Multiple solutions for quasilinear Schrödinger equations involving critical exponent

Multiple solutions for quasilinear Schrödinger equations involving critical exponent

Applied Mathematics and Computation 216 (2010) 849–856 Contents lists available at ScienceDirect Applied Mathematics and Computation journal homepag...

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Applied Mathematics and Computation 216 (2010) 849–856

Contents lists available at ScienceDirect

Applied Mathematics and Computation journal homepage: www.elsevier.com/locate/amc

Multiple solutions for quasilinear Schrödinger equations involving critical exponent q Wang Youjun a,*, Zhang Yimin b, Shen Yaotian b a b

Department of Mathematical Sciences, Tsinghua University, Beijing 100084, PR China Department of Mathematics, South China University of Technology, Guangzhou 510640, PR China

a r t i c l e

i n f o

a b s t r a c t By using Lions’ second concentration–compactness principle and concentration–compactness principle at infinity to prove that the (PS) condition holds locally and by minimax methods and the Krasnoselski genus theory, we establish the multiplicity of solutions for a class of quasilinear Schrödinger equations arising from physics. Crown Copyright Ó 2010 Published by Elsevier Inc. All rights reserved.

Keywords: Quasilinear Schrödinger equations Critical exponents Concentration–compactness

1. Introduction This paper is concerned with the following quasilinear elliptic equations

Du þ VðxÞu  ½Dðu2 Þu ¼ hðuÞ;

x 2 RN :

ð1:1Þ

Such equations arise in various branches of mathematical physics and they have been the subject of extensive study in recent years. Part of the interest is due to the fact that solutions of (1.1) are related to the existence of standing wave solutions for quasilinear Schrödinger equations of the form

@ t z ¼ Dz þ VðxÞz  lðjzj2 Þz  kDgðjzj2 Þg 0 ðjzj2 Þz;

x 2 RN ;

ð1:2Þ

where V is a given potential, k is a real constant, l and g are real functions. Quasilinear equations of the form (1.2) appear more naturally in mathematical physics and have been derived as models of several physical phenomena, such as superfluid film equations in plasma physics and the fluid mechanics in condensed matter theory. The related semilinear equations for k = 0 have been extensively studied (see e.g. [1,2,5,12–15], as well as their references). For k – 0, Poppenberg et al. [11] studied the existence of a positive ground state solution for the quasilinear Schrödinger equation in u00 þ VðxÞu  ðu2 Þ00 u ¼ hjujp1 u in R. In [8], by a change of variables the quasilinear problem was transformed to a semilinear one and an Orlicz space framework was used as the working space, and they were able to prove the existence of positive solutions of (1.2) by the Mountain-Pass theorem. The same method of changing of variables was used in [10], but the usual Sobolev space Hl ðRN Þ framework was used as the working space and they studied a different class of nonlinearity. In [9], the existence of both one sign and nodal ground state type solutions were established by the Nehari method. The main purpose of the present paper is to show the existence of multiple solutions for quasilinear Schrödinger equations of the form

Du  ½Dðu2 Þu ¼ akðxÞjujp2 u þ bu2ð2 

where N P 3; 2 < p < 4; 2 ¼

2N N2



;

x 2 RN ;

r

N

Þ1

ð1:3Þ 



and kðxÞ 2 L ðR Þ with r ¼ 2ð2 Þ=ð2ð2 Þ  pÞ  a and b are real parameters.

q

Rearch supported by the National Natural Science Foundation of China (No. 10771074). * Corresponding author. E-mail addresses: [email protected] (W. Youjun), [email protected] (Z. Yimin).

