Physics Letters B 610 (2005) 61–66 www.elsevier.com/locate/physletb
Non-forward BFKL pomeron at next-to-leading order ✩ V.S. Fadin a , R. Fiore b a Budker Institute for Nuclear Physics and Novosibirsk State University, 630090 Novosibirsk, Russia b Dipartimento di Fisica, Università della Calabria and Istituto Nazionale di Fisica Nucleare, Gruppo Collegato di Cosenza,
I-87036 Arcavacata di Rende, Cosenza, Italy Received 7 January 2005; accepted 24 January 2005 Available online 29 January 2005 Editor: P.V. Landshoff
Abstract The kernel of the BFKL equation for non-zero momentum transfer is found at next-to-leading order. It is presented in various forms depending on the regularization of the infrared singularities in “virtual” and “real” parts of the kernel. The infrared safety of the total kernel is demonstrated and a form free from the singularities is suggested. 2005 Elsevier B.V. All rights reserved.
The kernel of the BFKL equation [1] for the case of forward scattering, i.e., for the momentum transfer t = 0 and vacuum quantum numbers in the t-channel, was found at next-to-leading order (NLO) already five years ago [2]. Unfortunately, the NLO calculation of the kernel for non-forward scattering was not completed till now. We remind that the kernel depends on the representation of the colour group in the t-channel; however, for any representation R it is given by the sum of “virtual” and “real” contributions [3]. The “virtual” contribution is universal (does not depend on R). It is expressed through the NLO gluon Regge trajectory [4] and is known. The “real” contribution is related to particle production in Reggeon–Reggeon collisions and consists of parts coming from one-gluon, two-gluon and quark–antiquark pair production. The first part is expressed through the effective Reggeon–Reggeon-gluon NLO vertex [5]. Apart from a colour coefficient this part is also universal. It was found in Refs. [6,7] for the quark and gluon contributions, respectively. Each of last two parts for any R can be presented as a linear combination of two independent pieces, one of which can be determined by the antisymmetric colour octet representation R = 8a (we shall call it gluon channel) and the other by the colour singlet representation R = 1 (Pomeron channel). For the case of quark–antiquark production both these pieces are known [6]. Instead, only the piece related to the gluon channel is known for the case of two-gluon production [7]. ✩ Work supported in part by the Ministero Italiano dell’Istruzione, dell’Università e della Ricerca, in part by INTAS and in part by the Russian Fund of Basic Researches. E-mail addresses:
[email protected] (V.S. Fadin),
[email protected] (R. Fiore).
0370-2693/$ – see front matter 2005 Elsevier B.V. All rights reserved. doi:10.1016/j.physletb.2005.01.062
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The only missing piece of the non-forward kernel was then the two-gluon production contribution in the Pomeron channel. We have calculated this contribution and therefore have solved the problem of finding the nonforward kernel at NLO for an arbitrary colour state in the t-channel. Details of the calculation will be given elsewhere. Here we present the NLO kernel for the most important Pomeron channel. Note that for the case of the scattering of physical (colourless) particles only the Pomeron channel exists. Since the quark contribution to the non-forward kernel is known [6] for any R, we shall consider in the following only the gluon contribution, i.e., pure gluodynamics. Making use of the conventional dimensional regularization with the space–time dimension D = 4 + 2, the BFKL equation for the Mellin transform of the Green’s function of two Reggeized gluons in the t-channel is written as d D−2 r q1 − q2 ) + K( q1 , r; q)G(r , q2 ; q), ωG( q1 , q2 ; q) = q12 q1 2 δ (D−2) ( (1) r2 (r − q)2 where qi and qi ≡ qi − q (i = 1–2) are the Reggeon (Reggeized gluon) momenta, q q⊥ is the total t-channel 2 = − momentum, q 2 q⊥ q 2 = t and the vector sign is used for denoting the components of momenta transverse to the plane of initial momenta. The kernel 2 2 2 (D−2) 2 q1 q1 q1 δ q1 + ω − ( q1 − q2 ) + Kr ( q1 , q2 ; q) K( q1 , q2 ; q) = ω − (2) is given by the sum of the “virtual” part, determined by the gluon Regge trajectory ω(t) (actually the trajectory is j (t) = 1 + ω(t)), and the “real” part, related to particle production in Reggeon–Reggeon collisions. In the limit → 0 we have [4] −t 2 1 + ln 2 ω(t) = −2g¯ µ µ 1 −t 11 1 67 404 2 −t − 2ζ (2) + 2 ln + 2ζ (3) . − g¯ µ4 (3) − ln + − 3 2 9 27 µ2 µ2 Here g¯ µ2 =
gµ2 Nc (1 − ) (4π)2+
,
(4)
where gµ is the renormalized coupling in the MS scheme, Nc is the number of colors, (x) is the Euler function and ζ (n) is the Riemann zeta function, (ζ (2) = π 2 /6). The remarkable properties of the “real” part of the kernel, which follow from general arguments, are q1 , 0; q) = Kr ( q , q2 ; q) = Kr ( q1 , q; q) = 0 Kr (0, q2 ; q) = Kr (
(5)
Kr ( q1 , q2 ; q) = Kr (− q1 , − q2 ; q) = Kr (− q2 , − q1 ; − q ).
