Exact solutions to mKdV equation with variable coefficients

Exact solutions to mKdV equation with variable coefficients

Applied Mathematics and Computation 216 (2010) 2792–2798 Contents lists available at ScienceDirect Applied Mathematics and Computation journal homep...

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Applied Mathematics and Computation 216 (2010) 2792–2798

Contents lists available at ScienceDirect

Applied Mathematics and Computation journal homepage: www.elsevier.com/locate/amc

Exact solutions to mKdV equation with variable coefficients Alvaro H. Salas * Universidad de Caldas, Manizales, Colombia Department of Mathematics, Universidad Nacional de Colombia, Manizales, Colombia

a r t i c l e

i n f o

a b s t r a c t In this paper a special mKdV with variable coefficients is considered. A transformation of variables is first applied in order to obtain a mKdV equation with constant coefficients. Some its one-, two- and three-soliton as well as breather-type soliton solutions are derived by using Hirorta’s bilinear approach. Ó 2010 Elsevier Inc. All rights reserved.

Keywords: KdV mKdV Hirota’s method Bilinear form Multisoliton solution

1. Introduction Modified Kortweg-de Vries (mKdV) equation manifests in diverse areas of physics [1–6]. For example, it appears in the context of, electromagnetic waves in size-quantized films, van Alfén waves in collisionless plasma [7], phonons in anharmonic lattice [8], interfacial waves in two layer liquid with gradually varying depth [9], transmission lines in Schottky barrier [10], ion acoustic solitons [11,12], elastic media [13], and traffic flow problems [14,15]. It is an integrable dynamical system with an infinite number of conserved quantities; the solutions of this equation are well studied [16,17]. Recently nonlinear equations with variable coefficients have attracted considerable attention in the literature. Nonlinear Schro¯dinger equation (NLSE) with variable nonlinearity and dispersion is relevant to both optical fibers and Bose–Einstein condensates [18]. Nonlinear Schro¯dinger equation with source, having distributed coefficients like variable dispersion, variable Kerr nonlinearity and gain or loss, is applicable to asymmetric twin-core optical fibers [19,20]. It has been shown that, solitons can be compressed and their dynamics effectively controlled through these variable parameters. The Kortweg-de Vries (KdV) equation with variable coefficients has been studied recently in the context of ocean waves, where the spatio-temporal variability of the coefficients are due to the changes in the water depth and other physical conditions. The fact that, mKdV equation is relevant to hydrodynamics and a variety of physical phenomena, it is natural to expect the possibility of temporal variations in the equation parameters occurring in the same. Furthermore, for propagating solitons, the first integral of the mKdV equation yields NLSE with a source, making it imperative to investigate the effect of the temporal variation of the distributed parameters on the solitary wave solutions of this dynamical system. The mKdV with variable coefficients we shall consider has the form

ws þ pðsÞw2 wn þ cpðsÞwnnn ¼ 0;

where w ¼ wðs; nÞ and c ¼ constant > 0:

ð1:1Þ

Our next purpose is to apply a suitable transformation of the variables n and s to reduce Eq. (1.1) to an equation with constant coefficients. To this end, let

t ¼ tðs; nÞ;

x ¼ xðs; nÞ and wðs; nÞ ¼ v ðtðs; nÞ; xðs; nÞÞ ¼ v ðt; xÞ;

where x(s, n) and t(s, n) are some functions to be determined. Inserting (1.2) into (1.1) gives following equation: * Address: Department of Mathematics, Universidad Nacional de Colombia, Manizales, Colombia. E-mail address: [email protected] 0096-3003/$ - see front matter Ó 2010 Elsevier Inc. All rights reserved. doi:10.1016/j.amc.2010.03.129

ð1:2Þ

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ðcpðsÞt nnn þ ts Þv t þ pðsÞxn v 2 v x þ cpðsÞx3n v xxx þ ðcpðsÞxnnn þ xs Þv x þ 3cpðsÞxn xnn v xx þ ð3cpðsÞt n xnn þ 3cpðsÞxn tnn Þv tx þ 3cpðsÞx2n t n v txx þ 3cpðsÞxn t 2n v ttx þ cpðsÞt3n v ttt þ pðsÞtn v 2 v t þ 3cpðsÞtn tnn v tt ¼ 0:

ð1:3Þ

Now, we choose functions x(s, n) and t(s, n) so that

1 1 ts ¼ pffiffiffiffiffiffi pðsÞ and xn ¼ pffiffiffiffiffiffi ; a ac ac

tn ¼ xnn ¼ xs ¼ 0;

where a ¼ constant > 0:

ð1:4Þ

Under restrictions (1.4) Eq. (1.3) takes the form

pðsÞ



v t þ av 2 v x þ v xxx



¼ 0:

ð1:5Þ

In view of (1.4) and (1.5), to solve (1.1), we first find solutions to following mKdV equation with constant coefficients

v t þ av 2 v x þ v xxx ¼ 0

ð1:6Þ

and then a solution to Eq. (1.1) may be found by the formula

wðs; nÞ ¼ v ðt; xÞ;

1 where t ¼ tðsÞ ¼ pffiffiffiffiffiffi a ac

Z

1 pðsÞdsx ¼ xðnÞ ¼ pffiffiffiffiffiffi n: ac

ð1:7Þ

To solve Eq. (1.5), we may solve its potential version

1 ut þ aðux Þ3 þ uxxx ¼ 0 with 3

v ¼ ux :

ð1:8Þ

2. Hirota’s method In this section we make use of Hirota’s approach [21] to solve nonlinear pde’s. For any two smooth functions f = f(t, x) and g = g(t, x) we define Hirota operators as

  @m @n  ½ f ðt þ s; x þ yÞgðt  s; x  yÞ  for m; n ¼ 1; 2; 3; . . . ;  @sm @yn s¼0;y¼0   @m m Dm ½f ðt þ s; xÞgðt  s; xÞ for m ¼ 1; 2; 3; . . . ; t ðf  gÞ ¼ Dt ðf ðt; xÞgðt; xÞÞ ¼ m @s s¼0   @n Dnx ðf  gÞ ¼ Dnx ðf ðt; xÞgðt; xÞÞ ¼ n ½f ðt; x þ yÞgðt; x  yÞ for n ¼ 1; 2; 3; . . . : @y y¼0 n m n Dm t Dx ðf  gÞ ¼ Dt Dx ðf ðt; xÞgðt; xÞÞ ¼

ð2:1Þ ð2:2Þ ð2:3Þ

In particular,

Dtx ðf  f Þ ¼ Dxt ðf  f Þ ¼ D1t D1x ðf  f Þ ¼ 2ðfftx  ft fx Þ;

ð2:4Þ

Dx ðf  gÞ ¼ D1x ðf  gÞ ¼ gfx  fg x ; Dt ðf  gÞ ¼ D1t ðf  gÞ ¼ fg t  gft ;   Dxx ðf  f Þ ¼ D2x ðf  f Þ ¼ 2 fx2  ffxx ;   Dxx ðg  gÞ ¼ D2x ðg  gÞ ¼ 2 g 2x  gg xx ; Dxxx ðf  gÞ ¼ D3x ðf  gÞ ¼ 3f x g xx  3f xx g x

ð2:5Þ ð2:6Þ ð2:7Þ ð2:8Þ  fg xxx þ gfxxx :

ð2:9Þ

From (2.4)–(2.9) it follows that

2f t fx þ Dtx ðf  f Þ gfx  Dx ðf  gÞ gft  Dt ðf  gÞ ; gx ¼ ; gt ¼ ; 2f f f 2f 2 þ Dxx ðf  f Þ 2g 2 þ Dxx ðg  gÞ 3f g  3f xx g x þ gfxxx  Dxxx ðf  gÞ fxx ¼ x ; g xx ¼ x ; g xxx ¼ x xx : 2f 2g f

ftx ¼ fxt ¼

ð2:10Þ ð2:11Þ

We seek solutions to Eq. (1.8) in the form

u ¼ uðt; xÞ ¼ arctan

  gðt; xÞ : f ðt; xÞ

Substituting ansatz (2.12) into (1.8) gives following pde:

ð2:12Þ

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A.H. Salas / Applied Mathematics and Computation 216 (2010) 2792–2798