0096-3003/$ - see front matter Crown Copyright Ó 2010 Published by Elsevier Inc. All rights reserved. doi:10.1016/j.amc.2010.01.091

850

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

Note that 2ð2 Þ behaves like a critical exponent for the above equations [8, Remark 3.13]. For the subcritical case, the existence of solutions for Problem (1.1) was studied in [7–10] and it was left open for the critical exponent case [8, Remark 3.13].  To the best of our knowledge, the existence of nontrivial radial solutions for (1.1) with hðuÞ ¼ lu2ð2 Þ1 was firstly studied by Moameni [17], where the same Orlicz space as [8] was used. Our main result is the following: Theorem 1.1. Suppose that X :¼ fx 2 RN : kðxÞ > 0g is an open subset of RN and 0 < jXj < 1. Then (i) 8b > 0, there exists a1 > 0 such that if 0 < a < a1 , Problem (1.1) has a sequence of solutions. (ii) 8a > 0, there exists b1 > 0 such that if 0 < b < b1 , Problem (1.1) has a sequence of solutions. Notation. In this paper, we make use of the following notation: n o R 1=2  .  D1;2 ðRN Þ :¼ u 2 L2 ðRN Þ : ru 2 L2 ðRN Þ endowed with the norm kuk ¼ RN jruj2 dx  1=r R .  For 1 6 r < 1; Lr ðRN Þ denotes the usual Lebesgue space with norms kukr ¼ RN jujr dx  c; c1 ; c2 denote positive (possibly different) constants. 2. Preliminaries It should be pointed out that the natural functional/associated with (1.3) given by

IðuÞ ¼

1 2

Z RN

ð1 þ 2u2 Þjruj2 dx 

a p

Z

kðxÞjujp dx 

RN

b 2ð2 Þ

Z



u2ð2 Þ dx RN

is not well defined in general, for instance, in D1;2 ðRN Þ. To overcome this difficulty, we employ an argument developed by Colin and Jeanjean [10]. We make the changing of variables v ¼ f 1 ðuÞ, where f is defined by:

1 f 0 ðtÞ ¼ pffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi ; and f ð0Þ ¼ 0 1 þ 2f 2 ðtÞ on ½0; 1Þ and by f ðtÞ ¼ f ðtÞ on ð1; 0. The following results is due to Colin and Jeanjean [10]. Lemma 2.1. f satisfies the following properties: ðf0 Þ f is uniquely defined, C 1 and invertible. ðf1 Þ jf 0 ðtÞ 6 1j for t 2 R. ! 1 as t ! 1. ðf2 Þ f ðtÞ t ðf3 Þ fpðtÞffit ! 21=4 as t ! 1. 0 ðf4 Þ 12 f ðtÞ 6 tf ðtÞ 6 f ðtÞ for all t P 0. So, after the change of variables, we can write IðuÞ as

Jðv Þ ¼

1 2

Z RN

jrv j2 dx 

Z

a p

RN

kðxÞjf ðv Þjp dx 

b 2ð2 Þ

Z RN



f 2ð2 Þ ðv Þ dx:

ð2:1Þ

Then, Jðv Þ is well defined on D1;2 ðRN Þ and J 2 C 1 . In fact, we have the following results. Lemma 2.2 R

(i) The functional Fðv Þ :¼

RN

kðxÞjf ðv Þjp dx is well defined and weakly continuous on D1;2 ðRN Þ. Moreover, FðuÞ is continuously

differentiable, its derivative F0 ðv Þ : D1;2 ðRN Þ ! ðD1;2 ðRN ÞÞ is given by

hF0 ðv Þ; hi ¼ p

Z RN

kðxÞjf ðv Þjp2 f ðv Þf 0 ðv Þh dx:

(ii) The functional Gðv Þ :¼ G ðv Þ :¼ D 0

1;2

R

1;2

N

ðR Þ ! ðD

hG0 ðv Þ; hi ¼ 2ð2 Þ

Z RN

f 2ð2

ð2:2Þ



RN

f 2ð2 Þ ðv Þ dx is well defined. Moreover, Gðv Þ is continuously differentiable, its derivative N



ðR ÞÞ is given by 

Þ1

ðv Þf 0 ðv Þh dx:

ð2:3Þ

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

851

Proof. By ðf2 Þ and ðf3 Þ, it is clear that F and G are well defined on D1;2 ðRN Þ. In order to prove F; G 2 C 1 , it suffices to show both F and G have continuous Gateaux derivative on D1;2 ðRN Þ. We consider only F since the proof for G is simpler. Our argument is similar to that [18, Lemma 3.10]. Let u; h 2 D1;2 ðRN Þ. Given x 2 RN and 0 < jtj < 1, by the mean value theorem, there exists k 2 ð0; 1Þ such that

  jf ðv þ thÞjp  jf ðv Þjp  p2 p2 p ¼ pjf ðv þ tkhÞjp1 jf 0 ðv þ tkhÞjjhj 6 cjv þ tkhj 2 jhj 6 cðjv j 2 jhj þ jhj2 Þ: jtj

By Hölder inequality, we have

Z

RN

kðxÞðjv j

p2 2

p

p2 2

jhj þ jhj2 Þ dx 6 kkðxÞkr khk2  ðkv k

p2

þ khk 2 Þ:

It follows from the Lebesgue Dominated Convergence theorem that F is Gateaux differentiable and

hF0 ðv Þ; hi ¼ p

Z

RN

kðxÞjf ðv Þjp2 f ðv Þf 0 ðv Þh dx:

Now, we proof continuity of Gateaux derivative. Assume that v n ! v , in D1;2 ðRN Þ, then f 2 ðv n Þ ! f 2 ðv Þ in D1;2 ðRN Þ. By the   continuity of the embedding D1;2 ðRN Þ,!L2 ðRN Þ; f 2 ðv n Þ ! f 2 ðv Þ in L2 ðRN Þ. Let us define Hðv Þ :¼ pkðxÞjf ðv Þjp2 f ðv Þf 0 ðv Þ, then  2 2 N N 0 Hðv Þ 2 ðL ðR Þ; CðL ðR ÞÞ Þ [16, p. 30]. It follows that Hðv n Þ ! Hðv Þ in ðL2 ðRN ÞÞ0 . Using Hölder and Sobolev inequalities, we get 

2 hF0 ðv n Þ  F0 ðv Þ; hi 6 kHðv n Þ  Hðv Þkð2 Þ0 khk 6 ckHðv n Þ  Hðv Þkð2 Þ0 khk

Hence kF0 ðv n Þ  F0 ðv Þk ! 0 and F 2 C 1 . As in [10], we observe that if f is a nontrivial critical point of J, then

Dv ¼ gðx; v Þ;

v is a nontrivial solution of problem

x 2 RN ;

ð2:4Þ

where

gðx; sÞ ¼ f 0 ðsÞðakðxÞÞjf ðsÞjp2 f ðsÞ þ bf 2ð2 Therefore, setting u ¼ f ðv Þ and since ðf problem



Þ1

ðsÞÞ:

1 0

Þ ðtÞ ¼ ½f 0 ðf 1 ðtÞÞ1 ¼

Du  ½Dðu2 Þu ¼ akðxÞjujp2 u þ bu2ð2



Þ1

:

pffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 þ 2t2 , we conclude that u is a nontrivial solution of the



Theorem 2.3. Suppose that X :¼ fx 2 RN : kðxÞ > 0g is an open subset of RN and 0 < jXj < þ1. Then, (i) 8b > 0, there exists a1 > 0 such that if 0 < a < a1 , Problem (2.4) has a sequence of solutions fv m g with Jðv m Þ < 0 and Jðv m Þ ! 0 as m ! þ1. (ii) 8a > 0, there exists b1 > 0 such that if 0 < b < b1 , Problem (2.4) has a sequence of solutions fv m g with Jðv m Þ < 0 and Jðv m Þ ! 0 as m ! þ1. We recall the second concentration–compactness principle of Lions [12]. 

