplace transformation, the equations are reduced to ordinary dierential equations, then the equations are converted into a single fourth-order ordinary dierential equation by introducing a transformation function. The solution of the equation can be easily obtained, and thus, the temperature and moisture distributions in the transform domain can be determined. Finally, the transformed values are analytically or numerically inverted to obtain the time domain results. Therefore, the transient solution at any given time can be evaluated. The results are identical with published analytical solutions for a special case using decoupling technique, and they agree with a published analytical solution for wood slab. The method is compact enough to be generally applied to problems of heat and mass transfer in porous media. # 2000 Elsevier Science Ltd. All rights reserved.
1. Introduction Simultaneous heat and moisture transfer accompanied by phase change and/or absorption heat in some porous and composite materials is a process which occurs frequently in various engineering applications. The moisture movement contributes to heat transfer, while phase-change and/or heat of absorption within the material act as heat sources or sinks. The coupled system for temperature and moisture potential can be handled through both analytical and numerical approaches, depending on complexities of the speci®c problem considered. For linear problems, the analytical solutions, based on classical integral transform approach, have been obtained by Mikhailov
* Corresponding author. E-mail address:
[email protected] (W.-J. Chang).
et al. [1]. It was later discovered by the same group [2] that the existence of complex eigenvalues, not accounted for in the solutions previously reported, could signi®cantly alter the temperature and moisture distributions. Liu et al. [3] later recon®rmed such ®ndings by discovering a pair of complex eigenvalue. Recently, Mikhailov et al. [4] again found another complex eigenvalue. In the cited papers, there exist numerical diculties in computing the complex conjugate eigenvalues that lead to an incorrect solution containing high frequency oscillation of limited usefulness. Chang et al. [5] applied a decoupling technique to coupled governing equations, but failed to address the case of simultaneous coupling of governing equations and boundary conditions. Ribeiro et al. [6] treated the coupled system by applying the generalized integral transform technique with complicated procedures. Recently, Cheroto et al. [7] presented a modi®ed lumped system analysis method to yield approximate
0017-9310/00/$ - see front matter # 2000 Elsevier Science Ltd. All rights reserved. PII: S 0 0 1 7 - 9 3 1 0 ( 0 0 ) 0 0 0 0 3 - X
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Nomenclature cm cp C D Dm hC hm hLV I0 I1 J0 J1 k K0 K1 ` L m m0
moisture capacity (kg/kg 8M) heat capacity (J/kg K) moisture content (kg/kg) equivalent diusion coecient of moisture content (m2/s) conductivity coecient of moisture content (kg/m s 8M) convective heat transfer coecient (W/m2 K) convective moisture transfer coecient (kg/m2 s 8M) heat of phase change (kJ/kg) modify Bessel function of the ®rst kind of order zero modify Bessel function of the ®rst kind of order ®rst Bessel function of the ®rst kind of order zero Bessel function of the ®rst kind of order ®rst thermal conductivity (W/m K) modify Bessel function of the second kind of order zero modify Bessel function of the second kind of order ®rst half thickness of specimen (m) equivalent diusion coecient of temperature (m2/s) moisture potential (8M) initial moisture potential (8M)
solutions, avoiding diculties experienced by Mikhailov et al., Liu et al., and Ribeiro et al., but sacri®cing accuracy. In this paper, a dierent analytical approach is developed. The coupled system is ®rst subjected to Laplace transformation. The coupled partial dierential equations thus are reduced to the coupled ordinary dierential equations. Then, the temperature and moisture in the transformed domain are expressed in terms of a transformation function. Consequently, the system of ordinary dierential equations can be reduced to a single fourth-order ordinary dierential equation. The solution of the equation can be obtained and the coecients are determined from the boundary conditions. Finally, the transformed solution can be analytically or numerically inverted to yield the time domain results. 2. Problem formulation A typical heat and mass transfer problem is governed by Luikov's equations [8], which relate to drying a porous moist slab under constant pressure. The phase-change occurring within the slab act as heat
m S t T T0 T Y0 Y1
Laplace transformation Laplace transformation time (s) temperature (K) initial temperature (K) Laplace transformation Bessel function of the zero Bessel function of the ®rst
of m parameter
of T second kind of order second kind of order
