Discrete subsets and convergent sequences in topological groups

Discrete subsets and convergent sequences in topological groups

Topology and its Applications 191 (2015) 137–142 Contents lists available at ScienceDirect Topology and its Applications www.elsevier.com/locate/top...

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Topology and its Applications 191 (2015) 137–142

Contents lists available at ScienceDirect

Topology and its Applications www.elsevier.com/locate/topol

Discrete subsets and convergent sequences in topological groups Valentin Keyantuo a , Yevhen Zelenyuk b,∗,1 a

Department of Mathematics, University of Puerto Rico, PO Box 70377, San Juan, PR 00936-8377, USA b School of Mathematics, University of the Witwatersrand, Private Bag 3, Wits 2050, Johannesburg, South Africa

a r t i c l e

i n f o

Article history: Received 28 October 2014 Received in revised form 29 May 2015 Accepted 31 May 2015 Available online xxxx MSC: primary 03E35, 54H11 secondary 22A05, 54G05

a b s t r a c t We show that (1) assuming there is no rapid ultrafilter, every countable nondiscrete maximally almost periodic topological group contains a discrete nonclosed subset which is a convergent sequence in some weaker totally bounded group topology, (2) every infinite Abelian totally bounded topological group contains such a discrete subset (in ZFC), and (3) if an extremally disconnected topological group contains such a discrete subset, then there is a selective ultrafilter. © 2015 Elsevier B.V. All rights reserved.

Keywords: Topological group Maximally almost periodic Totally bounded Extremally disconnected Discrete subset Convergent sequence Rapid ultrafilter P -point Selective ultafilter

1. Introduction In [8], O. Sipacheva obtained partial solutions to Arhangel’ski˘ı’s question of whether there exists in ZFC a countable nondiscrete extremally disconnected topological group [1] and to Protasov’s question of whether there exists in ZFC a countable nondiscrete topological group in which every discrete subset is closed [6]. It had been known previously that the existence of an extremally disconnected topological group containing a countable discrete nonclosed subset implies the existence of a P -point, and similar result holds for a  nondiscrete group topology T on ω Z2 which is finer than the direct sum topology, has no discrete subset * Corresponding author. 1

E-mail addresses: [email protected] (V. Keyantuo), [email protected] (Y. Zelenyuk). The second author was supported by NRF grant IFR2011033100072.

http://dx.doi.org/10.1016/j.topol.2015.05.089 0166-8641/© 2015 Elsevier B.V. All rights reserved.

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with a unique accumulation point, and satisfies one more condition [10]. (The direct sum topology is the one induced by the product topology.) Sipacheva showed that the existence of a nondiscrete extremally  disconnected group topology on ω Z2 finer than the direct sum topology implies the existence of a rapid  ultrafilter, and similar result holds for a group topology on ω Z2 which is finer than the direct sum topology and has no discrete subset with a unique accumulation point. In this paper we show that (1) assuming there is no rapid ultrafilter, every countable nondiscrete maximally almost periodic topological group contains a discrete nonclosed subset which is a convergent sequence in some weaker totally bounded group topology, (2) every infinite Abelian totally bounded topological group contains such a discrete subset (in ZFC), and (3) the existence of an extremally disconnected topological group containing such a discrete subset implies the existence of a selective ultrafilter. Notice that such a subset has a unique accumulation point and converges to that point in that weaker topology. Recall that a nonprincipal ultrafilter p on ω is (i) a P -point if for every partition {An : n < ω} of ω with An ∈ / p, there is A ∈ p such that |A ∩ An | < ω for all n, (ii) selective if for every partition {An : n < ω} of ω with An ∈ / p, there is A ∈ p such that |A ∩ An | ≤ 1 for all n, and (iii) rapid if for every partition {An : n < ω} of ω with finite An , there is A ∈ p such that |A ∩ An | ≤ n for all n. Clearly, every selective ultrafilter is rapid. MA implies the existence of P -points and rapid ultrafilters. However, it is consistent with ZFC that there is no P -point [7, VI, §4], and it is consistent with ZFC that there is no rapid ultrafilter [5]. A topological group is totally bounded (maximally almost periodic) if it can be topologically and algebraically (continuously and algebraically) embedded into a compact group. All topologies are assumed to be Hausdorff. 2. Rapid ultrafilters Every group topology on a countable group can be weakened to a metrizable (= first countable) group topology [2]. Consequently, every maximally almost periodic group topology on a countable group can be weakened to a metrizable totally bounded group topology. In this section we prove the following result. Theorem 2.1. Assume there is no rapid ultrafilter. Let (G, T ) be a countable nondiscrete maximally almost periodic topological group and let T0 be a metrizable totally bounded group topology on G weaker than T . Then (G, T ) contains a discrete nonclosed subset which is a convergent sequence in T0 . As a consequence we obtain that Corollary 2.2. It is consistent with ZFC that every countable nondiscrete maximally almost periodic topological group contains a discrete nonclosed subset which is a convergent sequence in some weaker totally bounded group topology. The proof of Theorem 2.1 involves the following result [11, Theorem 3.1]. Theorem 2.3. Let G be a countably infinite metrizable totally bounded topological group. Then there exist a  sequence (mn )n<ω of integers ≥ 2 and a homeomorphism h : G → n<ω Zmn with h(1) = 0 such that