Proposition 2.4. Let fum g be a weakly convergent sequence to u in D1;2 ðRN Þ such that jum j2 * m and jrum j2 * l in the sense of measures. Then, for some at most countable index set J,  P (i) m ¼ juj2 þ j2J mj dxj ; mj > 0, P 2 (ii) l P jruj þ j2J lj dxj ; lj > 0, 2=2 6 lj , (iii) Smj

where S is the best Sobolev constant, i.e., S ¼ inf constants.

nR

RN

o  jruj2 dx : kuk22 ¼ 1 ; xj 2 RN ; dxj are Dirac measures at xj and

The following result can be found in [4,17]. Proposition 2.5. Let fum g be a weakly convergent sequence to u in D1;2 ðRN Þ and define R



l1 ¼ limR!1 lim sup jxj>R jum j2 dx, m!1 R (ii) l1 ¼ limR!1 lim sup jxj>R jrum j2 dx. (i)

m!1

The quantities (iii) lim sup m!1 2=2 6 1

(iv) Sm

R

m1 and l1 exist and satisfy

RN





jum j2 dx ¼ juj22 þ kmk þ m1 ; lim sup

l1 .

m!1

RN R

jrum j2 dx ¼ jruj22 þ klk þ l1 .

lj mj are

852

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

We say that fv n g is a Palais–Smale sequence for the functional J at level c 2 R ((PS)c sequence in short), if Jðv n Þ ! c and J 0 ðv n Þ ! 0 as n ! 1. Lemma 2.6. Any ðPSÞc sequence for J is bounded. Proof. Let fv n g be a ðPSÞc sequence. Then, for n large,

Jðv n Þ ¼

1 2

Z

jrv n j2 dx 

RN

a p

Z RN

kðxÞjf ðv n Þjp dx 

b 2ð2 Þ

Z RN



f 2ð2 Þ ðv n Þ dx ¼ c þ oð1Þ;

ð2:5Þ

and for any x 2 D1;2 ðRN Þ,

hJ 0 ðv n Þ; xi ¼ Choose x ¼ xn ¼

Z RN

rv n rx dx  a

Z RN

kðxÞjf ðv n Þjp2 f ðv n Þf 0 ðv n Þx dx  b

Z



f 2ð2

RN

Þ1

ðv n Þf 0 ðv n Þx dx ¼ oðkv n kÞ:

ð2:6Þ

pffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 þ 2f 2 ðv n Þf ðv n Þ, we have xn 2 D1;2 ðRN Þ. From ðf4 Þ and since

 jrxn j ¼ 1 þ

2f 2 ðv n Þ jrv n j; 1 þ 2f 2 ðv n Þ

we deduce that kxn k 6 ckv n k. By (2.6),

hJ 0 ðv n Þ; xn i ¼

Z RN

 1þ

Z Z  2f 2 ðv n Þ jrv n j2 dx  a kðxÞjf ðv n Þjp dx  b f 2ð2 Þ ðv n Þ dx ¼ oðkv n kÞ 2 1 þ 2f ðv n Þ RN RN

Then, by Hölder and Sobolev inequalities, since

Z RN

jrf 2 ðv n Þj2 dx ¼ 4

Z RN

f 2 ðv n Þ jrv n j2 dx 6 2 1 þ 2f 2 ðv n Þ

Z RN

jrv n j2 dx;

we have,

 Z Z

1 1 1 2f 2 ðv n Þ a 2 0 j ð v Þ; x i ¼ r v j dx  kðxÞjf ðv n Þjp dx  hJ 1 þ n n n 2ð2 Þ 2ð2 Þ 1 þ 2f 2 ðv n Þ r RN RN 2 Z 1r Z p 2ð2 Þ  a jrv n j2 dx  jkðxÞjr dx jf ðv n Þj2ð2 Þ dx N N r R R Z 1r Z 4p a 1 jrv n j2  jkðxÞjr dx jrf 2 ðv n Þj2 dx P kv n k2  ckv n kp=2 ; N N N r R R

c þ oðkv n kÞ ¼ Jðv n Þ  P P

1 N 1 N

Z RN

Z RN

we immediately deduce that fv n g is bounded since p < 4.

h

Proposition 2.7 (i) 8b > 0, there exists a1 > 0 such that if 0 < a < a1 and c < 0, then J satisfies (PS)c. (ii) 8a > 0, there exists b1 > 0 such that if 0 < b < b1 and c < 0, then J satisfies (PS)c

