A note on a classical problem in the mathematical theory of heat conduction

A note on a classical problem in the mathematical theory of heat conduction

Int. J. Engng Sci. Vol. 5, pp. 3948. Pergamon Press 1967. Printed in Great Britain A NOTE ON A CLASSICAL PROBLEM IN THE MATHEMATICAL THEORY OF HEAT ...

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Int. J. Engng Sci. Vol. 5, pp. 3948.

Pergamon Press 1967. Printed in Great Britain

A NOTE ON A CLASSICAL PROBLEM IN THE MATHEMATICAL THEORY OF HEAT CONDUCTION H. NUTTALL Department

of Theoretical Mechanics, University of Bristoi, England Communicated

by R. BERKER

A~ct-Two-dime~ional steady heat flow in a rectangular corners of the region implies an infinite rate of heat transfer. give rise to this condition are never realized in a mat physical estimate of the rate of heat flow may be calculated for more 1. STATEMENT

region with a temperature discontinuity at the The boundary conditions of the problem which situation. A method is given whereby a simple realistic boundary conditions.

OF THE

PROBLEM

WE define the steady state temperature at a point (x, y) of the region as fI(x, 7). The problem basic to the discussion in the sense that more general boundary conditions may be included by superposition, is to determine the temperature distribution and heat ffow in a rectangular region where the boundary conditions are as shown in Fig. 1. y ,0=$

b _-,

0

--

- x b R=O

8=0’

-II

The differential equation to be satisfied is

V20_a20 a20

-=0, for -dX2Cay2

06 Ixj
(1.1)

The boundary conditions are,

(1.2) where 0 is a constant.

H. NUTTALL

40

A formal solution of the problem using Fourier series is ( - 1)”cosh(2s + l)ny/2n. cos(2s + 1)7rx/2a (2s + l)cosh(2s + l)nb/2a For a rigorous demonstration to Carslaw and Jaeger [l].

(1.3)

that this is the solution of the problem the reader is referred

The rate of heat flow into the region across the faces I,v]=b is given by (1.4) where K is the thermal conductivity. When applied to 6’as given by (1.3) we have I6KO m tanh(2s + l)rcb/2a Y=-c (2s+l) 0

(1.5)

The series in (1.5) is clearly divergent, the physical explanation lying in the discontinuity of 0 at the corners of the region. This temperature discontinuity implies infinite temperature gradients at the corners of the region which makes the integral in (1.4) infinite. 2. DISCUSSION

OF SOLUTION

FOR

A SEMI-INFINITE

STRIP

A closer insight into the behaviour of 0 in the corner regions of the finite rectangle is obtained by considering a semi-infinite strip having the same boundary conditions as the finite rectangle except that 0 is zero at infinity. This leads to a closed solution and it is reasonable to suppose that the general form of the temperature distribution at the corners will give a qualitative picture of the behaviour for the case of the finite rectangle.

Y'

-e=o



FIG. 2

A note on a classical problem in the mathematical

.4 conformal

41

transformation z’=sin

transforms

theory of heat conduction

2,

region I, Fig. 2, into region II.

A second transformation z’-1 w=log-=u++u z’+ 1 transforms

the region 1I of Fig. 2 to the region 111. zL.-

1

I I

w=u+iv=log-

z’f I

+iarg-,

z’-

1

z’+ 1

v=tan-’

(2.1)

= tan- ‘20 where

tan 0 = cos x/sinh y.

Hence

If the temperature

at the base of the strip is 0

(2.2)

=-

4KO

‘I2 dx -+cc lt s 0 cosx

(2.3)

Equation (2.2) exhibits the behaviour of 8 and shows clearly the way in which the temperature gradient tends to infinity at the corners of the strip. 3. MODIFIED

It should

be remarked

BOUNDARY

CONDITIONS

in passing that the problem

with boundary

e=e,,

06 Ix\
IYI =h,

e=e,,

o< Jyj
1x1 =a,

c=-e,, is equivalent

to the problem

treated

in section

1 with 0, - e2 =O.

conditions

42

H.NUTTALL

It has been shown that these boundary conditions imply an infinite rate of heat flow. While boundary conditions may exist in a real physical situation which resemble those specified above, the model breaks down at the corners where temperature discontinuities will not exist in a real situation. The mechanical or chemical engineer is more interested in rates of heat transfer than in temperature distribution. Our concern in the remainder of this paper is to establish as simply as possible a means of estimating the rate of heat flow through arectangular section where the boundary conditions resemble the idealized ones stated above but where the discontinuity at the corners is removed.

x

FIG. 3

We consider a rectangular such as

section as in Fig. 3. It is realistic to suppose that the faces

can be maintained at a constant temperature

and that the faces

1x1 =a can be maintained at a constant temperature B=O for OG]yl
in which 0 falls from 0 to 0 as y varies from b to b--E.