Greek symbols r material density (kg/m3) n coupling coecient due to moisture migration (K/8M) l coupling coecient due to heat conduction (8M/K) f transformation function g heat of absorption or desorption (kJ/kg) e ratio of vapor diusion coecient to coecient of total moisture diusion Subscripts 0 initial condition m moisture 1 ambient atmosphere
source or sink resulting in the coupled relationship between mass transfer and heat transfer. In a coupled problem, the heat of absorption or desorption is generally one of the sources or sinks as well. This heat is not negligible for some hygrothermal materials [9,10]. In the present study, one-dimensional governing equations with coupled temperature and moisture for a porous slab are considered, and the eect of the absorption or desorption heat is added. Material properties and pressure are considered to be constant throughout the material. A local thermodynamic equilibrium between the ¯uid and the porous matrix is assumed. Moreover, the coupled equations can be generalized to apply to cases of hollow cylindrical and hollow spherical geometries. The equations are rcp x 1ÿ2n
@T @ @T @m k x 1ÿ2n rcm
ehLV gx 1ÿ2n @t @x @x @t
1a
rcm x 1ÿ2n
@m @ @m @ @T Dm x 1ÿ2n Dm d x 1ÿ2n @t @x @x @x @x
1b
W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
where n 1=2 for slab, n 0 for hollow cylinder, and n ÿ1=2 for hollow sphere. T is the temperature, and m is the moisture potential, k and Dm are the thermal and moisture conductivity coecients, respectively, cp and cm are the heat and moisture capacities of the medium, respectively, r is the material density, hLV is the heat of evaporative phase-change, g represents the heat of absorption or desorption, d is the thermogradient coecient, and e is the ratio of the vapor diusion coecient to the coecient of total moisture diusion. All the material properties mentioned above are eective properties. The moisture potential m is related to the moisture content C, and C cm m
2
The coupling diusion system represented by Eqs. (1a) and (1b) contains not only general diusion equations, but also some source or sink terms. The governing equation (1a) expresses the balance of thermal energy within the body; the last term in this equation represent the heat sources or heat sinks due to liquid-tovapor phase-change and to the heat of absorption or desorption. Similarly, Eq. (1b) expresses the balance of moisture within the medium; the last term in this equation represents the moisture source or moisture sink with respect to the temperature gradient. To simplify the notation, dividing Eq. (1a) by rcp x 1ÿ2n and using the expression for @ =@ x
x 1ÿ2n @ T=@ x obtained from Eq. (1a) into Eq. (1b), then rearranging the two new equations, yields @ @T @T @m x 1ÿ2n ÿn
3a Lx 2nÿ1 @x @x @t @t @ @m @m @T Dx 2nÿ1 x 1ÿ2n ÿl @x @x @t @t
3b
D
k rcp
4a
kDm rcm k Dm d
ehLV g
4b
cm
ehLV g n cp
l
cp Dm d cm k Dm d
ehLV g
duction, respectively; L and D are also always positive expressing the equivalent temperature diusion coef®cient and the equivalent moisture diusion coecient, respectively. The moisture in Eq. (3a) will play the role of a heat source for the temperature distribution, if the moisture rate is positive (i.e. @ m=@ t > 0), and act as a heat sink if the moisture rate is negative (i.e. @ m=@ t < 0). Similarly, the temperature may play the role of a moisture source or a moisture sink, depending on the temperature rate being positive or negative. Therefore, the coupling diusion system rewritten as Eqs. (3a) and (3b) more compactly and clearly represents the same physical process modeled by Eqs. (1a) and (1b). At the boundaries of the domain, the latent heat of vaporization becomes part of the energy balance, and the mass diusion caused by the temperature and moisture gradients aects the mass balance. The associated hygrothermal boundary and initial conditions are k
@ T
x 1 , t hC1 T
x 1 , t ÿ T11 @x
1 ÿ e hLV hm1 m
x 1 , t ÿ m11
5a
@ T
x 2 , t hC2 T
x 2 , t ÿ T12 @x
1 ÿ e hLV hm2 m
x 2 , t ÿ m12
5b
ÿk
@ m
x 1 , t @ T
x 1 , t Dm d @x @x hm1 m
x 1 , t ÿ m11
5c
@ m
x 2 , t @ T
x 2 , t ÿ Dm d @x @x hm2 m
x 2 , t ÿ m12
5d
Dm
ÿDm
where L
3623
4c
4d
In Eqs. (3a) and (3b), n and l are positive coupling coecients due to moisture migration and heat con-
T
x, 0 T0
6a
m
x, 0 m0
6b
Eqs. (5a)±(5d) constitute the natural boundary conditions for temperature and moisture, respectively. Eqs. (5a) and (5b) represent the heat balance at x x 1 and x x 2 : The two equations express the heat ¯ux in terms of convection heat transfer and the phase-change energy transfer. Eqs. (5c) and (5d) represent the moisture balance at the two surfaces; the two terms on the left-hand side of the equal sign describe the supply of moisture ¯ux under the in¯uence of a temperature gradient and a moisture gradient, respectively. The
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terms to the right side of the equal sign describes the amount of moisture drawn o from or into the surfaces. Eqs. (6a) and (6b) represent initial temperature and moisture value within the domain, respectively.