Proof. Let fv n g be a (PS)C sequence, by Lemma 2.6, fv n g is bounded in D1;2 ðRN Þ then ff 2 ðv n Þg is also bounded in D1;2 ðRN Þ. We can assume, going if necessary to a subsequence, that v n * v in D1;2 ðRN Þ; v n ! v a.e. in RN , since f 2 C 1 , then f 2 ðv n Þ ! f 2 ðv n Þ a.e. in RN and then f 2 ðv n Þ * f 2 ðv n Þ in D1;2 ðRN Þ. Thus, there exist measures l and m such that 

N jrf 2 ðv n Þj2 * l; f 2ð2 Þ ðv n Þ * m. Let xk be a singular point of the measures l and m. We define a function / 2 C 1 0 ðR Þ such pffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi N N 2 ~ ~ that /ðxÞ ¼ 1 in Bðxj ; Þ; /ðxÞ ¼ 0 in R n Bðxj ; 2Þ and jr/j 6 2= in R . Let xn ¼ 1 þ 2f ðv n Þf ðv n Þ/, then fxn g is bounded

~ n i ¼ 0, that is, in D1;2 ðRN Þ. We have limn!1 hJ 0 ðv n Þ; x

lim

n!1

Z RN

Z qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 þ 2f 2 ðv n Þf ðv n Þrv n r/dx ¼ lim n!1

 Z Z  2f 2 ðv n Þ 1þ kðxÞjf ðv n Þjp /dx  b f 2ð2 Þ ðv n Þ/dx /jrv n j2 dx  a 2 1 þ 2f ðv n Þ RN RN RN

853

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

On the other hand, by ðf4 Þ, we have,

Z  lim 

n!1

RN

 Z qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi  1 þ 2f 2 ðv n Þf ðv n Þrv n r/ dx 6 limn!1 c jv n rv n r/j dx RN "Z Z 1=2

6 c lim

n!1

6c

Z Bðxj ;2Þ

RN

jrv n j2 dx 

RN

1=2 # Z c jv n r/j2 dx

RN

1=2 jv r/j2 dx

!1=2

jv j2 dx

! 0; as

 ! 0:

Then, by the weak continuity of Fðv Þ

0 ¼ lim

Z

n!1

RN

 1þ

Z 1 P lim n!1 2 RN

Z Z 2f 2 ðv n Þ 2 p 2ð2 Þ /j r v j dx  a kðxÞjf ð v Þj / dx b f ð v Þ/ dx n n n 1 þ 2f 2 ðv n Þ RN RN Z Z lj  /jrf 2 ðv n Þj2 dx  a kðxÞjf ðv n Þjp / dx  b f 2ð2 Þ ðv n Þ/ dx ¼  bmj ; as N N 2 R R

 ! 0;

we get 2bmj P lj . By Proposition 2.4 (iii), we have that either

ðIÞ

mj ¼ 0; or ðIIÞ mj P ð21 b1 SÞN=2 :

To obtain the possible concentration of mass at infinity, similarly, we define a cut off function /R 2 /R ðxÞ ¼ 0 on jxj < R and /R ðxÞ ¼ 1 on jxj > R þ 1. Since f/R xn g is bounded in in D1;2 ðRN Þ, we have

ð2:7Þ N C1 0 ðR Þ

such that

Z

qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 þ 2f 2 ðv n Þf ðv n Þrv n r/R dx RN

Z  Z Z 2f 2 ðv n Þ 2 p 2ð2 Þ ¼ lim 1þ j r v j dx  a kðxÞjf ð v Þj / dx  b f ð v Þ/ dx : / n n n R R n!1 1 þ 2f 2 ðv n Þ R RN RN RN

lim

n!1

Notice that

Z  lim lim 

R!1 n!1

RN

 qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi  1 þ 2f 2 ðv n Þf ðv n Þrv n r/R dx ¼ 0

and using the weak continuity of F, we have,

Z  lim 

n!1

jxj>R

  kðxÞjf ðv nÞjp /R dx ! 0; as R ! 1:

Therefore,

0 ¼ lim

n!1

Z RN

 1þ

Z 1 P lim n!1 2 RN

Z Z 2f 2 ðv n Þ 2 p 2ð2 Þ / j r v j dx  a kðxÞjf ð v Þj / dx  b f ð v Þ/ dx n n n R R 1 þ 2f 2 ðv n Þ R RN RN Z Z  l /R jrf 2 ðv n Þj2 dx  a kðxÞjf ðv n Þjp /R dx  b f 2ð2 Þ ðv n Þ/R dx ¼ 1  bm1 ; as R ! 1; 2 RN RN

Combining with (iv) of Proposition 2.5 we have that either

ðIIIÞ

m1 ¼ 0; or ðIVÞ m1 P ð21 b1 SÞN=2 :

ð2:8Þ

Next, we claim that (II) and (IV) cannot occur if a and b are chosen properly. Indeed, from the weak lower semicontinuity of the norm and the weak continuity of F,

 0 > c ¼ lim Jðv n Þ 



qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 0 2 ðv Þf ðv Þ ð v Þ; 1 þ 2f J n n n n!1 2ð2 Þ  Z

Z 2 1 1 2f ðv n Þ a ¼ lim jrv n j2 dx  kðxÞjf ðv n Þjp dx  1þ  2 n!1 2ð2 Þ 1 þ 2f ðv n Þ pr RN RN 2  Z Z 1 a 1 a p=2 p=2 P lim jrv n j2 dx  kkðxÞkr kf 2 ðv n Þk2 P jrv j2 dx  kkðxÞkr kf 2 ðv Þk2 n!1 N RN N RN pr pr Z 1 a S a p=2 p=2 kf 2 ðv Þk22  kkðxÞkr kf 2 ðv Þk2 ; P jrf 2 ðv Þj2 dx  kkðxÞkr kf 2 ðv Þk2 P 2N RN 2N pr pr

this yields,

kf 2 ðv n Þk2 6 ca2=ð4pÞ :

854

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

Therefore,

 0 > c ¼ lim Jðv n Þ 



qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 J 0 ðv n Þ; 1 þ 2f 2 ðv n Þf ðv n Þ  n!1 2ð2 Þ Z

 Z 1 1 2f 2 ðv n Þ a 2 p ¼ lim r v j dx  kðxÞjf ð v Þj dx  1þ j n n  n!1 2ð2 Þ 1 þ 2f 2 ðv n Þ pr RN RN 2 Z 1 a 1 1 P lim lim jrv n j2 /R dx  kkðxÞkr kf 2 ðv n Þkp=2 l  cap=ð4pÞ P 2ð2NÞ=2 bð2NÞ=2 SN=2  cap=ð4pÞ : P 2 N R!1 n!1 RN 2N 1 2N pr

However, if a > 0 is given, we can choose b1 so small such that for every 0 < b < b1 , the last term on the right-hand side above is greater than 0, which is a contradiction. Similarly, if b > 0 is given, we can take a1 so small such that for every 0 < a < a1 , the last term on the right-hand side above is greater than 0. Similarly, we can prove that (II) cannot occur for each j. Thus,

lim

Z

n!1

and

lim



RN

Z

n!1

RN

f 2ð2 Þ ðv n Þ dx ¼

Z

n!1

RN



RN

f 2ð2 Þ ðv Þ dx;

ð2:9Þ

  kðxÞ jf ðv n Þjp  jf ðv Þjp dx 6 lim kkðxÞkr kjf ðv n Þjp  jf ðv Þjp k2ð2 Þ ¼ 0: n!1

Since JðmÞ ¼ c, then,

lim

Z

jrv n j2 dx ¼

Z RN

p

jrv j2 dx:

ð2:10Þ

By Brézis–Lieb Lemma, we get,

lim

n!1

Z

RN

jrðv n  v Þj2 dx ¼ 0:

ð2:11Þ

This completes the proof of Proposition 2.7.

h

3. Proof of theorems In this section, we use minimax procedure to prove Theorem 2.3. Let X be a Banach space, define the set