A note on a classical problem in the mathematical

theory of heat conduction

43

If this dist~bution of temperature is known, the problem is a Dirichlet problem and 0 and the rate of heat Row may be determined. In general however, 0 will be unknown along the element of surface as specified by (3.1) and the problem would be made unique by specifying some boundary condition relating the surface temperature and its normal derivative to the manner in which heat is being transmitted across the element to the external environment [2]. It is not the purpose of the discussion to seek a rigorous solution for a prescribed set of boundary conditions along the surface (3.1). In practice the true nature of this boundary condition may not be well defined. We shall show that if 8 is small and we assume the temperature 0 to vary linearly from value 0 to Q along the surface element (3.1), it is possible to calculate the rate of heat flow fairly easily and that the value obtained is not unduly sensitive to the size of a within what might be regarded as a practical range of size. 4. SOLUTION

WITH

MODIFIED

BOUNDARY

CONDITIONS

We therefore seek a solution of the differential equations

with boundary conditions,

e=o,

It is clearly seen by the use of Fourier series that such a solution is

+ $ a, cos(2s + l)ny/2b mcosh(2s f l)nx/2b

=9-b++,

From (4.2) and (4.1) 40 * ( - lY cosh(2s + I f(nyf2a) scos(2s + I)(ltx/2a) 0=-T (2s + l)cosh(2s -I-l)(rrb/2a)

b-s
(4.1)

(4.2)

44

H. NUTTALL

The rate of heat flow into the block per unit length is dx which when applied to (4.3) gives nb

tanh(2s + 1): - tanh(2s + 1)~;; 1 --

2b m tanh(2s + 1~(~#~2b)sin(2~+ t)(as/2b) r: (2s + 1)” x.5 0

(4.4)

The numerical valuation of this expression for given ratio b/a requires the summation of the series

Let us call n~/2h=s

and denote the sum of the series by S(X). Since 1 - nnx =flog 2(1 -cosx) cDol cos

= ‘ilog

1 1 -&log 2( 1 - cos x) 2( 1 - cos 2x)

=gog

( > cotZ

2 ’

whence

but s(n/2)=+$-

. . . =0*9159656,

and S(x) = 0.9159656 + +j:,z log(cot.$d~

(4.5)

A note

on a classical

problem

in the mathematical

theory

45

of heat conduction

where (4.6) where B, denotes Bernoulli’s (4.5) and (4.6) give

number.

% siN~;s~~~~Pb =y

(

If we denote

nqi)+ 0.78539821

log cot-

the ratio c/b by A, x =ne/2b =d/2,

+O.l 076607A3

+ 0.0185945A5 + 0~00345~’ + 0.00067925A9 + . . . Since tanh(2s + l)[na/26], tanh(2s + l)[rcb/2a] converge rapidly to unity values of s, the rate of heat flow q as given by (4.4) is easily obtained. The following table shows the values of q obtained From (4.4) the value of q may be expressed as

with

(4.7) increasing

for varying values of ,I and ratio u/b.

q =k(a/b, A)K@ where k(a/b, A) is tabulated

in Table

1.

TABLE 1. VALUES OF k(u/b, A)

a/b

a/b

l/l&

114 14.8887

14.8699

314 14.7365

l/200

16.6538

16.6348

l/500

18.9871

l/l,ooo l/10,000

alb

4

0

14.4666

413 14.0042

13.1046

4/l 11.3572

16.5016

16.2316

15.7694

14.8702

13.1226

18.9682

18.8348

18.5648

18.1024

17.2030

15.4556

20.7523

20.7334

20.6000

20.3300

19.8676

18.9682

17.2208

26.6158

26.5969

26.4635

26.1936

25.7312

24.8318

23.0844

l/2

alb

l/l

211

a/b

It is useful to note that for the range of values of i listed in the above table, the values If in equation (4.7) for small values of of k(a/b, A) may be obtained by a simple expression. .I we neglect terms in A3 and higher powers, replace cot(rry4) by 4/7r3, and rearrange the terms in (4.4); then for small 1

H. NUTTALL

46

If we write I = lo-“, then equation (4.8) becomes k(a/& R)=k(a/b)+5.8635~,

(4.9)

where the value of k(a/b) for the several values of the ratio (a/b) are given in Table 2. TABLE2

l/4

l/2

314

l/l

413

2/l

4/l

3.1615

3.1425

3.0093

2.7393

2.2770

1.3777

-0.3699

a/b k(0)

5. DISCUSSION

OF THE

CASE @

WHERE

THE

TEMPERATURE

FALLS

FROM

TO 0 NONLINEARLY

It may be that the temperature drop will not be linear in the region 1x1=a, b--E< IyI< 6, but may vary as shown in Figs. 4(a) and (b). A

FIG. 4(b)

FIG. 4(a)

In case 4(a),

[email protected](Y>,wherefI (Y)k 0,

b-&y<

b, .fi(b)=fl(b-&)=O.

In case 4(b), 8=o[l-(E+j

+

@f,(y),

where _fdy> G 0,

b-s
_f2(b)=f2(b--e)=O.