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(a) h(xy) = h(x)+h(y) whenever φ(x)+2 ≤ θ(y), where φ(x) = max supp(h(x)) and θ(y) = min supp(h(y)), (b) φ(xi y j ) ≤ max{φ(x), φ(y)} + 1 for all i, j ∈ {1, −1}, and if |φ(x) − φ(y)| ≥ 2, then φ(xi y j ) ≥ max{φ(x), φ(y)} − 1, and (c) if m < ω and h(x)(n) = h(y)(n) for each n ≤ m, then θ(x−1 y), θ(xy −1 ) ≥ m.  Here, n<ω Zmn is endowed with the direct sum topology, and the functions φ and θ are not defined at x = 1. Notice that in [11, Theorem 3.1] property (c) reads as θ(x−1 y), θ(xy −1 ) ≥ m − 1, but the proof shows that in fact θ(x−1 y), θ(xy −1 ) ≥ m holds (although this small improvement plays no role in our result). The next theorem is a more precise statement of Theorem 2.1. Theorem 2.4. Let (G, T ) be a countable nondiscrete maximally almost periodic topological group and let T0 be a metrizable totally bounded group topology on G weaker than T . Suppose (G, T ) contains no discrete  nonclosed subset which is a convergent sequence in T0 . Let h : G → n<ω Zmn be a mapping guaranteed by Theorem 2.3. Then for every ultrafilter p on G converging to 1 in T , the ultrafilter φ(p) on ω is rapid. Here, φ(p) is the ultrafilter on ω with a base consisting of subsets φ(A), where A ∈ p. In the proof of Theorem 2.4 we use the following characterization of rapid ultrafilters [5]: An ultrafilter p on ω is rapid if and only if there is a function h : ω → ω with the property that, whenever f : ω → ω, there exists A ∈ p such that for every n < ω, |A ∩ f (n)| ≤ h(n), where A ∩ f (n) = A ∩ {0, 1, . . . , f (n) − 1}. Proof. Let f : ω → ω be given. Without loss of generality one may suppose that f is increasing. Define U ⊆ G by U = {1} ∪ {x ∈ G : f (θ(x)) < φ(x)}. It then follows that U is a neighborhood of 1 in T . Indeed, assume the contrary. Then 1 is an accumulation point of G \ U = {x ∈ G : f (θ(x)) ≥ φ(x)}. But for every n < ω, there are only finitely many x ∈ G \ U with θ(x) = n, because φ(x) ≤ f (θ(x)). Consequently, G \ U is a sequence converging to 1 in T0 , a contradiction. Pick a neighborhood V of 1 in T such that V V −1 ⊆ U . We claim that for every n < ω, |φ(V ) ∩ f (n)| ≤



mi .