R ¼ fA  X n f0g : A is closed in X and symmetric with respect to the origing: For A 2 R, define

cðAÞ :¼ inffm 2 N : 9u 2 CðA; Rm n f0gÞ; uðxÞ ¼ uðxÞg; if there is no mapping u as above for any m 2 N, then cðAÞ :¼ þ1. The properties of the genus can be found in [3,13]. Proposition 3.1. Let A; B 2 X, Then, (1) (2) (3) (4)

If there exists an odd map f 2 CðA; BÞ, then cðAÞ 6 cðBÞ. If A  B, then cðAÞ 6 cðBÞ. c(A[B) 6c(A)+c(B). If A is compact, there exists a symmetric neighborhood N of A, such that cðNÞ ¼ cðAÞ.

Let J be the functional defined as in (2.1), then

Jðv Þ ¼

1 2

Z RN

jrv j2 dx 

a p

Z RN

kðxÞjf ðv Þjp dx 

b 2ð2 Þ

Z RN



f 2ð2 Þ ðv Þ dx

Z 1=r Z p=2ð2 Þ Z  1 a b 2 r 2ð2 Þ jkðxÞj dx f ðv Þ dx  f 2ð2 Þ ðv Þ dx P kv k   2 2ð2 Þ RN p RN RN   1 1 P kv k2  ac1 kjf ðv Þjkp=2  bc2 kf ðv Þk2 P kv k2  ac1 kv kp=2  bc2 kv k2 : 2 2 

We define the function Q ðtÞ :¼ 1=2t2  ac1 tp=2  bc2 t 2 . Then, it is easy to see that, given b > 0, there exists a2 > 0 so small that for every 0 < a < a2 , there exists 0 < T 0 < T 1 such that Q ðtÞ < 0 for 0 < t < T 0 ; Q ðtÞ > 0 for T 0 < t < T 1 ; Q ðtÞ < 0 for t > T 1 . Similarly, given a > 0, we can choose b2 > 0 with the property that T 0 ; T 1 as above exist for each 0 < b < b2 . Clearly, Q ðT 0 Þ ¼ Q ðT 1 Þ ¼ 0. Using the same idea as in [6], we consider the truncated functional

eJðv Þ ¼ 1 2

Z RN

jrv j2 dx 

a p

Z RN

kðxÞjf ðv Þjp dx 

b wðv Þ 2ð2 Þ

Z RN



f 2ð2 Þ ðv Þ dx;

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

855

where wðuÞ ¼ sðkukÞ and s : Rþ ! ½0; 1 is a nonincreasing C 1 function such that sðtÞ ¼ 1 if t 6 T 0 and sðtÞ ¼ 0 if t P T 1 . Thus,

e ðkv kÞ; eJðv Þ P Q

ð3:1Þ

e ðtÞ :¼ 1=2t2  ac1 t p=2  bc2 t2 wðtÞ. It is clear that eJðv Þ 2 C 1 and is bounded from below. where Q Moreover, we can follow from Proposition 2.7 and (3.1) that: Proposition 3.2 (i) If eJðv Þ < 0, then kv k 6 T 0 and eJðv Þ ¼ Jðv Þ; (ii) 8b > 0, there exists a3 > 0 such that if 0 < a < a3 and c < 0, then eJ satisfies (PS)c. (iii) 8a > 0, there exists b3 > 0 such that if 0 < b < b3 and c < 0, then eJ satisfies (PS)c.

Lemma 3.3. Denote K c :¼ fv 2 D1;2 ðRN Þ; eJ 0 ðv Þ ¼ 0; eJðv Þ ¼ cg. Then for any m 2 N, there is 1 Proof. Denote by D1;2 0 ðXÞ the closure of C 0 ðXÞ with respect to the norm kuk ¼

R X

em < 0 such that cðeJ em Þ P m.