  ð3g xxx þ 3g t Þf 5  3ðfxxx þ ft Þf 4 g  9ðfxx g x þ fx g xx Þf 4 þ 6ðg xxx þ g t Þf 3 g 2 þ 18fx2 g x þ ag 3x  6g 3x f 3   4 þ 18ðfx fxx  g x g xx Þf 3 g  6ðfxxx þ ft Þf 2 g 3  3 afx g 2x  18f x g 2x þ 6fx3 f 2 g  3ðfxxx þ ft Þg 5 þ 3ðg xxx þ g t Þfg     2 3 þ 9ðfxx g x þ fx g xx Þg 4  18f x g 2x þ afx3  6fx3 g 3 þ 18ðfx fxx  g x g xx Þfg þ 3 afx2 g x  18fx2 g x þ 6g 3x fg ¼ 0:

ð2:13Þ

To put this equation in its bilinear form, we substitute (2.10) and (2.11) into (2.13) to obtain

   2 3 ða  24ÞðDx ðf  gÞÞ  9 f 2 þ g 2 Dx ðf  gÞ½Dxx ðf  f Þ þ Dxx ðg  gÞ þ 3 f 2 þ g 2 ½Dt ðf  gÞ þ Dxxx ðf  gÞ ¼ 0:

ð2:14Þ

Eq. (2.14) shows that it is convenient to choose a = 24. Decoupling Eq. (2.14) gives following bilinear form to Eq. (1.8):



Dxx ðf  f Þ þ Dxx ðg  gÞ ¼ 0;

ð2:15Þ

Dt ðf  gÞ þ Dxxx ðf  gÞ ¼ 0:

Observe that we have derived the bilinear form of Eq. (1.8) algorithmically. Accordingly in view of (2.6)–(2.9), system (2.14) may be written equivalently as

(

fx2  fxx f þ g 2x  g xx g ¼ 0;

ð2:16Þ

fg t  gft þ 3f x g xx  3f xx g x  fg xxx þ gfxxx ¼ 0: It is obvious that if the pair f = f(t, x) and g = g(t, x) is a solution to system (2.16), then function

u ¼ uðx; tÞ ¼ arctan

  gðt; xÞ f ðt; xÞ

ð2:17Þ

is a solution to the potential mKdV equation (1.8) with a = 24 and then

v ¼ v ðt; xÞ ¼ @ x arctan

  gðt; xÞ fg  gfx ¼ 2x f ðt; xÞ f þ g2

ð2:18Þ

is a solution to mKdV equation (1.6). Consequently, a solution to our main Eq. (1.1) may be calculated by formula (1.7) with a = 24:

wðs; nÞ ¼ v



1 pffiffiffiffiffiffi 48 6c

 1 pðsÞds; pffiffiffiffiffiffi n : 2 6c

Z

ð2:19Þ

In the next section we obtain exact solutions to Eq. (1.6) with a = 24:

v t þ 24v 2 v x þ v xxx ¼ 0:

ð2:20Þ

3. Solutions to mKdV equation 3.1. One-soliton solutions We seek solutions to system (2.16) in the form

f ¼ a0 þ a1 expðkx  xtÞ and g ¼ 1 þ b1 expðkx  xtÞ;

ð3:1Þ

for some constants a0, a1, b1, k – 0 and x – 0. From (2.16) and (3.1) we obtain following equations:

(

2

k ða0 a1 þ b1 Þ expðkx  xtÞ ¼ 0; 2

ð3:2Þ

3

k ða0 b1  a1 Þðx  k Þ expðkx  xtÞ ¼ 0: Solving (3.2) gives

x ¼ k3 ; b1 ¼ a0 a1 :

ð3:3Þ

This in turns gives following solution to Eq. (2.20): 3

v 1 ðt; xÞ ¼ @ x arctan

1  a0 a1 expðkx  k tÞ 3

a0 þ a1 expðkx  k tÞ

!

3

¼

ka1 expðkx  k tÞ 3

1 þ a21 expð2ðkx  k tÞÞ

:

ð3:4Þ

In particular, if a = 1 we obtain the solution

vf1 ðt; xÞ ¼ 

1 3 k sechðkx  k tÞ: 2

ð3:5Þ

A.H. Salas / Applied Mathematics and Computation 216 (2010) 2792–2798

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3.2. Two-soliton solutions We seek solutions to system (2.16) in the form



f ¼ 1 þ a1 expðk1 x  x1 tÞ þ a2 expðk2 x  x2 tÞ þ a3 expðk1 x  x1 t þ k2 x  x2 tÞ; g ¼ 1 þ b1 expðk1 x  x1 tÞ þ b2 expðk2 x  x2 tÞ þ b3 expðk1 x  x1 t þ k2 x  x2 tÞ;

