On some new integral inequalities of Gronwall–Bellman–Bihari type with delay for discontinuous functions and their applications

On some new integral inequalities of Gronwall–Bellman–Bihari type with delay for discontinuous functions and their applications

Available online at www.sciencedirect.com ScienceDirect Indagationes Mathematicae xx (xxxx) xxx–xxx www.elsevier.com/locate/indag On some new integr...

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Available online at www.sciencedirect.com

ScienceDirect Indagationes Mathematicae xx (xxxx) xxx–xxx www.elsevier.com/locate/indag

On some new integral inequalities of Gronwall–Bellman–Bihari type with delay for discontinuous functions and their applications✩ Q1

Xiaohong Liu a,∗ , Lihong Zhang b , Praveen Agarwal c , Guotao Wang b a School of Mathematical Sciences, Xiamen University, Xiamen, Fujian 361005, People’s Republic of China b School of Mathematics and Computer Science, Shanxi Normal University, Linfen, Shanxi 041004,

People’s Republic of China c Department of Mathematics, Anand International College of Engineering, Rajasthan, Jaipur 303012, India

Received 31 October 2014; received in revised form 26 June 2015; accepted 5 July 2015 Communicated by H. Woerdeman

1 2

Abstract

3

In this article, some new explicit bounds on solutions to a class of new nonlinear integral inequalities of Gronwall–Bellman–Bihari type with delay for discontinuous functions are established. These inequalities generalize and improve some former famous results about inequalities, and which provide an excellent tool to discuss the qualitative and quantitative properties for solutions to some nonlinear differential and integral equations. To illustrate our results, we present an example to show estimated solutions for an impulsive differential system. c 2015 Published by Elsevier B.V. on behalf of Royal Dutch Mathematical Society (KWG). ⃝

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Keywords: Integral inequalities; Discontinuous functions; Gronwall–Bellman–Bihari type inequalities; Impulsive differential systems

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4 5 6 7 8 9

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✩ This work was supported by the Natural Science Foundation for Young Scientists of Shanxi Province, China (2012021002-3). ∗ Corresponding author. Tel.: +86 15959262015. E-mail addresses: [email protected] (X. Liu), [email protected] (L. Zhang), [email protected] (P. Agarwal), [email protected] (G. Wang).

http://dx.doi.org/10.1016/j.indag.2015.07.001 c 2015 Published by Elsevier B.V. on behalf of Royal Dutch Mathematical Society (KWG). 0019-3577/⃝

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1. Introduction

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Q2

During the past years, a number of efforts have been devoted to the integral inequalities. The celebrated results given by Gronwall, Bellman, Bihari and their linear and nonlinear generalizations in the case of continuous and discontinuous functions provide a fundamental role in the study of many qualitative properties of differential and integral equations, which we can find in [3,6,4,11,12,15–17,2,1,10,9]. For some new development on this topic, see [5,8,13,18,14,19,7]. In 2007, Jiang and Meng [8] discussed the following delay integral inequalities:  t  p x (t) ≤ ρ(t) + π(t) f (s)x q (s) + h(s)x r (σ (s)) ds t0

9

with the initial condition:

10

s(t) = φ(t) t ∈ R+

11

φ(σ (t)) ≤ ρ(t) p

1

12

t ∈ R+ σ (t) ≤ 0

and x (t) ≤ ρ(t) + π(t) p

13

 t

  f (s)x q (s) + L s, x(σ (s))

t0 14 15 16 17 18 19

20

with the same initial condition. Under the assumption of functions x(t), ρ(t), π(t), f (t), h(t) ∈ C(R + , R + ), authors obtained explicit bounds on unknown function x(t) of the above inequalities. The purpose of this paper is to give explicit bounds to some new nonlinear integral inequalities of Gronwall–Bellman–Bihari type with delay for discontinuous functions. Precisely, we consider the following nonlinear integral inequalities:  t   x p (t) ≤ ρ(t) + π(t) f (s)x q (s) + h(s)x r (σ (s)) ds + ai x m (ti − 0) to
t0 21

22

and x p (t) ≤ ρ(t) + π(t)

 t

   f (s)x q (s) + L s, x(σ (s)) + ai x m (ti − 0).

t0

to
25

Our results develop and improve certain results which were proved by Jiang and Meng [8]. At the end of the article, an example of application is presented to show estimated solutions for an impulsive differential system.