3. Method of solution Applying the Laplace transformation to Eqs. (3a), (3b), (5a)±(5d) and (6a), (6b) with respect to t, they become 2nÿ1 d 1ÿ2n dT Lx x ST ÿ T0 ÿ nSm nm0
7a dx dx Dx 2nÿ1
d dm x 1ÿ2n Sm ÿ m0 ÿ lST lT0 dx dx
1 , S dT
x 1 , S ÿ T11 k hC1 T
x dx S m11 1 , S ÿ
1 ÿ e hLV hm1 m
x S
n
ji
Slab Hollow cylinder
1/2 0
Hollow sphere
ÿ1/2
e pi x I0
pi x for i 1, 2 K0
pi x for i 3, 4 e pi x =x
S n f
x, S T0 T
x, L S
10a
1 1 d df m0 f
x, S ÿ x 2nÿ1 x 1ÿ2n L S dx dx S
m
x, S
10b we ®nd that Eq. (7a) is automatically satis®ed and Eq. (7b) becomes
8a
ÿk
1 , S 1 , S dm
x dT
x Dm d dx dx m11 1 , S ÿ hm1 m
x S
Geometry
7b
2 , S dT
x 2 , S ÿ T12 hC2 T
x dx S m12 2 , S ÿ
1 ÿ e hLV hm2 m
x S
Table 1 The functions ji
x, S , shown in Eq. (12), for slab, hollow cylinder and hollow sphere
8b
d 1ÿ2n d 2nÿ1 d 1ÿ2n df x x x x dx dx dx dx S D d df ÿ x 2nÿ1 x 1ÿ2n 1 D L dx dx 2nÿ1
11
S 2
1 ÿ nl f0 LD
Therefore, the system of coupled ODE equations (7a) and (7b) is reduced to a single Eq. (11). Eq. (11) is a fourth-order ODE. Assume the solution of f
x, S in the following form
Dm
8c
f
4 X xi
S ji
x, S
12
i1
2 , S 2 , S dm
x dT
x ÿ Dm d dx dx m12 2 , S ÿ hm2 m
x S
ÿDm
8d
where ji represents dierent functions, as shown in Table 1, for slab, hollow cylindrical and hollow spherical geometries. p In Table 1, pi Sqi , in which qi is de®ned as 2
0 T0 T
x, S
9a
31=2 s 2 ai 4 D D 4lnD 5 qi p 1 bi 1ÿ L L L 2D
m0 S
9b
and where
m
x, 0
and m
S are the Laplace transformation where T
S of T
t and m
t, respectively; and S is Laplace transformation parameter. Introducing a transformation function f
x, S such that
8 <1 ai 1 : ÿ1 and
for i 1, 2 for i 1, 2, 3, 4 for i 3, 4
13
if slab and hollow sphere if hollow cylinder if slab and hollow sphere
W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
bi
ÿ1 for i 1, 3 : 1 for i 2, 4
Q1
The coecients xi
S
i 1, 2, 3, 4 can be determined by using Eqs. (8a)±(8d). The results are then written in the matrix form K x
S fQg
14
in which 0
K11 B K21 K B @ K31 K41
K12 K22 K32 K42
1
K13 K23 K33 K43
K14 K24 C C K34 A K44
T x
S x1
S , x2
S , x3
S , x4
S
15a
15b
15c
T
where fx
S g and fQg stand for the transpose of fx
S g and fQg, respectively, and where K1j
1 ÿ e hLV hm1 2nÿ1 d djj kn djj 1ÿ2n x x dx L dx S dx 1 ÿ hC1 n
1 ÿ e hLV hm1 jj L at x x 1 , j 1, 2, 3, 4
16a
1 ÿ e hLV hm2 2nÿ1 d djj kn djj K2j x 1ÿ2n x ÿ dx L dx S dx 1 ÿ hC2 n