i≤n

To see this, assume the contrary. Then there exist distinct x, y ∈ V \ {1} such that φ(x), φ(y) < f (n) and h(x)(i) = h(y)(i) for each i ≤ n. Let z = xy −1 . Then 1 = z ∈ U , θ(z) ≥ n, and φ(z) ≤ f (n). Hence, f (n) ≤ f (θ(z)) < φ(z) ≤ f (n), a contradiction. 2 3. Totally bounded topological groups In [6] it was shown that every infinite totally bounded topological group contains a countable discrete nonclosed subset. In this section we derive from Theorem 2.4 the following result.

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Theorem 3.1. Let (G, T ) be a countably infinite totally bounded topological group and let T0 be a metrizable group topology on G weaker than T . Then (G, T ) contains a discrete nonclosed subset which is a convergent sequence in T0 . Given a group G and a left invariant topology T on G, Ult(T ) ⊆ βG consists of all nonprincipal ultrafilters on G converging to 1 in T and is called the ultrafilter semigroup of T (see [9, Section 7.1]). Here, βG is the Stone–Čech compactification of G. The points of βG are the ultrafilters on G and the topology is generated by taking as a base the subsets A = {p ∈ βG : A ∈ p}, where A ⊆ G. For any p, q ∈ βG, the ultrafilter  pq ∈ βG has a base consisting of subsets x∈A xBx , where A ∈ p and Bx ∈ q for every x ∈ A. See [4] and [9] for more information about βG. Lemma 3.2. Let (G, T ) be a countably infinite metrizable totally bounded topological group, let h : (G, T ) →  ∗ n<ω Zmn be a mapping guaranteed by Theorem 2.1, and let S = Ult(T ). Then φ(S) = ω , and for every u ∈ ω ∗ , φ−1 (u) ∩ S is a closed left ideal of S. Proof. For every n < ω, pick xn ∈ G with supp(h(x)) = {n}. The sequence (xn )n<ω converges to 1 in T . It then follows that φ(S) = ω ∗ . Now let p ∈ S and q ∈ φ−1 (u) ∩ S. Then pq ∈ S, and we claim that φ(pq) = u. To see this, let A ∈ u. Put P = G \ {1}, and for every x ∈ P , pick Qx ∈ q such that φ(Qx ) ⊆ A and φ(x) + 2 ≤ θ(y) for all y ∈ Qx ,  so φ(xy) = φ(y). Let R = x∈P xQx . Then R ∈ pq and φ(R) ⊆ A. 2  Proof of Theorem 3.1. Let h : (G, T0 ) → n<ω Zmn be a mapping guaranteed by Theorem 2.1 and let S = Ult(T ) and S0 = Ult(T0 ). By Lemma 3.2, φ(S0 ) = ω ∗ , and for every u ∈ ω ∗ , φ−1 (u) ∩ S0 is a closed left ideal of S0 , so φ−1 (u) ∩ S0 contains an idempotent (see [9, Theorem 6.12]). Since S contains all the idempotents of G∗ [9, Lemma 7.10], it follows that φ(S) = ω ∗ . Consequently, there are ultrafilters in φ(S) which are not rapid. Hence by Theorem 2.3, (G, T ) contains a discrete nonclosed subset which is a convergent sequence in T0 . 2 Now we are going to extend Theorem 3.1 to all infinite Abelian totally bounded topological groups. Lemma 3.3. Let (G, T ) be an Abelian totally bounded topological group, let H be a subgroup of G, and let T0 be a group topology on H weaker than T |H . Then there is a group topology T1 on G weaker than T such that T1 |H = T0 . Proof. Let Γ denote the set of all characters of (G, T ) (= continuous homomorphisms ϕ : (G, T ) → T) and Γ0 the set of all characters of (H, T0 ) and let Γ1 = {ϕ ∈ Γ : ϕ|H ∈ Γ0 }. Then {ϕ|H : ϕ ∈ Γ1 } = Γ0 , and for every a ∈ G \ H, there is ϕ ∈ Γ1 such that ϕ(a) = 1 ([3, Corollary 24.12]). Let T1 be the coarsest topology on G in which each character from Γ1 is continuous. 2 Theorem 3.4. Every infinite Abelian totally bounded topological group contains a discrete nonclosed subset which is a convergent sequence in some weaker group topology. Proof. Let (G, T ) be an infinite Abelian totally bounded topological group. Pick a countably infinite subgroup H of G and a metrizable group topology T0 on H weaker than T |H . By Lemma 3.3, there is a group topology T1 on G weaker than T such that T1 |H = T0 . By Theorem 3.1, there is a sequence (xn )n<ω in H having 1 as an accumulation point in T |H and converging to 1 in T0 . But then (xn )n<ω converges to 1 in T1 , and consequently, 1 is the unique accumulation point of (xn )n<ω in T . 2 Using the same argument as in the proof of Theorem 3.4, we obtain the following result.