26

2. Main results

27

Lemma 2.1 ([8]). Assume that a ≥ 0, p ≥ q ≥ 0 and p ̸= 0, then

23 24

q 28

29

ap ≤

q q−p p p − q qp K a+ K p p

for any K > 0.

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Theorem 2.1. If x(t)(t ≥ t0 ≥ 0) is a nonnegative piecewise continuous function with discontinuities of the 1st kind in the points ti (t0 < t1 < t2 < · · · , limi→∞ ti = ∞) and satisfies the following form of inequality: x p (t) ≤ ρ(t) + π(t)

 t

  ai x m (ti − 0) f (s)x q (s) + h(s)x r (σ (s)) ds +

(2.1)

1 2 3

4

to
t0

where ρ(t), π(t) ≥ 1 are both non-decreasing functions at t ≥ t0 , h(s), f (s) ∈ C(R+ , R+ ), σ (s) ≤ s, lim|s|→∞ σ (s) = ∞, ai ≥ 0, m > 0, p ≥ q ≥ 0, p ≥ r ≥ 0. Then, for t ≥ t0 , the following estimates hold: t  1 t0 Q(s)ds p  ρ(t)π(t)A(t)e , t ∈ I0 = [t0 , t1 ]     t  1   Q(s)ds p   , t ∈ I1 = [t1 , t2 ] ρ(t)π(t)[M2 (t) + A1 L 2 (t)]e t1     ti     s Q(τ )dτ x(t) ≤ ρ(t)π(t) M (t) + Q(s) M (s) + A L (s) e ti−1 ds i i i−1 i   t i−1   1  t  m  t  p   ti−1 Q(s)ds p ti Q(s)ds  e , +Ai (Mi (t) + Ai−1 L i (t))e    t ∈ Ii = [ti , ti−1 ]

(2.2)

where

5 6 7

8

9

A(t) = 1 +

 t

f (s)

t0 m p

p − r rp  p − q qp K + h(s) K ds, p p

m

Ai = ai ρ (ti − 0)π p (ti − 0), q q− p r r−p Q(t) = K p f (t)π(t) + K p h(t)π(t), p p  t1 s Q(τ )dτ M2 (t) = A(t) + Q(s)A(s)e t0 ds,

t  m Q(s)ds p , L 2 (t) = A(t)e t0

(2.3)

10

t0

Mi (t) = Mi−1 (t) +



ti

   s Q(τ )dτ Q(s) Mi−1 (s) + Ai−2 L i−1 (s) e ti−1 ds

(i > 2),

ti−1 t  m Q(s)ds p L i (t) = (Mi−1 (t) + Ai−2 L i−1 (t))e ti−2

(i > 2).

Proof. Being ρ(t) ≥ 1, we have  t  x p (t) x q (s) x r (σ (s))  ≤ 1 + π(t) f (s) + h(s) ds + ai x m (ti − 0). ρ(t) ρ(t) ρ(t) t0 to
11

12

Considering ρ(t) a non-decreasing function, for s ≤ t, we get ρ(s) ≤ ρ(t), then: x p (t) ≤ 1 + π(t) ρ(t)

 t t0

f (s)

 x q (s) x r (σ (s))  + h(s) ds + ai x m (ti − 0). ρ(s) ρ(s) to
13

(2.4)

14

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By setting u(t) = 

x p (t) ρ(t)

u(t) ≤ π(t) 1 +

2

, we can see u(t0 ) = 1 and there is

 t t0

3

ω(t) = 1 +

 t

f (s)

t0

8

9

It is obvious that x p (t) ≤ π(t)ω(t). ρ(t) This means that x p (t) ≤ ρ(t)π(t)ω(t). The above inequality implies the estimation for x(t) such as  1 p x(t) ≤ ρ(t)π(t)ω(t)

12

13

14

 1 p x(ti − 0) ≤ ρ(ti − 0)π(ti − 0)ω(ti − 0) .

