..., x,)). Let II = <:.v,,..., s,). Since I(G/Z,)’ / .< p”, each element of G/Z, has at most p71 conjugates and so, if U/Z, = C,,,,(NZJZ,), then jG: Uj
inverts a group,
if it inverts
LEMMA 2.2. Let G beafinite p-group admitting an involutory automorphism LY. IfG L--:[G, a], then a:inverts ~,(G)/Y+~(G) if i isodd, and centralizes~(G)/Y~+~(G) if i is even.
Proof. We may assume G #- 1, in which we see [Xl ,..., hence [Xl ,..., The p-group.
case p + 2. Since G -=: [G, a], that 01inverts G/y,(G). If xi ,..., xi E G, then the coset of the commutator xi] modulo yiT1(G) depends only on the cosets of xi ,..., Xi mod G’ and mod yi+i(G) we have [xi ,..., xi]” 7-1 [xi” ,..., .qa] :+ [XL’ ,..., A-;‘] F xi]t-I)‘, from which the assertion follows. next lemma deals with the special case of the theorem when G is a When p + 2, notice that we obtain an explicit bound.
I,EMMA 2.3. Let G be a jnite p-group admitting an involutory automorphism cywith / Co(o)1= p”l. Then
(i) If p # 2, G contains an a-invariant subgroupof nilpotency classat mosttwo and index at mostpfW, wheref2(m) == la $ 22 -j- .** + m2. (ii) If p == 2, then G containsan o-invariant abelian subgroupof index at most2fJnr), wheref3(m) is a certain integer-valuedfunction.
Proof. (i) We use induction on m. If m = 0 then a! operates fixed point freely on G, and so G is abelian. Thus we may put f*(O) = 0. Now suppose that m > 0 and the statement has been proved for smaller values. If G > [G, a], then by Lemma 1.l(ii) we have I G : [G, a]1 := pi, where 0 < i < m, and for G, = [G, a] we have ] Ccl(~)1 = P”‘--~. By induction, G, contains an or-invariant subgroup of nilpotency class at most two and index at most pfkJm .
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Kow suppose that G [G, a]. Supp osc that G has nilpotency class t, and put s = t if t is odd, or s =I t J- 1 if t is even. Then, by Lemma 2.2, a inverts ys(G). We may suppose that s :l 1, and hence WC may choose an element .v E rs-i(G)\rz(G) such that xv E rJ(G). By Lemma 2.2, (Y centralizes subgroup of G. r,-l(G)lrs(G), and so H ---=
Finally, f.(m - 1) + m : j(j - 1) < fa(m - 1) + m + m(m f2(m - 1) 7 m* - fa(m), and so 1’ is the subgroup sought.
1) =
(ii) Here G is a 2-group, and by forming the semidirect product G(a), we can suppose that OLis an involution in G. Let A be a maximal abelian normal subgroup of G. If A, = Q,(A) = {a E A : a2 = I}, then thinking of A, as a vector space over the field of two elements and (Y as a linear transformation - 1) of A, > we have (a - I)* = (Y? - 2cr $- 1 = 0. Hence the map a+a(a. determines an embedding of AliCA1(a) into C,L((Y), and we have 1 A, 1 < Pm. Therefore A has rank at most 2~2, that is, .4 is a direct product of at most 2m cyclic groups. By Lemma 1.1(i), 1 A : [A, a]1 .< 2”‘, and so [A, a] 3 B = {Us”: a E A}. If w E A, then clearly cy inverts W-W --: [w, x]. Hence (Y inverts B. Since the inverting automorphism lies in the centre of the automorphism group of every abelian group, we find that [G, LY] centralizes B. By Lemma 1.1, C,(B), which contains [G, or], has index at most 2” in G. Since A/B has bounded rank and bounded exponent, its order is bounded in terms of m, and hence its centralizer in G has bounded index. Thus G contains a subgroup U of bounded index which centralizes both A/B and B. Hence U/C,(A) is isomorphic to a subgroup of Hom(A/B, B). This is because, if II E U, the map T,,: a + [u, u] is a homomorphism of A into B which induces one of A/B into B, and the map u--f 7” is the desired embedding. Now A/B is a direct product of at most 2m cyclic groups of orders dividing 2”‘, and B has rank at most 2m, and hence ) Hom(AIB, B)I = 1Hom(A/B, Q,,,(B))1 is at most 2.iff13.Hence I U : C,(A)1 is bounded by a function of m. Since A is a maximal abelian normal subgroup of G, C,(.4) 3.; 4, and hence I G : .4 is bounded in terms of m.
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COROLLARY 2.4. Let G be a finite nilpotent group admitting an involutory automorphismLX,and let ( Co(a)1 : = m. Then G has an cu-invariant subgroupof nilpotency classat mosttwo and index boundedby a function of m.
Proof. We note that if p is any prime not dividing m, then (Y operates fixed point freely on the Sylow p-subgroup G, of G, and so G, is abelian. I,emma 2.3 then gives the result. 1Ve should remark for completeness that in the situation of the corollary, there need not be an abelian subgroup of bounded index. This is because an cy of extraspecial group P of order p2”i-l (p #: 2) admits an automorphism order two which inverts the Frattini factor group; thus 1 C,(a)1 =p, while k may be arbitrarily large.
