x<+cQ (6) where Y is a symmetric error measure. Rewriting the arguments on the left of (6) in terms of p”/x and x, and using the symmetry of Y, gives j((p”/x) . x)1/2 - x 1 = 1(x . (P”/x))“” - (P”/X)l d(x - (P”/4>““, P”l4 . F(((P2/X) . xY2, x) ERROR MEASURES AND ASSOCIATED MEANS 65 This relation reduces to dP3x>= (X/P> dP3P2/4> Q