16

17

By Lemma 2.1, for any K > 0, we obtain

18

19

20

21

22

 q  p−q q q q− p  p x q (t) ≤ ρ(t)π(t)ω(t) ≤ K p ρ(t)π(t)ω(t) + Kp p p  r  p−r r r r−p  p x r (t) ≤ ρ(t)π(t)ω(t) ≤ K p ρ(t)π(t)ω(t) + K p. p p It follows from (2.7) and (2.8) that  t  q q− p   p−q q Kp ω(t) ≤ 1 + f (s) K p π(s)ω(s) + p p t0  r r−p   p−r r  + h(s) K p π(s)ω(s) + K p ds p p  m  m  p p + ai ρ(ti − 0)π(ti − 0) ω(ti − 0) to
23

(2.7)

and

Noting σ (s) ≤ s, then          1  1 p p x σ (s) ≤ ρ σ (s) π σ (s) ω σ (s) ≤ ρ(s)π(s)ω(s) .

15

(2.6)

u(t) ≤ π(t)ω(t).

10

11

 x q (s) x r (σ (s))  ai x m (ti − 0). + h(s) ds + ρ(s) ρ(s) to
Using (2.6) in (2.5), we obtain

6

7

(2.5)

Denote

4

5

   x q (s) x r (σ (s)) m ai x (ti − 0) . f (s) ds + + h(s) ρ(s) ρ(s) to
= 1+

t0

 − q qp p − r rp K f (s) + K h(s) ds p p

(2.8)

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 t  r r−p q q−p p f (s)π(s) + K p h(s)π(s) ω(s)ds K + p t0 p  m  m  p p ai ρ(ti − 0)π(ti − 0) + ω(ti − 0) .

1

(2.9)

2

to
Set

3

 t  p − q qp p − r rp A(t) = 1 + K f (s) + K h(s) ds p p t0 q q−p p r r −p p Q(t) = K f (t)π(t) + K h(t)π(t) p p  m p Ai = ai ρ(ti − 0)π(ti − 0) . Then (2.9) can be restated as  t  m Q(s)ω(s)ds + Ai [ω(ti − 0)] p . ω(t) ≤ A(t) +

(2.10)

4

5

(2.11)

6

to
t0

Let us consider Ii = [ti , ti+1 ](i = 0, 1 · · ·). For t ∈ I0 ,  t t Q(s)ds ω(t) ≤ A(t) + Q(s)ω(s)ds ≤ A(t)e t0 .

7 8

(2.12)

9

t0

It is obvious that t  1 Q(s)ds p . x(t) ≤ ρ(t)π(t)A(t)e t0

10

11

Now let us consider the next interval I1 . For t ∈ I1 , we have  t  m p ω(t) ≤ A(t) + Q(s)ω(s)ds + A1 ω(t1 − 0) t0  t1

s

≤ A(t) +

Q(s)A(s)e

t0

Q(τ )dτ



t

ds +

t0

12

13

t  m Q(s)ds p Q(s)ω(s)ds + A1 A(t)e t0

14

t1 t1

  ≤ A(t) +

s

Q(s)A(s)e

t0

Q(τ )dτ

t  m  t Q(s)ds p Q(s)ds ds + A1 A(t)e t0 e t1 .