1 ÿ e hLV hm2 jj L at x x 2 , j 1, 2, 3, 4
16b djj Dm d d x 2nÿ1 x 1ÿ2n S dx dx dx djj hm1 2nÿ1 d 1ÿ2n x x dx S dx djj hm1 Dm
dn 1 ÿ j L dx L j at x x 1 , j 1, 2, 3, 4
K3j ÿ
K4j
1 hC1
T0 ÿ T11
1 ÿ e hLV hm1
m0 ÿ m11 S
16e 1 hC2
T0 ÿ T12
1 ÿ e hLV hm2
m0 ÿ m12 S
16f
Q3
hm1
m0 ÿ m11 S
16g
Q4
hm2
m0 ÿ m12 : S
16h
The solution of Eq. (14) can be determined by Cramer's rule. xi
S
T Q Q1 , Q2 , Q3 , Q4 T
Q2
djj Dm d d x 2nÿ1 x 1ÿ2n dx S dx dx djj hm2 2nÿ1 d 1ÿ2n x x dx S dx djj hm2 Dm
dn 1 ÿ j ÿ L dx L j at x x 2 , j 1, 2, 3, 4
3625
jZi j , jKj
i 1, 2, 3, 4
17
where jZi j is the determinant of the matrix resulting from K in which the ith column is replaced by the column vector fQg: Substituting Eq. (17) into Eq. (12), Eqs. (10a) and (10b) can be rewritten as 4 X T0 S n T
x, x
S ji
x, S L i1 i S
m
x, S
4 X 1 i1
m0 ÿ q2i xi
S ji
x, S : L S
18a
18b
As it is dicult in general to ®nd the inverse Laplace S and m
x, transformation of the functions T
x, S analytically, a numerical inversion method [11] may be used. This method has been proven to yield accurate results in previous research [12]. However, for some special cases, the functions at any given time can be evaluated using the inversion theorem for the Laplace transformation. 4. Analysis of a special case
16c
16d
As a special case of the foregoing analysis, we now consider an in®nitely long hollow cylinder, having inner and outer radii x 1 and x 2 , respectively, subjected to symmetrical hygrothermal loadings. The mathematical formulation is expressed as follows: 1 @ @T @T @m L x ÿn
19a x @x @x @t @t D
1 @ @m @m @T x ÿl x @x @x @t @t
19b
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W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
T
x 1 , t T1 ,
T
x 2 , t T1
m
x 1 , t m0 ,
m
x 2 , t m0
T
x, 0 T0 ,
m
x, 0 m0 :
20
In this problem, the moisture contains vapor phase only, then the phase change within the cylinder is excluded. A similar problem have been solved in previous research [5] by using decoupling techniques. Comparing the present problem with the previous general problem, we ®nd that hC1 hC2 hC 4 1,
hm1 hm2 hm 4 1,
p1 p3 ,
p2 p4 , m11 m12 m1 m0 , L Fig. 1. Schematic representation of the wood slab.
k , rcp
D
q1 q3 ,
kDm , rcm
k Dm dg
cp Dm d l : cm
k Dm dg
Fig. 2. Temperature at the center and surface of wood specimen for case 1.