(6)
and
The properties (5) imply that the kernel turns into zero at zero transverse momenta of the Reggeons and appear as consequences of the gauge invariance; in turn the properties (6) are the consequence of cross-invariance. In pure gluodynamics the “real” part Kr is given by the sum of one-gluon- and two-gluon-production contributions. The first of them differs from the corresponding contribution in the gluon channel only by a colour group coefficient. As for the second one, it occurs to be much more complicated in the Pomeron channel than in the gluon one. The simplicity of the gluon channel is related to the gluon Reggeization. Technically it is determined by the cancellation of contributions of non-planar diagrams due to the colour group algebra. The complexity of contributions of non-planar diagrams is well known since the calculation of the non-forward kernel for the QED Pomeron [8] which was found only in the form of a two-dimensional integral. In QCD the situation is greatly worse because
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of the existence of cross-pentagon and cross-hexagon diagrams in addition to QED-type cross-box diagrams. It requires the use of additional Feynman parameters. At arbitrary D no integration over these parameters at all can be done in elementary functions. It occurs, however, that in the limit → 0 the integration over additional Feynman parameters can be performed, so that the result can be written as a two-dimensional integral, as well as in QED. Let us present the kernel Kr in the limit D = 4 + 2 → 4 as sum of two parts: sing
Kr = Kr
(reg)
+ Kr
.
(7)
Here the first contains all singularities: sing
Kr
( q1 , q2 ; q) =
q12 q2 2 + q1 2 q22 2 − q π 1+ (1 − ) k2
2
11 67 k 404 11 2 11 − + × 1 + g¯ µ + − 2ζ (2) + − + 14ζ (3) + ζ (2) , 3 3 9 27 3 µ2 (8) 2g¯ µ2 µ−2
where k = q1 − q2 = q1 − q2 . The second, putting = 0 and g¯ µ2 = αs (µ2 )Nc /(4π), is given by αs2 (µ2 )Nc2 2 50 reg 2 2 Kr ( q1 , q2 ; q) = 2 q1 + q2 − q ζ (2) − 9 16π 3 2 2 2 2 2 q2 q 2 − q22 q1 2 q1 q q q q 11 2 + q22 ln 2 − q2 ln 1 2 − 1 2 q1 ln ln 12 − 3 q2 k2 k2 k4 k2 2 2 2 2 2 q q q q q 1 + q2 ln 12 ln 12 + ln 22 ln 22 + ln2 12 2 q q q q q2 2 2 2 2 2 2 2 2 2 q2 q1 q1 q q1 q2 q1 q2 + q2 q1 2 ln ln + ln 2 ln 12 − − 2 2 2 2 2 q2 q2 2k k k 2 2 2 2 2 2 2 2 q (3 q − 3 q2 ) q1 − q2 ) q ( k k ln 2 + 2 ln 2 + 1 1 2 2 q2 q1 2k 2k 2 2 2 ( q − q2 )( q1 + q22 )( q1 2 − q2 2 ) + q 2 k2 − q12 − q22 + 2 q12 q22 − 1 2k2 2 k 2 q1 + q2 2 I k2 , q22 , q12 − 2J ( q1 , q2 ; q) − 2J (− + q12 q1 2 + q22 q2 2 − q2 , − q1 ; − q) 2 qi }. + { qi ←→ − (9) In expression (9) two quantities appear, precisely 1 I (a, b, c) = 0
a(1 − x) + bx dx ln a(1 − x) + bx − cx(1 − x) cx(1 − x)
and
2 2 2 Q Q − ln J ( q1 , q2 ; q) = dx dz q1 q1 (2 − x1 x2 ) ln 2 x1 Q20 k 0 0 2 2 1 1 2 x2 q1 q1 p1 ( − x1 x2 q1 − 2 q1 p1 q1 − 2 q1 p2 + q1 − p2 ) − q1 2 q1 p2 2 x1 2Q2 Q 1
1
(10)