(2.13)

15

t0

By setting M2 (t) = A(t) +

16



t1

s

Q(s)A(s)e

t0

Q(τ )dτ

ds

17

t0 t  m Q(s)ds p L 2 (t) = A(t)e t0 .

Therefor for the interval I1 , we see t  1 Q(s)ds p x(t) ≤ ρ(t)π(t)[M2 (t) + A1 L 2 (t)]e t1 .

18

Q3

19

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Consider the next interval I2 , we have  t  m p ω(t) ≤ A(t) + Q(s)ω(s)ds + A2 ω(t2 − 0) t0 t1

 3

s

≤ A(t) +

Q(s)A(s)e

t0

Q(τ )dτ

ds +

t0



t

+

4

t2



Q(s)[M2 (s) + A1 L 2 (s)]e

s t1

Q(τ )dτ

ds

t1

t m  Q(s)ds p Q(s)ω(s)ds + A2 [M2 (t) + A1 L 2 (t)]e t1

t2 5

≤ M2 (t) +



t2

Q(s)[M2 (s) + A1 L 2 (s)]e

s t1

Q(τ )dτ

ds

t1



t

+

6

t  m Q(s)ds p . Q(s)ω(s)ds + A2 [M2 (t) + A1 L 2 (t)]e t1

(2.14)

t2 7

8

Thus, we have  ω(t) ≤

M2 (t) +



t2

  s Q(τ )dτ Q(s) M2 (s) + A1 L 2 (s) e t1 ds

t1

9

10 11 12

13 14

15

+ A2



m  t p t1 Q(s)ds M2 (t) + A1 L 2 (t) e



t

e

t2

17

.

(2.15)

 1 p Taking into account x(t) is such that x(t) ≤ ρ(t)π(t)ω(t) , ∀t ≥ t0 , from inequalities (2.15), we can see for t ∈ I2 estimates (2.2) are valid for x(t). Consequently, by using a similar procedure for t ∈ Ii , we complete the proof of Theorem 2.1.  Theorem 2.2. Assume that x(t), ρ(t), π(t), σ (t) are defined in Theorem 2.1 and x(t) satisfies the following form of integral inequality  t    f (s)x q (s) + L s, x(σ (s)) + ai x m (ti − 0) (2.16) x p (t) ≤ ρ(t) + π(t) t0

16

Q(s)ds

to
2 , R ) satisfying where p ≥ q ≥ 1, m ≥ 0 and L , M ∈ (R+ +

0 ≤ L(t, x) − L(t, y) ≤ M(t, y)(x − y)

18

for x ≥ y ≥ 0, then the inequality (3.1) with the initial condition in Theorem 2.1 implies

19

t  1 ˜ t0 Q(s)ds p  ˜ ρ(t)π(t) A(t)e , t ∈ I0 = [t0 , t1 ]        t ˜ 1   Q(s)ds p   ρ(t)π(t) M˜ 2 (t) + A˜1 L˜2 (t) e t1 , t ∈ I1 = [t1 , t2 ]     ti    s ˜ ˜ i (t) + ˜ ˜ i (s) + Ai−1 ˜ L˜i (s) e ti−1 Q(τ )dτ ds x(t) ≤ ρ(t)π(t) M Q(s) M   ti−1   1  t  m  t ˜  p ˜   ti−1 Q(s)ds p t1 Q(s)ds ˜ ˜ ˜ ˜  + A ( M (t) + A L (t))e e , i i i−1 i    t ∈ Ii = [ti , ti−1 ]

(2.17)

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where

1

 t  p − q qp p − r rp ˜ =1+ K f (s) + K h(s) ds, A(t) p p t0  m p A˜i = ai ρ(ti − 0)π(ti − 0) q q− p r r−p ˜ Q(t) = K p f (t)π(t) + K p h(t)π(t) p p  t1 s ˜ t0 Q(τ )dτ ˜ + ˜ A(s)e ˜ M˜ 2 (t) = A(t) Q(s) ds

(2.18)

t m  ˜ t0 Q(s)ds p ˜ L˜2 (t) = A(t)e

2

t0

˜ (t) + M˜ i (t) = Mi−1

ti



  s ˜ ˜ ˜ (s) + Ai−2 ˜ L i−1 ˜ (s) e ti−1 Q(τ )dτ ds Q(s) Mi−1

ti−1



˜ (t) + Ai−2 ˜ L i−1 ˜ (t))e L˜i (t) = ( Mi−1

t ti−2

 ˜ Q(s)ds

m p

.