3. GENERAL We need the following
simple
CASF
representation-theoretic
lemma:
LEMMA 3.1. Let G = A(u) be the semidirectproduct of a $nite abelian normal subgroupA by a cyclic group (u) of prime order q. Let k be a jeld and V a kc-module, ofjnite dimensionover k, suchthat I’ : [I’, [A, u]]. Thendim, V r q dim, C,,(u). Proof. If k is any extension field of k and Y = v Ok k, then C,(u) :.C,(u) @k k. This well known fact is proved by writing v = $&o V @ w, where a is a k-basis for k Hence we may assume that k is algebraically closed. Let p :? 0 be the characteristic of k, and write A = P x Q, where P is the Sylow p-subgroup of .4 and Q the Sylow p’-subgroup; put P =: 1 and Q 1 A if p 0. We claim that I’ = [V, [Q, u]]. For [I’, [Q, u]] is a KG-submodule of I’. If it is proper, then it is contained in a maximal submodule W of I/. The irreducible module I,‘/ W is trivial for P and for [Q, a] and hence for [A, u] = [P, u] x [Q, u]. Hence [V, [A, u]] < W, contrary to the hypothesis. Thus we indeed have I - = [I;, [Q, u]], and by considering Q(u> instead of G, we may assume that A is a p’-group. Then I’, is completely reducible, and W [II’, [,4, u]] for any kA-submodule W of I,-. Sow cvcry irreducible kG-module X such that X = [X, [A, u]] is induced from .4 and so has dimension q. For if X, is an irreducible A-submodule of X, then the stabilizer of X, is .-I, since otherwise X,, is homogenous, A acts on it by scalar multiplication and [.4, u] is trivial on X. Clifford’s Theorem then shows that X is induced from A, as claimed. It follows from this that if T is any irreducible k-4-submodule of r, so that dim, T = 1, then ?’ 3 Tu (+ ... 5; Tu’ ’ is an irreducible KG-submodule. Therefore I’ is a sum of irreducihlc KG-modules, each induced from A, and must be the direct sum of a collection of them. Each of thcsc contributes one to dim,: C,(U), and the result follows.
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Proof of theorem. By the remarks following the statement of the theorem, we need to consider a finite soluble group G admitting an involutory automorphism (Ysuch that ! C,(a)1 = m, and have to show that G contains a nilpotent subgroup of classat most two and index bounded by a function of m. Let F(G) denote the Fitting subgroup of G and F,(G)/F(G) = F(G/F(G)). By Corollary 2.4, it sufficesto bound 1G : F(G)l. If e = G/F(G), thenF,(G) = C&@j) [4, 111.4.21and so it suffices to bound jF,(G)l. Hence we may assumethat G z=zF,(G). By Lemma 1.1(i), [ Cc(ct)l < m, and as c is now nilpotent, Corollary 2.4 gives us an a-invariant subgroup R ==:If/F(G) of (7, of nilpotency class at most two and index bounded by a function of m. Since F(G) = F(H), we may assumethat G -: H, so that G is nilpotent of classat most two. Let z :; Z/F(G) be the centre of G. Then e/Z is abelian and if G, = [G, LY]Z,then OLinverts every element of G,/Z, and Lemma 1.1(i) shows that I G : G, ) < m. Let 2 = A/F(G) be a maximal abelian normal subgroup of G, == GJF(G). Then G, 3 A 3 Z, and so A is a-invariant. Also 2 3 Ccl(A), and so bounding 12 I will bound : c1 1and hence c 1.Therefore we may assumethat (? is abelian, and since01inverts [c, 011, Lemma 1.1(i) allowsus to even assumethat (Yinverts %. Now let G, be the semidirect product G2 = G(+. Then F(G) ==F(G,) n G and so it suffices to show that 1G, : F(G&I is bounded. To this end, we can assumethat the Frattini subgroup of G2 is trivial [4, 111.4.21.Hence F(G,) is a direct product of minimal normal subgroupsof G, [4, 111.4.51,and so is F(G). Let W be such a minimal normal subgroup which is not centralized by [G, a]. We can view Was an irreducible KF-module, where k is a suitable finite prime field and F = G.JF(GJ, which is the split extension of an abelian normal subgroup B = GF(GJF(G,) g G/F(G) inverted by an involution which we may denote by a. If WI is any irreducible B-submodule of W, then B/C,( WI) is cyclic and C,(W,) 4 B(a). Since W = W, -i- Wla, we find that C,( WI) = C,(W), and so F/C,(W) IS . a dihedral group. We have [W, [B, a’JJ # 0 by hypothesis, and so W = [W, [B, a]] as W is irreducible. By Lemma 3.1, ( CW(~)!2= ( W i. Hence, if IV* is the product of all minimal normal subgroups like W, we have \ W* l2 = i C,+,.(a)!” ,< m2. Hence I[G, a] : C,,.,,(W*)( is bounded by a function of m. But CI,,,~( W*) = : Crc.~l(F(G)), clearly, and this is contained in F(G). Hence ([G, a]F(G)/F(G)I is bounded, and by a final application of Lemma I.l(i), we find that 1G/F(G)] is bounded.
REFERENCES BLACKBERN A?*‘D B. HIJPPERT, “Finite Groups II.” Springer-Verlag, Heidelberg/New York, to appear. 2. R. BRAUER AND K. FOWLER, On groups of even order, Ann. of Math. 62 (1955), 3. P. FONG, On orders of finite groups and centralizers of p-elements, Osahn 13 (1976), 483-489. 1. N.
Berlin/ 565-583. J. Math.
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4. R. H~wrenr,
OF
“Endliche Gruppen I.” Springer-Verlag, Berlin;‘New AND B. A. F. WEHRFRITZ, “Locally Finite Groups,” Amsterdam, 1973. 6. V. P. %JKOV. On periodic groups with an almost regular involution, I1 (1972), 470-493 (Russian); Algebra and Logic I I (1972), 26&272 5. 0.
H.
KECEL
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York, 1967. North-Holland, Algebra i Z.ogika (English).
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