Erratum to: “Performance analysis of Jakimoski–Kocarev attack on a class of chaotic cryptosystems”

Erratum to: “Performance analysis of Jakimoski–Kocarev attack on a class of chaotic cryptosystems”

Physics Letters A 309 (2003) 165 www.elsevier.com/locate/pla Erratum Erratum to: “Performance analysis of Jakimoski–Kocarev attack on a class of cha...

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Physics Letters A 309 (2003) 165 www.elsevier.com/locate/pla

Erratum

Erratum to: “Performance analysis of Jakimoski–Kocarev attack on a class of chaotic cryptosystems” [Phys. Lett. A 307 (2003) 22] ✩ Shujun Li a,∗ , Xuanqin Mou a , Zhen Ji b , Jihong Zhang b , Yuanlong Cai a a Institute of Image Processing, School of Electronics and Information Engineering, Xi’an Jiaotong University,

Xi’an, Shaanxi 710049, PR China b College of Information Engineering, Shenzhen University, Shenzen Guangdong 518060, PR China

The Publisher regrets that in the above article, the following errors had not been corrected. (i−1) (i−1) (i) On page 23, right column, first paragraph, last line, the equation ‘x0 = F Ci (x0 )’ should read ‘x0 = F Ci (x0(i−1))’. (i) On page 23, right column, second paragraph, third line, the equation ‘x0 = F C1 +C2 +···+Ci−1 (x0 )’ should read ‘x0(i−1) = F C1 +C2 +···+Ci−1 (x0 )’. (i) On page 26, left column, last paragraph, fifth line, the equation ‘x0 = F C1 +C2 +···+Ci−1 (x0 )’ should read (i) ‘x0 = F C1 +C2 +···+Ci (x0 )’. On page 26, left column, last paragraph, last four lines, ‘Of course, any possible bit extracting function can be used, but we will point out that fbe (x0(i) ) cannot be freely selected to avoid information leaking of the current chaotic state.’ should read ‘Please note that the bit extracting function cannot be freely selected to avoid information leaking of the current chaotic state, which will be discussed in the next subsection.’   ( C1 +···+Ci−1 F j (x ))’ should read On page 27, the right side of the first line of equation (2), ‘fbe 0 j =0   ( C1 +···+Ci F j (x ))’. That is to say, Eq. (2) should read: ‘fbe 0 j =0  (i)   fbe x0 = fbe

 C1 +···+C  i

  (i)   x0 ⊕ F (x0 ) ⊕ · · · ⊕ x0 . F j (x0 ) = fbe

(2)

j =0

Accordingly, in the fourth line after Eq. (2), the equation ‘



C1 +···+Ci−1 j =0

doi of original article: 10.1016/S0375-9601(02)01659-6.

* Corresponding author.

E-mail address: [email protected] (S. Li). 0375-9601/03/$ – see front matter  2003 Elsevier Science B.V. All rights reserved. doi:10.1016/S0375-9601(03)00073-2

F j (x0 )’ should read ‘

C1 +···+Ci j =0

F j (x0 )’.