Proof. Being ρ(t) ≥ 1 a non-decreasing function, the following inequality holds:  t    x q (s) x p (t) ≤ 1 + π(t) f (s) + L s, x(σ (s)) ds + ai x m (ti − 0) ρ(t) ρ(s) t0 to
3

4

(2.19)

Denote

5

Q4

ω(t) ˜ =1+

 t

f (s)

t0

x q (s) ρ(s)

  + L(s, x(σ (s))) ds + ai x m (ti − 0)

6

7

to
it is obvious that  1 p x(t) ≤ ρ(t)π(t)ω(t) ˜

8

(2.20)

1 p x(ti − 0) ≤ ρ(ti − 0)π(ti − 0)ω(t ˜ i − 0) .

9



By Lemma 2.1, we obtain  q  p−q q p x q (t) ≤ ρ(t)π(t)ω(t) ˜ ρ(t)π(t)ω(t) ˜ + ≤ p p

10

11

and

12

 1  p−1 1 p x(t) ≤ ρ(t)π(t)ω(t) ˜ ≤ ρ(t)π(t)ω(t) ˜ + . p p

13

Then there is

Q5

q p−q ρ(s)π(s)ω(s) ˜ π(s)ω(s) ˜ + ds + L s, + p p p t0 t0  m  m  p p + ai ρ(ti − 0)π(ti − 0) ω(t ˜ i − 0)

ω(t) ˜ ≤ 1+



t

f (s)

to






t



p − 1 p

ds

14

15

16

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X. Liu et al. / Indagationes Mathematicae xx (xxxx) xxx–xxx

 t  q ρ(s)π(s)ω(s) ˜ p−q p − 1 ˜ + ds + L s, + ds f (s) π(s)ω(s) p p p p t0 t0  t   t  p − 1 p − 1 − ds + ds L s, L s, p p t0 t0  m  m p + ai ρ(ti − 0)π(ti − 0) [ω(t ˜ i − 0)] p 

t

= 1+

1

2

3

to
 t  q p−q p − 1  ρ(s)π(s)ω(s) ˜ ≤ 1+ f (s) π(s)ω(s) ˜ + ds ds + M s, p p p p t0 t0 m  m   p p + ai ρ(ti − 0)π(ti − 0) ω(t ˜ i − 0)

4

5

to
 t  p − 1  ρ(s)π(s)  p−q q = 1+ f (s) ds + f (s)π(s) + M s, ω(s)ds ˜ p p p t0 t0 p  m  m p + ai ρ(ti − 0)π(ti − 0) [ω(t ˜ i − 0)] p . (2.21)

6

7

to
8

9

10

11

12

13

Setting in the last inequality  t p−q ˜ A(t) = 1 + f (s)ds p t0  m p A˜i = ai ρ(ti − 0)π(ti − 0)  p − 1  ρ(t)π(t) q ˜ Q(t) = f (t)π(t) + M t, p p p we obtain ˜ + ω(t) ˜ ≤ A(t)



t t0

˜ ω(s)ds Q(s) ˜ +

 to
 m p A˜i ω(t ˜ i − 0) .

14

Thus, we get the similar form of inequality (2.11) in Theorem 2.1, we complete the proof.