q2 q4 ,
n
cm g , cp
hLV 0,
21
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3627
This problem is a special case of the coupled system discussed previously. The corresponding coecients are now reduced to 2
n 6 L I0
p1 x 1 6 6n 6 I0
p1 x 2 6L 6 K 6 6 1 2 6 ÿ q1 I0
p1 x 1 6 L 6 6 4 1 ÿ q21 I0
p1 x 2 L
fQgT
T1 ÿ T0 , S
n I0
p2 x 1 L n I0
p2 x 2 L 1 2 ÿ q2 I0
p2 x 1 L 1 ÿ q22 I0
p2 x 2 L
T1 ÿ T0 , S
n K0
p1 x 1 L n K0
p1 x 2 L 1 2 ÿ q1 K0
p1 x 1 L 1 ÿ q21 K0
p1 x 2 L
3 n K0
p2 x 1 7 L 7 7 n 7 K0
p2 x 2 7 L 7 7 1 7 2 ÿ q2 K0
p2 x 1 7 7 L 7 7 5 1 ÿ q22 K0
p2 x 2 L
22
0,
23
0
Then xk
S in Eq. (17) can be simpli®ed as xk
S
L
T1 ÿ T0 1 1 2 2 ÿ 2 ÿ q ÿ q g Zk k 2 1 L L Sn q2 ÿ q21 ÿp ÿp ÿp ÿp K0 Sqk x 2 ÿ K0 Sqk x 1
d1k d2k I0 Sqk x 1 ÿ I0 Sqk x 2
d3k d4k ÿp ÿp ÿp ÿp , I0 Sqk x 1 K0 Sqk x 2 ÿ I0 Sqk x 2 K0 Sqk x 1
k 1, 2, 3, 4
24
where gk
ÿ1 for k 1, 3 0 for k 2, 4
and Zk
0 for k 1, 3 1 for k 2, 4
and dij is the Kronecker delta which is de®ned as dij
1 when i j 0 when i 6 j
Consequently, Eqs. (18a) and (18b) become 2 X 1 1 2 2 S Tÿ 1 ÿ T0 T
x, ÿ q ÿ q ÿ d 1n 2 1 d2n L L S q22 ÿ q21 n1 ÿp ÿp ÿp ÿp ÿp ÿp T0 K0 Sqn x 2 ÿ K0 Sqn x 1 I 0 Sqn x I0 Sqn x 1 ÿ I0 Sqn x 2 K0 Sqn x ÿp ÿp ÿp ÿp S I0 Sqn x 1 K0 Sqn x 2 ÿ I0 Sqn x 2 K0 Sqn x 1
m
x, S
ÿ 2 ÿ L
T1 ÿ T0 L1 ÿ q21 L1 ÿ q22 X ÿ 2 ÿ d1n d2n Sn q2 ÿ q21 n1 ÿp ÿp ÿp ÿp ÿp ÿp m0 K0 Sqn x 2 ÿ K0 Sqn x 1 I0 Sqn x I0 Sqn x 1 ÿ I0 Sqn x 2 K0 Sqn x ÿ ÿ ÿ ÿ p p p p S I0 Sqn x 1 K0 Sqn x 2 ÿ I0 Sqn x 2 K0 Sqn x 1
25a
25b
The temperature and moisture distributions in the transformation domain, Eqs. (25a) and (25b) can be transformed to time domain by the inversion theorem for the Laplace transformation [13]. From the theorem we then have
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W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
Fig. 3. Moisture content at the center and surface of wood specimen for case 1.