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Theorem 3.5. Assume there is no rapid ultrafilter. Then every nondiscrete Abelian maximally almost periodic topological group containing a countable nondiscrete subset has a discrete nonclosed subset which is a convergent sequence in some weaker totally bounded group topology. Corollary 3.6. It is consistent with ZFC that every nondiscrete Abelian maximally almost periodic topological group containing a countable nondiscrete subset has a discrete nonclosed subset which is a convergent sequence in some weaker totally bounded group topology. 4. P -points and selective ultrafilters Let X be a space, let D be a discrete subset of X, and let x ∈ X be an accumulation point of D. We say that D is locally maximal with respect to x if there is an open U ⊆ X containing D such that, whenever C ⊆ U \ D and D ∪ C ⊆ U is discrete, x is not an accumulation point of C. Notice that if X is extremally disconnected and D is countable, then D is locally maximal with respect to x and there is only one ultrafilter on X containing D and converging to x (see [9, Lemma 5.13]). Theorem 4.1. Let G be a topological group and let D be a countable discrete subset of G with 1 being an accumulation point of D. Suppose that D is locally maximal with respect to 1 and there is only one ultrafilter p on G containing D and converging to 1. Then there is a mapping f : G → ω such that f (p) is a P -point. Furthermore, if D is a convergent sequence in some weaker group topology on G, then f can be chosen so that f (p) is a selective ultrafilter. Proof. Let U be an open neighborhood of D ⊆ X witnessing that D is locally maximal with respect to 1. Enumerate D as {xn : n < ω}. Construct inductively a decreasing sequence (Un )n<ω of open neighborhoods of 1 with U0 = G such that xn ∈ / Un+1 and the subsets xn Un+1 , where n < ω, are pairwise disjoint and  contained in U . Define f : D → ω by f (x) = n if x ∈ Un \ Un+1 , and let q = f (p). Since n<ω Un ∩ D = ∅, q is a nonprincipal ultrafilter on ω. We prove that q is a P -point. / q and let Dm = f −1 (Am ). Then {Dm : m < ω} is a Let {Am : m < ω} be a partition of ω with Am ∈ partition of D with Dm ∈ / p, so 1 is not an accumulation point of Dm . Every element xn ∈ D belongs to  some subset Dmn of the partition. Put C = n<ω xn (Un+1 ∩ Dmn ). Then C is disjoint from D and D ∪ C is a discrete subset of U . Since D is locally maximal, it follows that G \ C is a neighborhood of 1. Pick a neighborhood V of 1 such that V 2 ⊆ G \ C. Put E = D ∩ V and A = f (E). We claim that for every m < ω, A ∩ Am is finite. To see this, assume the contrary. Then there exist xn ∈ E ∩ Dm and xk ∈ Un+1 ∩ E ∩ Dm . On the one hand, xn xk ∈ E 2 ⊆ V 2 , and on the other hand, xn xk ∈ xn (Un+1 ∩ Dm ) ⊆ C, a contradiction. Notice that we would have |A ∩ Am | ≤ 1, and so f (p) would be a selective ultrafilter, if (Un )n<ω were a  decreasing sequence of open neighborhoods of 1 with n<ω Un ∩ D = ∅ such that the sets yn Un+1 , where n < ω and yn ∈ (Un \ Un+1 ) ∩ D, are pairwise disjoint. Indeed, otherwise there exist n < k < ω, yn ∈ (Un \ Un+1 ) ∩ Dm ∩ E and yk ∈ (Uk \ Uk+1 ) ∩ Dm ∩ E, and then, on the one hand, yn yk ∈ E 2 ⊆ V 2 , and on the other hand, yn yk ∈ yn (Un+1 ∩Dm ) ⊆ C, a contradiction. It remains to show how to arrive at this situation supposing that D is a convergent sequence is some weaker group topology T0 on G. Construct inductively a decreasing sequence (Un )n<ω of open neighborhoods of 1 in T0 such that  n<ω Un ∩ D = ∅ and the sets yn Un+2 , where n < ω and yn ∈ (Un \ Un+1 ) ∩ D, are pairwise disjoint and contained in U . We can do this because D is a convergent sequence in T0 , and so (Un \ Un+1 ) ∩ D is   finite. Let D = n<ω (U2n \ U2n+1 ) ∩ D and D = n<ω (U2n+1 \ U2n+2 ) ∩ D. The sets D and D form a partition of D, so one of them is a member of p. Without loss of generality one may suppose that D ∈ p.   Let Un = U2n . Then the sets yn Un+1 , where n < ω and yn ∈ (Un \ Un+1 ) ∩ D , are pairwise disjoint and contained in U . 2