15

3. Example

16

17

18 19

20 21 22

As an application, when p = 1, let us consider the following impulsive system:  dy   = u(y, t) + v(y, t) t ̸= ti dt 1y| = Ii (y)   +t=ti y(t0 ) = y0 when t ≥ t0 ≥ 0, limi→∞ ti = ∞, ti−1 < ti , i = 1, 2, . . . . Suppose that u(y, t), v(y, t) and Ii (y) satisfy the nonlinearity conditions: (a) ∥u(y, t)∥ ≤ f (t)∥y∥q f : R+ → R+ ; (b) ∥v(y, t)∥ ≤ h(t)∥y∥r h : R+ → R+ ; (c) ∥Ii (y)∥ ≤ ai ∥y∥m , ai = const. > 0, m > 0.

(2.22) 

(3.1)

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X. Liu et al. / Indagationes Mathematicae xx (xxxx) xxx–xxx

Denote y(t) = x(t, t0 , y0 ) the solution for (3.1), so that y(t) = y(t, t0 , y0 )(y(t0 ) = y0 ), it is obvious that its integro-sum representation is the following:  t  t y(t, t0 , y0 ) = y0 + u(s, y(s, t0 , y0 ))ds + v(s, y(s, t0 , y0 ))ds t0 t0  Ii (y(ti − 0, t0 , y0 )). +

1 2

3

4

to
Thus, (3.1) is equivalent to the above equation. By using conditions (a), (b) and (c), it is easy to have:  t  t ∥y(t, t0 , y0 )∥ ≤ ∥y0 ∥ + f (s)∥y(s, t0 , y0 )∥ds + h(s)∥y(s, t0 , y0 )∥ t t0  0 + ai ∥y(ti − 0, t0 , y0 )∥m .

5 6

7

8

to
Set x(t) = ∥y(t, t0 , y0 )∥, we obtain the particular case of integro-sum inequality (2.1):  t   x(t) ≤ ∥y0 ∥ + f (s)x q (s) + h(s)x r (s) ds + ai x m (ti − 0)

9

10

to
t0

if in (2.1) p = 1, ρ(t) = ∥y0 ∥, π(t) = 1, τ (s) = s. Therefore, we get the estimated solutions for impulsive system:

11 12

t  Q(s)ds  ∥y0 ∥A(t)e t0 , t ∈ I0 = [t0 , t1 ]   t   t Q(s)ds  ∥y0 ∥[M2 (t) + A , t ∈ I1 = [t1 , t2 ]  1 L 2 (t)]e 1        s Q(τ )dτ ti ∥y(t, t0 , y0 )∥ ≤ ∥y0 ∥ Mi (t) + Q(s) Mi (s) + Ai−1 L i (s) e ti−1 ds  ti−1  t t      m Q(s)ds  Q(s)ds  +Ai (Mi (t) + Ai−1 L i (t))e ti−1 e ti ,    t ∈ Ii = [ti , ti−1 ]

(3.2)

where

13

14

A(t) = 1 +

 t

 (1 − q)K q f (s) + (1 − r )K r h(s) ds,

f (t) + r K r −1 h(t),  t1 s Q(τ )dτ ds, Q(s)A(s)e t0 M2 (t) = A(t) + Q(t) = q K

Ai = ai ∥y(t, t0 , y0 )∥,

t0 q−1

t   Q(s)ds m , L 2 (t) = A(t)e t0

t0

Mi (t) = Mi−1 (t) +



ti

   s Q(τ )dτ Q(s) Mi−1 (s) + Ai−2 L i−1 (s) e ti−1 ds

(3.3)

15

(i > 2),

ti−1 t   Q(s)ds m L i (t) = (Mi−1 (t) + Ai−2 L i−1 (t))e ti−2

(i > 2).

References [1] R.P. Agarwal, Difference Equation and Inequalities: Theory, Methods and Applications, New York, 1992. [2] R. Bellan, K.L. Cooke, Differential-Difference Equations, Academic Press, New York, 1963.

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