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1 2 2 q1 k + (1 − z) + z(1 − z) q2 q1 q1 + q1 z q1 q1 Q20 1 − 2 q1 2 q1 (p1 − 2 q1 ) + 4x1 q12 ( q1 p2 ) + q1 q1 ( q1 q1 − q1 p1 − q1 p2 ) Q q1 p2 ) − 2( q1 p2 )( q1 p1 ) + 2( q1 p1 )( −1 x2 + q1 2 2 q2 p2 ) q1 p2 ) q1 k + x2 ( q1 p2 ) q22 − k2 + 2( q1 q 2 ( µ2 Q2 x1 2 x2 Q2 Q0 q1 ( q1 + k) 2 1 1 + 2 2 ( q1 p0 ) q1 k − ln ln − x1 µ0 Q0 x1 p22 µ22 p02 µ20 2 Q 1 1 1 x2 q ln ( q p )( q + k) p − 2 (x q + q ) p p + 2 + 2 1 2 2 2 1 2 2 1 2 1 x1 Q2 p2 p22 µ22 2 2 Q0 (x2 q1 + q2 ) q1 1 1 1 1 Q + 2 + − 2 ln ( q p )( q + k) p ln 1 0 0 1 x1 p0 p02 µ20 Q20 p22 µ22 q12 µ21 µ22 1 1 Q2 1 + + ( q2 p2 )( ( q2 k)( L− L + ( q2 k)( L q2 k) 2 − q2 k) q2 p1 ) 2 − d d d d µ2 µ1 k2 2 ( q2 q2 ) k 1 + ( q2 p2 )( (11) q2 p1 ) L− 2 + L . d 2 Q Here we make use of the following positions: p2 = z (1 − x)k − x q2 + (1 − z)(1 − x) q1 ; q2 , p1 + p2 = k, p1 = zx q1 + (1 − z) x k − (1 − x) 2 2 2 2 2 2 2 2 2 µi = Q + pi , Q = x(1 − x) q1 z + q1 (1 − z) + z(1 − z) q2 x + q2 (1 − x) − q x(1 − x) , q1 ; Q20 = z(1 − z) q2 2 , µ20 = zk2 + (1 − z) q1 2 , p0 = zk + (1 − z) d = µ21 µ22 − k2 Q2 = z(1 − z)x(1 − x) k2 − q12 − q2 2 k2 − q1 2 − q22 + k2 q2 2 2 µ µ L = ln 1 2 . + q12 q22 xz(x + z − 1) + q1 2 q2 2 (1 − x)(1 − z)(1 − x − z), k2 Q2
(12)
Note that the integral I (a, b, c) is invariant with respect to any permutation of its arguments, which can be seen from the representation 1 1 1 I (a, b, c) = 0 0 0
dx1 dx2 dx3 δ(1 − x1 − x2 − x3 ) . (ax1 + bx2 + cx3 )(x1 x2 + x1 x3 + x2 x3 )
(13)
does not change performing the substitution q1 ↔ −q2 . In particular, As far as the quantity J is concerned, its expression (11) is rather cumbersome. Unfortunately, till now our attempts to find a more simple representation for it have been unsuccessful. sing All singularities of Kr are present only in its first part Kr . We recall that the one-gluon- and two-gluonproduction contributions to Kr separately contain first and second order poles at = 0. When summing these two contributions the pole terms cancel, so that at fixed nonzero k2 , when the term (k2 /µ2 ) in expression (8) of the kernel can be expanded in , the sum is finite at = 0. However, expression (8) is singular at k2 = 0 so that, when it is integrated over q2 , the region of so small k2 , such that | ln(k2 /µ2 )| ∼ 1, does contribute. Therefore the expansion of (k2 /µ2 ) is not done in expression (8). Moreover, the terms ∼ are taken into account in the I (k 2 , q22 , q12 )
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coefficient of the expression divergent at k2 = 0, in order to save all contributions non-vanishing in the limit → 0 after integration. (reg) The part Kr is finite in the limit = 0. Moreover, integration of this part in Eq. (1) for the Green’s function does not create singularities at = 0 as well. Indeed, the points r = 0 and r = 0, which at first glance could give the singularities in Eq. (1), are not dangerous because of the “gauge invariance” properties (5) of the kernel Kr . (sing) (reg) It follows from formula (7) that if one of two parts (Kr or Kr ) of the kernel possesses these properties, the (sing) (reg) same is valid for the other. “Gauge invariance” of Kr is evident from expression (8), therefore Kr also turns (reg) into zero at zero Reggeon momenta. It is worthwhile to say that the fulfillment of these