1=2 jruj2 dx . Extending functions in D1;2 0 ð XÞ

1;2 by 0 outside X we can assume that D1;2 ðRN Þ. Let X m be a m-dimensional subspace of D1;2 0 ðXÞ  D 0 ðXÞ. For any v 2 X m ; v –0 write v ¼ r m w with w 2 X m and kwk ¼ 1. From the assumptions of kðxÞ, it is easy to see for every w 2 X m with kwk ¼ 1 that there exist dm > 0 such that

Z

kðxÞjwjp=2 dx 6 dm :

X

Thus for 0 < rm < T 0 , since all the norms are equivalent and 0 < jXj < þ1, by ðf4 Þ we have,

Z Z Z  a b eJðv Þ ¼ Jðv Þ ¼ 1 jrv j2 dx  kðxÞjf ðv Þjp dx  f 2ð2 Þ ðv Þ dx  2 X 2ð2 Þ X p X Z Z Z  1 a b 6 jrv j2 dx  kðxÞðcjv jp=2 þ cÞ dx  ðv 2 þ cÞ dx  2 X 2ð2 Þ X p X Z Z Z p  1 ac bc 1 2 6 jrv j2 dx  kðxÞjv j2 dx  v 2 dx  c 6 r2m  acdm rp=2  m  bcr m  c :¼ em : 2 X p X 2ð2 Þ X 2

Therefore, we can choose r m 2 ð0; T 0 Þ so small that eJðv Þ < em < 0. Let Srm ¼ fu 2 D1;2 ðRN Þ; kv k ¼ r m g. Then Srm \ X m  eJ em . By Proposition 3.1 (2),cðeJ em Þ P cðSrm \ X m Þ P m. P Therefore, if we denote Cm ¼ fA 2 ; cðAÞ P mg and let

cm :¼ inf A2Cm supv 2AeJðv Þ;

ð3:2Þ

1 < cm 6 em < 0;

ð3:3Þ

then

m 2 N;

because eJ em 2 Cm and eJ is bounded from below. h Proposition 3.4. Let a; b be as in Proposition 3.2 (ii) or (iii). Then all cm given by (3.2) are critical values of eJ and cm ! 0 as m ! 1. Proof. It is clear that cm 6 cmþ1 , and by (3.3), cm < 0. Hence cm ! c 6 0. Moreover, since (PS)c is satisfied, it follows from a standard argument (e.g. [13]) that all cm are critical values of eJ. Now, we claim that c ¼ 0. If c < 0, because K c is compact and P K c 2 , it follows from that cðK c Þ ¼ mo < þ1 and there exists d > 0 such that cðK c Þ ¼ cðN d ðK c ÞÞ ¼ m0 . By the deformation lemma there exist  > 0ðc þ  < 0Þ and an odd homeomorphism g such that

gðeJ cþ n Nd ðK c ÞÞ  eJ c :

ð3:4Þ

Since cm is increasing and converges to c, there exists m 2 N such that cm > c   and C mþm0 6 c. There exists A 2 Cmþm0 such e < c þ . By Proposition 3.1, we have, that supu2A GðuÞ

cðA n Nd ðK c ÞÞ P cðAÞ  cðNd ðK c ÞÞ P m; cðgðA n Nd ðK c ÞÞÞ P m:

ð3:5Þ

Therefore,

gðA n Nd ðK c ÞÞ 2 Cm : Consequently,

sup u2gðAnNd ðK c ÞÞ

e GðuÞ P cm > c  :

ð3:6Þ

856

W. Youjun et al. / Applied Mathematics and Computation 216 (2010) 849–856

On the other hand, by (3.4) and (3.5),

gðA n Nd ðK c ÞÞ  gðeJ cþ n Nd ðK c ÞÞ  eJ c ; which contradicts (3.6). Hence cn ! 0.

ð3:7Þ

h

Proof of the Theorem 2.3. By Proposition 3.2 (i), eJðv Þ ¼ Jðv Þ if eJ < 0. This and Proposition 3.4 give the result. Proof of the Theorem 1.1. This follows from Theorem 2.3, since um ¼ f ðv m Þ – un ¼ f ðv n Þ if

vm – vn.

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