Wk
x, t
T1 ÿ T0 ÿ 2pi q22 ÿ q21
gi1 1 1 2 ÿ ÿ q2 L gÿi1 z L 1 U1 d1k ÿ q21 d2k n L V1 1 L 1 U2 2 2 ÿ q1 d1k ÿ q2 d2k L n L V2 ezt dz T0 d1k m0 d2k
26
where k 1, 2; W1 and W2 represent T and m, respectively; and ÿp ÿp ÿp Uk K0 zqk x 2 ÿ K0 zqk x 1 I0 zqk x ÿp ÿp ÿp I0 zqk x 1 ÿ I0 zqk x 2 K0 zqk x ezt , k 1, 2
27a
ÿp ÿp ÿp ÿp Vk I0 zqk x 1 K0 zqk x 2 ÿ I0 zqk x 2 K0 zqk x 1 , k 1, 2
27b The singularities of the integrand are z 0, p p zq1 ian , and zq2 ian , which correspond to the simple poles z 0, z ÿa2n =q21 , z ÿa2n =q22 , respect-
ively, where an satis®es J0
an x 1 Y0
an x 2 ÿ J0
an x 2 Y0
an x 1 0
28
Note that the relationships I0
ian x J0
an x and K0
ian x ÿpi 2 J0
an x ÿ iY0
an x are used to obtain the above equation. Using the residue theorem to evaluate Eq. (26), yields Wk
x, t
T1 ÿ T0 d1k Res
0 ÿ ÿ L1 ÿ q22
T1 ÿ T0 2 q ÿ q21 2 L 1 2 ÿ q1 d2k d1k n L ! 1 1 X ÿ q21 a2 Res ÿ n2
T1 ÿ T0 L2 q1 q2 ÿ q21 n1 L 1 d1k ÿ q22 d2k n L ! 1 X a2n Res ÿ 2 T0 d1k m0 d2k q2 n1 k 1, 2:
29
W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
The residue at z 0 can be evaluated for small arguments I0
z11, I1
z1z=2, K0
z1 ÿ ln z, and K1
z11=z; then the limit can be taken by letting z 4 0, that is Res
0 1:
30
The residue at z ÿa2n =q21 , and z ÿa2n =q22 may be obtained from ! ÿ Uk ÿ a2n =q2k a2n Res ÿ 2 , ÿa2n =q2k
dVk =dzzÿa2n =q2 qk
31 k k 1, 2: Dierentiating Eq. (27b), we have
ÿ x 2 I1
ÿp ÿp zqk x 2 K0 zqk x 1
ÿp ÿp x 1 I0 zqk x 2 K1 zqk x 1
p In Eq. (32), inserting ian in place of zqk , and using the relationships I0
zK1
z I1
zK0
z 1=z, I0
ian x J0
an x, and Vk 0 in Eq. (27b), the following form is obtained J 2
an x 2 ÿ J 20
an x 1 a2n dVk ÿ 2 0 , 2J0
an x 1 J0
an x 2 qk dz zÿa2n =q2k
32
33
k 1, 2: Similarly,
Uk
ÿp ÿp dVk qk 1=2 x 1 I1 zqk x 1 K0 zqk x 2 dz 2z ÿp ÿp ÿ x 2 I0 zqk x 1 K1 zqk x 2
3629
a2 ÿ 2n qk
!
p Y0
an x 2 ÿ Y0
an x 1 J0
an x 2 J0
an x 1 ÿ J0
an x 2 Y0
an x 2 2 eÿ
an =qk t , k 1, 2
34
ÿ
Finally, substituting Eqs. (33) and (34) into Eq. (31), and then substituting Eqs. (31) and (30) into Eq. (29), the following results are obtained:
Fig. 4. Temperature at the center and surface of wood specimen for case 2.
3630
W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
Fig. 5. Moisture content at the center and surface of wood specimen for case 2.
Wk
x, t
T1 ÿ T0 d1k ÿ p
T1 ÿ T0
1 J a x X 0
n 1 ÿ J0
an x 2 J0
an x Y0
an x 2 ÿ J0
an x 2 Y0
an x J 20
an x 1 ÿ J 20
an x 2
n1
J0
an x 1
( ÿ ) 1 2 ÿ L1 ÿ q22 L 1 L 1 2 ÿ
a2n =q21 t 2 ÿ
a2n =q22 t L ÿ q1 ÿ q1 d2k e T0 d1k d1k 2 ÿ q2 d2k e d1k n L n L q2 ÿ q21 q22 ÿ q21
35
m0 d2k k 1, 2
In order to compare the results written in Eq. (35) with the results of [5], Eq. (35) can be rewritten as follows: T
x, t ÿ T0 p 1ÿ T1 ÿ T0 B1 B2 1 X J0
an x 1 ÿ J0
an x 2 J0
an x 1 U0
an x J 20
an x 1 ÿ J 20
an x 2 ÿ 2 2 2 2 B1 eÿan t=q1 B2 eÿan t=q2
m
x, t ÿ m0 pLB1 B2 l
T1 ÿ T0 D
B1 B2 1 J a x X 0
n 1 ÿ J0
an x 2 J0
an x 1 U0
an x J 20
an x 1 ÿ J 20
an x 2 n1 ÿ 2 2 2 2 ÿ eÿan t=q1 eÿan t=q2
36b
where
n1
36a
U0
an x J0
an x Y0
an x 2 ÿ J0
an x 2 Y0
an x
37a
W.-J. Chang, C.-I. Weng / Int. J. Heat Mass Transfer 43 (2000) 3621±3632
B1
1 ÿ Dq21 nl
37b
B2
Dq22 ÿ 1 nl
37c
and where
T ÿ T0 =
T1 ÿ T0 and
m ÿ m0 =l
T1 ÿ T0 are dimensionless forms of T and m, respectively. The temperature and moisture distributions, as written in Eqs. (36a) and (36b), are identical to those obtained by previous research [5].
