SHORT COMMUNICATWNS THE STABILITY OF LINEAR EQUATIONS ON A COMPACT SET* R.
DENCREV Dubna
‘neceived
14
November
1966)
The equation Ax = y
is
considered
subject
to the condition I( Br 11s .M
where A and B are selfconjugate commutative operators space H. The stability of the problem is investigated Let
SW(Y) ={ssH:
in the Hilbert for varying y.
IIBrIl SMM)
be a compact set in H. Let A be a continuous and A-’ a singlevalued (possibly unbounded) operator. Let % = B!Jk be the image of the set 9R . We denote by R( R) the contraction of the operator A-l on w It is known [II, that th e operator R(R ) is continuous. In this paper a method is proposed for calculating the modulus of continuity of the operator R( 951. (This method is to some extent a generalization of a method used by 1.1. Lavrent’ev [21 . ) We denote the modulus of continuity by O(E, M). It is easy to see that 0 (6 M) =
max{li z
that is, O(E. M) is the diameter in Hilbert space.
l
Zh.
vychisl.
Mat.
mat.
Fiz.
‘I,
II : IIAZ II 5
E, IIBX II d M},
of the intersection
6,
1367
-
1376,
of two ellipsoids
1967.
(1)
202
R.
Dencheu
We apply the method of Lagrange multipliers.
We form the functional
(D(z, h) = 11z II*+ hi (e2 - II Ax II") + hz(M2- II Bx 11’) It can be shown (as in the case of convex functions [3, 41), that if 2 is the point at which the maximum is attained in (11, il and ^hz exist satisfying the relations n x - “hiA”;- h&L; = o,, (2) !IBz”Ilshf,
IIAill S e,
(3)
~i(e-_AA^zII)+~a(M-~i~211)=o, L, iiB 0
(2)
We will - (4).
determine II ^xII for any vector ;, satisfying We will determine the maximum of the values
We first
(4)
the relations of 112 II obtained.
assume that both hl and A2 are non-zero.
Then (1 A”x11 = E, and I( ark (( = M. Multiplying
(2) by 2, we obtain (5)
11; 112 = Li,ez+ Ld42. Since A and B commute a spectral such that m A =
family
(6)
operators
E exists
m
f(6)&,
B=
‘~(0)dEe.
(‘31
s[1--.;2(e)-_~2(e)]dEe~=o.
(7)
s
-m
Substituting
of projective
in (2),
s --m
we obtain
OD
-m Let us consider
the expression
P(6) = I-
i#(6)
- ,\P$J~(~). We denote
by
N the set of its zeros; N is not empty, since otherwise it would follow from (‘7) that 2 = 0. Let us assume that N consists of a finite number of points. Let N contain
at least
two points
f2(elbw2)
61 and 62 such that
- f~(e2)cpvl)
z 0.
Then from the equations
2 - i,jyei)
- l;z(p2(&) = 0:
I . &;?(e2) - &(~z(f3~)= 0
we determine
A hl and ^hg, substitute Il,^ll =
them in (5)
[cp2(62)- cpz(e,)i e* + [fz(e,)-
f2(e,p+wz)--
fv32hw3i)
and obtain td(e2)i M2
The
We
denote and 02. If
for
stability
by ~I(E,
any
of
I)
the
two points
linear
equations
on
maximum of this
a;,
8j
E.
a compact
expression
203
set
with
respect
to aI
W
fz(0i)cp2(a,)
-f’(Oj)@(ei)
=
0.
we have
Ii = 2
- Eell _&
(‘y
= Zik,
i9
B&E ‘V
-2 = zf'(ek) bAl12 = &‘, l!Axl!
ilBsit
-2
~~2(~A)~i~k~~2
=
M2.
b9)
Therefore, II2 II =
11 2k I) and ok satisfy
where
We denote
II Xh 112),
iw
(9).
:U) the
by 02(s,
1(X
maximum of
(10)
subject
to the
condition
(9). Finally,
let
N consist
of only
From this
we obtain
11f(e,)X
that
u -=
81
one Point
81.
'Then
h (Ee, - E4,._0)2,
;= I!.& 11-
the
E,
!I A
5FI*,isfies
11 =
the
cp(el)
ii (p(e:)X
II = M.
relation
M
l-1f(&)
(11)
= e
and M
E ;I;Ij=_=-.
We
for
M) the
IfW
hew
I
maximum of
(12)
1
subject
(12) to the
condition
denote
by 03 (e,
We now
consider the case ., where ,I the,* numbers XI, k~ equals 0, one of M. Let the equation x2 = 0. Then 11A2 11 = e, 11Bz II
(11). zero,
example,
I .- hlf2(ei) = c have one root
81.
Then
11;= l/f”(01), II&~.
Hence
from
(3)
we obtain
(23)
for
81 the
if (w
I
condition
(141
204
R.
If
equation
one of
(13)
of
them will
(141
subject
has more than satisfy to
The modulus
of
the
numbers
01.
Let
us consider
of
one root
(14)
condition
it
and (15).
is
easy
Let o~(E,
to
see
that
M) denote
at least
the
maximum
(15).
continuity 02,
Dencheu
of
the
operator
R( 3)
equals
the
greatest
03 and 04,
an example.
Let
8
H = L2(0, I),
s
Bx=ig,
x(t) dt,
Ax =
0
that
is,
the
equation
*
c
s(t)dt
=
y(t)
n
is
considered,
In this
subject
case
to
equation
the
(31
condition
is
of
1
d2;
ds
: Fourier
form
s s&)dz+ iz-
4t)-d, By the
the I
==o.
dt2
0
transformation
* x(t) =
“,
1
_I..- 1 ‘)/Pn)_m
ectei(e)dtl
we obtain
ti2e4 - 82 + L) y (e) = 0. Let iI,
chg # 0.
AI = 0 exist
such
At least that
it=----, and
!I21 = Equating
to
zero
two roots
814 # 8~~.
81,
82 of
the
Then
ei2e22 82 + e22
L-L-
82 + e22
ei2e2w + ~2 ei2 + e22
Jf /at?, and af / a&, we f hd
=
f(e,, 0,).
equation
Age4 - O2 +
The
stability
of
linear
equations
mxf(thCbj=
on
a compact
205
set
y(eM)
01%
112 1) = ~0. From this If & = 0, from (14) and (15) we obtain to the condition 04 G .H*/e* we have rnaaxllZll = )((s, W . Therefore,
for
the
example
subject
considered e)(s, Mj = l(e, M).
by
Translated
J.
Berry
REFEREWCSS TIKHONOV, A.N. On the stability IVauk SSSR 39, 5, 195 - 198,
2.
LAVRENT’EV. M.M. Some Incorrect problems of mathematical Akad. Nauk SSSR, Novosibirsk, 1963. Izd-vo
physics.
3.
ROCKAFELLAR. R.T. functions. Duke
for
4.
KHENZ, H.P.
Extension (Math.
J.
of inverse 1944.
DokZ.
1.
problems,
of Fenchel’s duality 33, 1, 86 - 89, 1966.
and CRELLE, V. Non- linear
programming,
theorem
Mir,
Akad.
convex
MOSCOW,
1965.