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Corollary 4.2. Let G be an extremally disconnected topological group and let D be a countable discrete nonclosed subset of G. Then there is a mapping f : G → ω such that f (p) is a P -point. Furthermore, if D is a convergent sequence in some weaker group topology on G, then f can be chosen so that f (p) is a selective ultrafilter. The first part of Corollary 4.2 is the result from [10]. From the second part of Corollary 4.2 and Theorem 2.1 we obtain the result from [8]. Corollary 4.3. Assume there is no rapid ultrafilter. Then there is no countable nondiscrete extremally disconnected topological group that is maximally almost periodic. Proof. Let G be a countable nondiscrete extremally disconnected maximally almost periodic topological group. If G contains no discrete nonclosed subset being a convergent sequence in some weaker totally bounded group topology, then by Theorem 2.1, there is a rapid ultrafilter. Otherwise by Corollary 4.2, there is a selective ultrafilter. 2 References [1] A. Arhangel’ski˘ı, Every extremally disconnected bicompactum of weight c is inhomogeneous, Sov. Math. Dokl. 8 (1967) 897–900. [2] A. Arhangel’ski˘ı, Cardinal invariants of topological groups. Embeddings and condensations, Sov. Math. Dokl. 20 (1979) 783–787. [3] E. Hewitt, K. Ross, Abstract Harmonic Analysis, I, Springer-Verlag, 1979. [4] N. Hindman, D. Strauss, Algebra in the Stone–Čech Compactification, De Gruyter, Berlin, 1998. [5] A. Miller, There are no Q-points in Laver’s model for the Borel conjecture, Proc. Am. Math. Soc. 78 (1980) 103–106. [6] I. Protasov, Discrete subsets of topological groups, Math. Notes 55 (1994) 101–102. [7] S. Shelah, Proper and Improper Forcing, Springer, Berlin, 1998. [8] O. Sipacheva, Nonexistence of countable extremally disconnected groups with many open subgroups, Topol. Appl. 179 (2015) 193–199. [9] Y. Zelenyuk, Ultrafilters and Topologies on Groups, De Gruyter, Berlin, 2011. [10] Y. Zelenyuk, On extremally disconnected topological groups, Topol. Appl. 153 (2006) 177–181. [11] Y. Zelenyuk, Local homomorphisms of topological groups, J. Aust. Math. Soc. 83 (2007) 135–148.