5. Numerical results and discussions Now we consider a wood slab, subjected to symmetrical hygrothermal loadings; the heat and moisture transfer are coupled within the slab and its boundaries. Two cases are discussed here. For case 1, the coupled system is modeled by Eqs. (3a), (3b) to (6a), (6b). The geometry and the material properties of the wood slab shown in Fig. 1, which were used by Liu et al. [3], are used in the numerical calculations for comparison. Therefore, absorption heat in Eqs. (3a) and (3b) is assumed to be negligible and the geometry and boundary conditions in Eqs. (5a)±(5d) are assumed to be symmetric. The results can be obtained from Eqs. (18a) and (18b), and the data are as follows: n 1=2,
T0 108C,
T1 1108C,
m1 48M, r 370 kg=m3 ,
m0 868M,
k 0:65 W=
m K ,
Dm 2:2 10ÿ8 kg=
m s 8M , hLV 2500 kJ=kg, e 0:3,
cp 2500 J=
kg K,
d 2:08M=K, s 8M ,
hC1 hC2 hC 2:25 W=
m2 K , cm 0:01 kg=
kg 8M,
hm1 hm2 hm 2:5 10ÿ6 kg=
m2
` 0:012 m,
g 0:
For case 1, the temperature and moisture evolution at the surface and at the middle of the slab are shown in Figs. 2 and 3. It can be seen that the results from the two dierent methods agree well, even though the initial moisture content deviates a little, as shown in Fig. 3. The discrepancies might be caused by not including enough complex eigenvalues when using the eigenvalue method [3,4]. For case 2, to evaluate the ambient temperature eects on the moisture of the medium during drying, we make T0 T1 258C, and the other data are kept the same as for case 1. Fig. 4 shows the temperature evolution at the surface and at the center of the slab.
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The temperature of the slab at initial time is equal to that of the atmosphere, while the moisture of the slab is higher than that of the atmosphere, so that moisture is transferred from the surface of the slab as vapor to the atmosphere. Initially, this evaporation causes cooling of the slab at the surface. Subsequently, the temperature within the slab also decreases due to heat conduction. After the temperature decreases to a value of about 98C, it begins to increase due to heat convection from the surfaces. Simultaneously, the slab gains heat from the ambient atmosphere and loses heat through latent heat of evaporation. According to our mathematical analysis, the slab should reach an equilibrium temperature at T 258C after 30 h. The moisture content evolution is shown in Fig. 5. As expected, the moisture content of the slab decreases with increases in time, until it reaches an equilibrium value of 0.04 kg/kg after 30 h. The moisture content at the surfaces is lower than in the interior. Comparison of Figs. 3 and 5 indicates that the temperature has some eects on moisture migration during drying. Generally, the coupling eect between the temperature and moisture content becomes signi®cant as the value D=L approaches unity, while it will diminish as n l approaches zero. In this study, according to the data given by Liu et al., they are D=L11=12 and n l11=20:
6. Conclusion This study proposes a new analytical approach that consists of applying the Laplace transform technique and a transformation function to solve the problem of coupled temperature and moisture transport. The results, shown to be the same as published analytical solutions obtained using a decoupled technique, compare very well against published analytical solution for a wood slab con®guration, and can serve to evaluate the accuracy of approximate or numerical solutions. Therefore, the method is recommended for analytically solving problems involving coupled temperature and moisture transport in porous materials.
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