properties for Kr can be shown directly using the explicit expression (9), although this is far from to be evident. Nevertheless, it is not As we have already seen, at = 0 divergencies can come from the region of small k. (reg) difficult to check from expression (9) for Kr that non-integrable singularities at k = 0 are absent. The total kernel for the Pomeron channel must be infrared safe. Infrared singularities of Kr must be cancelled by singularities of the gluon trajectory after integration of the total kernel with any function non-singular at k = 0. Indeed, one can easily see that this is the case using Eqs. (3) and (8). It is convenient to present the total kernel in such a form that the cancellation of singularities between real and virtual contributions becomes evident. To this aim let us first switch from the dimensional regularization to the cut-off k2 > λ2 , with λ → 0, which is more convenient for practical purposes. With such regularization we can pass to the limit → 0 in the real part of the kernel, so that for its singular part we get αs (µ2 )Nc q12 q2 2 + q1 2 q22 sing λ 2 Kr ( q1 , q2 ; q) → Kr ( q1 , q2 ; q) = − q 2π 2 k2
2 67 αs (µ)Nc 11 k × 1− (14) ln 2 − + 2ζ (2) θ ( q1 − q2 )2 − λ2 . 4π 3 9 µ The trajectory must be transformed in such a way that the cut-off regularization yields the same result as the regularization does: 2+ 2 1 d q2 (1) 2 K ( q , q ; q )θ λ − ( q − q ) ω(t) → ωλ (t) = lim ω(t) + 1 2 1 2 r →0 2 q22 q2 2
2 −t αs (µ2 )Nc 11 −t αs (µ2 )Nc 2 λ ln 2 − ln2 − ln =− 2π 4π 6 λ µ2 µ2 −t 67 π 2 − ln 2 + 6ζ (3) . − (15) 9 3 λ It is easy to check that by integrating over d 2 q2 any function non-singular for k = 0 with the total kernel (2) sing at ω(t) → ωλ (t) and Kr ( q1 , q2 ; q) → Krλ ( q1 , q2 ; q) one obtains a λ-independent result in the limit λ → 0. Moreover, it is also easy to find a form of the kernel which does not contain λ at all. It is sufficient to find a representation 2 ωλ − (16) q1 = d 2 q2 fω ( q1 , q2 )θ ( q1 − q2 )2 − λ2 with a function fω such that the non-integrable singularities at k = q1 − q2 = q1 − q2 = 0 are cancelled in the “regularized virtual kernel” q1 , q2 ; q) = fω ( q1 , q2 ) + fω ( q1 , q2 ) + Kv ( reg
sing
Kr
( q1 , q2 ; q)|=0 . q22 q2 2
(17)
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After that we can proceed to the limit λ = 0:
sing q1 , q2 ; q)|=0 Kr ( reg 2 ˆ (KΨ )( q1 ) = d q2 Kv ( Ψ ( q2 ) − Ψ ( q1 , q2 ; q)Ψ ( q1 ) + q1 ) 2 2 q2 q2 reg Kr ( q1 , q2 ; q) + Ψ ( q2 ) . q22 q2 2
(18)
Of course, the choice of the function fω contains a large arbitrariness. A simple choice is q12 αs (µ2 )Nc 2π 2 k2 ( q12 + k2 )
2 αs (µ)Nc 11 k 11 k2 67 × 1− ln 2 − + 2ζ (2) + 6ζ (3) − ζ (2) . 4π 3 9 3 µ ( q12 + k2 )
q1 , q2 ) = − fω (
(19)
In a subsequent paper we shall present the results of the investigation of properties of the kernel.
Acknowledgements V.S.F. thanks the Dipartimento di Fisica dell’Università della Calabria and the Istituto Nazionale di Fisica Nucleare—gruppo collegato di Cosenza for their warm hospitality while a part of this work was done.
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