ð3:6Þ

for some constants a1, a2, a 3, b1, b2, b3, k1 – 0, k2 – 0, x1 – 0 and x2 – 0. Let

X ¼ expðk1 x  x1 tÞ and Y ¼ expðk2 x  x2 tÞ:

ð3:7Þ i j

Inserting (3.6) into (2.16) and equating to zero the different coefficients of X Y (i, j = 0, 1, 2, 3, . . . ) yields an algebraic system in the unknowns ai, bi, ki, xi. Solving it we get following solutions:

a1 ¼ b1 ;

a2 ¼ b2 ;

a3 ¼ b3 ¼ b1 b2

ðk1  k2 Þ2 ðk1 þ k2 Þ2

x1 ¼ k31 ; x2 ¼ k32 :

;

ð3:8Þ

From (2.18), (3.6) and (3.8) we see that a two-soliton solution to Eq. (2.20) is



1



2 3 3 3 3 1 k2 Þ 1 þ b1 exp k1 x  k1 t þ b2 exp k2 x  k2 t  b1 b2 ðk ðk1 þ k2 Þx  k1 þ k2 t 2 exp ðk þk Þ 1 2

A:



v 2 ðt; xÞ ¼ @ x arctan @ 2 3 3 3 3 1 k2 Þ t ðk þ k Þx  k þ k 1  b1 exp k1 x  k1 t  b2 exp k2 x  k2 t  b1 b2 ðk 1 2 2 exp 1 2 ðk þk Þ 0

1

ð3:9Þ

2

Similarly, if we assume an anstaz of the form



f ¼ 1 þ a1 expðk1 x  x1 tÞ þ a2 expðk2 x  x2 tÞ þ a3 expðk1 x  x1 t þ k2 x  x2 tÞ; g ¼ b1 expðk1 x  x1 tÞ þ b2 expðk2 x  x2 tÞ þ b3 expðk1 x  x1 t þ k2 x  x2 tÞ;

ð3:10Þ

we obtain

a1 ¼ a2 ¼ b3 ¼ 0;

a3 ¼ b1 b2

ðk1  k2 Þ2 ðk1 þ k2 Þ2

;

x1 ¼ k31 ; x2 ¼ k32

ð3:11Þ

and the corresponding two-soliton solution to Eq. (2.20) is (see Fig. 1):







1 2 3 3 3 3 1 k2 Þ b1 exp k1 x  k1 t þ b2 exp k2 x  k2 t  b1 b2 ðk k1 þ k2 t 2 exp ðk1 þ k2 Þx  ðk þk Þ 1 2 A:

v 3 ðt; xÞ ¼ @ x arctan @ 2 3 3 1 k2 Þ ðk þ k Þx  k þ k 1  b1 b2 ðk t 1 2 2 exp 1 2 ðk þk Þ 0

1

2

3.3. Three-soliton solutions We seek solutions to system (2.16) in the form

Fig. 1. Graphic of function

v3(x, t) for k1 = 3, k2 = 1, b1 = 3, b2 = 2, 0.1 6 t 6 0.5 and 4 6 x 6 6.

ð3:12Þ

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A.H. Salas / Applied Mathematics and Computation 216 (2010) 2792–2798

8 > < f ¼ 1 þ a12 expðn1 þ n2 Þ þ a13 expðn1 þ n3 Þ þ a23 expðn2 þ n3 Þ; g ¼ b1 expðn1 Þ þ b2 expðn2 Þ þ b3 expðn3 Þ þ b123 expðn1 þ n2 þ n3 Þ; > : n1 ¼ k1 x  x1 t; n2 ¼ k2 x  x2 t; n3 ¼ k3 x  x3 t;

ð3:13Þ

for some constants a12, a13, a23, b123, b2, b3, ki – 0 and xi – 0 (i = 1, 2, 3). Inserting (3.6) into (2.16) and equating to zero the different coefficients of ni1 nj2 nk3 (i, j, k = 0, 1, 2, 3, . . . ) yields an algebraic system. Solving it gives

a12 ¼ b1 b2

ðk1  k2 Þ2 ðk1 þ k2 Þ

b123 ¼ b1 b2 b3

2

;

a13 ¼ b1 b3

ðk1  k3 Þ2 2

ðk1 þ k3 Þ

ðk1  k2 Þ2 ðk1  k3 Þ2 ðk2  k3 Þ2 ðk1 þ k2 Þ2 ðk1 þ k3 Þ2 ðk2 þ k3 Þ2

;