It will be clear that for these cases the solution to our problem is determined by superposing upon the solution (4.3) harmonic functions which satisfy the boundary conditions, o< IXlGz,

e=o,

on IxI=a,

I4
o=o,

on IxJ=a,

b--E< lyl
6 =Of,(y)

case 4(a)

0 = Ofi

case 4(b).

on

jyl=b,

A note on a classical problem in the mathematical

theory of heat conduction

47

It follows from the Mean Value and Maximum Modulus theorems of harmonic functions that the superimposed solution arising fromf;(y) is at all points greater than or equal to zero. This implies a nett inflow of heat into the region along the sides 1x1=a arising from the positive temperature distribution fi(y). Similarly by the same reasoning there is a nett outflow of heat along the sides 1x1=a, arising from the negative distributionf,(y). Thus for the case 4(b) the rate of flow through the region exceeds that calculated upon the assumption of a linear drop over a length E, while in case 4(a) the rate of flow is less than that of the linear assumption. If the departure from linearity is not too great and if tangents to the temperature curves are drawn at the point A and produced to meet the line 1x1=a, at B as in Figs. 4(a) and (b), it will be evident that calculations of heat transfer based upon the linear temperature drops AB Fig. 4(b) and AB Fig. 4(a) will be upper and lower bounds respectively for any curve of temperature intermediate to Ii(y) and f2(y). As an illustration we consider a temperature drop of the form (j=@

[

1_(b-y) -+a(b-y)(b-y-E)

.

E

1

In this expression a@--W-y-s)

is fi(r)

or A(Y)

according as to whether the sign of a is negative or positive. The slope (&/dy) at y= b is given by de

0 dy

0

b=;(l

+a.?).

For a = &(1/2.s’) this gives values 30/2s and O/2&. Thus the rate of heat flow for this case will be bounded between the linear calculations corresponding to 1=2&/3b and 1=2&/b. An indication of the magnitudes of the difference between the upper and lower bounds is given in Table 3 below where the bounds are tabulated for two cases e/b = l/200, e/b = l/1000. The lower bounds for these two cases are given by rows 1 and 3 of Table 1. The upper bound values are calculated from the equation (4.9) and Table 2 for values x=log,,3oo=2~47712,

x=log,,

1500=3~17609. A

b

FIG. 5

48

H.

NUTTALL

TABLE 3

a/b

k(al&) upper E/b

314

l/l

413

2/l

411

17.6671

17.5339

17.2639

16.8016

15.9023

14‘1.547

16.6538

16.6348

16,5016

16.2316

15.7694

14.8702

13.1226

14.8887

14.8699

14.7365 _.~

14.4666

14.0042 _--

13.1046

11.3572

2 I -7845

21-7655

2 I .6323

21.3623

20.9~

20.~7

18.2531

20.7523

20.7334

20.6000

20.3300

19.8676

18.9682

17.2208

18.9871

IX.9682

18.8348

18.5648

18.1024

17.2030

15.4556

l/4

l/Q

17.6861

~-

--

4alb)

.= l/200

linear k(alb) lower ___-

-____-

k(albl

upper Ma/b) linear Ma/b) lower

E/h = l/l000

if the exact nature of the departure of the temperature drop from linearity were known the rate of heat flow could, in principle, be calculated by the method used for the iinear case. However, this is unlikely to be known and the above calculation demonstrates that the rate of heat transfer as calculated on the assumption of linear temperature drop is not unduly sensitive to a moderate departure from linearity. It will be apparent that the method which has been discussed within the context of heat conduction theory is applicable to a class of plane potential problems for rectangular regions with similar boundary conditions and finds analogous application in the fields of electrostatics and hydrodynamics. REFERENCES [I] CARSLAWand JAEGER,Cu~~~r~~~~of Heat in Solids, 121 Z&id.p. 18.

p.

166 (2nd edition). Oxford University Press (1900).

(Received 27 October 1965)

R&m&---Un Ccoulement de chaleur & deux dimensions, stabilisk, dans une region rectangulaire, avec des discontinuitCs de temperature dans les coins, implique une vitesse de transmission de chaleur infinie. Les conditions aux limites, necessaires pour faire apparaitre cet &at, ne sont jamais physiquement r&a&sables. L’auteur donne une mCthode suivant laquelle il est possible, par ie calcul, de faire une estimation de la vitesse de la transmission de chaleur pour des conditions aux fimites plus realistes. Zusammenfassung-Ein zweidimensionaler stationlrer Wirmefluss in einer rechteckigen Zone, in deren Ecken WLrmestosstellen auftreten, setzt voraus, dass die WLrmeleitungen mit unendlich grosser Geschwindigkeit vor sich geht. In der Natur sind die Randbedingungen fiir einen derartigen Zustand niemals gegeben. Hier wird unter der Annahme mehr reatistischer Randbedingungen eine Methode angegeben, mit der sich die Geschwindigkeit der W~rme~~~ragung ann~herungsweise und einfach berechnen &sst. Russo termico uniforme bidimensionaie in una regione rettangolare con una discontinuita di temperatura negli angoli della regione comporta un ritmo infinito di dispersione termica. Le condizioni limite de1 problema the portano a tale condizione non si verificano mai in una situazione fisica reale. In quest0 articolo si propone un metodo con il quale b possible calcolare una semplice stima de1 flusso termico per condizioni limite piti realistiche. Sommario-Un

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