;

a23 ¼ b2 b3

ðk2  k3 Þ2 ðk2 þ k3 Þ2

;

x1 ¼ k31 ; x2 ¼ k32 ; x3 ¼ k33 :

ð3:14Þ ð3:15Þ

From (3.13)–(3.15) we see that a three-soliton solution to Eq. (2.20) is

v 4 ðt; xÞ ¼ @ x arctan

  b1 expðn1 Þ þ b2 expðn2 Þ þ b3 expðn3 Þ þ b123 expðn1 þ n2 þ n3 Þ : 1 þ a12 expðn1 þ n2 Þ þ a13 expðn1 þ n3 Þ þ a23 expðn2 þ n3 Þ

ð3:16Þ

3.4. Breather-type solutions We seek solutions to system (2.16) in the form



f ¼ a1 coshðk1 x  x1 tÞ þ b1 cosðk2 x  x2 tÞ; g ¼ c1 coshðk1 x  x1 tÞ þ d1 cosðk2 x  x2 tÞ;

ð3:17Þ

for some constants a1, b1, c1, d1, b2, k1 – 0, k2 – 0, x1 – 0 and x2 – 0. Let

X ¼ expðk1 x  x1 tÞ and Y ¼ exp

pffiffiffiffiffiffiffi

1ðk2 x  x2 tÞ :

ð3:18Þ

Inserting (3.17) into (2.16) and equating to zero the different coefficients of XiYj (i, j = 0, 1, 2, 3, . . . ) yields an algebraic system in the unknowns ai, bi, ki, xi. This system reads

Fig. 2. Graphic of function

v5(x, t) for k1 = 2, k2 = 3, a1 = 3, b1 = 1, 0.1 6 t 6 0.1 and 2.5 6 x 6 3.5.

A.H. Salas / Applied Mathematics and Computation 216 (2010) 2792–2798

8 pffiffiffiffiffiffiffi 2 > > k  1k2 ða1 b1 þ c1 d1 Þ ¼ 0; > 1 > > < 

 2 2 2 2 k1 a21 þ c21  k2 b1 þ d1 ¼ 0; > >

> pffiffiffiffiffiffiffi > > : x1  k31 þ 3k22 k1 þ 1 x2 þ k32  3k21 k2 ðb1 c1  a1 d1 Þ ¼ 0:

2797

ð3:19Þ

Solving this system we obtain:

c1 ¼ 

b1 k2 ; k1

d1 ¼ 

a1 k1 ; k2









x1 ¼ k1 k21  3k22 ; x2 ¼ k2 k22  3k21 :

ð3:20Þ

From (2.18), (3.6) and (3.8) we see that a two-soliton solution to Eq. (2.20) is (see Fig. 2):





1 2 2 2 2 2 2 a1 k1 cos k2 x þ k2 k2  3k1 t  b1 k2 cosh k1 x  k1 k1  3k2 t 1



A: v 5 ðt; xÞ ¼ @ x arctan @ k1 k2 b1 cos k2 x þ k2 k2  3k2 t þ a1 cosh k1 x  k1 k2  3k2 t 2 1 1 2 0

4. Concluding remarks Sometimes, we may reduce the problem of finding solutions to an nonlinear pde with variable coefficients to that of solving a similar equation with constant coefficients. This approach simplifies the tedious algebraic computations and allows us to use known results. On the other hand, Hirota’s method is a powerful tool for solving nonlinear pde’s in mathematical physics. Other results concerning pde’s with variable coefficients may be found in [22–24,34,35]. Additional results concerning the problem of finding analytic solutions to nonlinear pde’s are derived in [25–33]. We think that some of the results we presented in this work are new in the open literature. References [1] R.M. Miura, C.S. Gardner, M.D. Kruskal, Korteweg-de Vries equation and generalizations. II. existence of conservation laws and constants of motion, J. Math. Phys. 9 (1968) 1204. [2] M. Wadati, The exact solution of the modified Korteweg-de Vries equation, J. Phys. Soc. Jpn. 32 (1972) 1681. 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