Smooth invariant curves of singularities of vector fields on ℝ3

Smooth invariant curves of singularities of vector fields on ℝ3

Ann. lnsl. Henri Vol. 3, n° Poincare, 2, 1986, p. 111-183. mooth invariant curves of singularities of vector fields on R3 Patrick BONCKA...

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Ann. lnsl. Henri

Vol.

3,



Poincare,

2, 1986,

p. 111-183.

mooth invariant

curves

of

singularities

of vector fields

on

R3

Patrick BONCKAERT Limburgs

Universitair

B-3610

centrum,

universnaire

campus,

Diepenbeek (Belgium)

We describe singularities of Coo vector fields, mainly ABSTRACT. in ~3, in the neighbourhood of a given « generalized » direction (this is : the image of a Coo germ y : ([R + , 0) - (~3, 0) with y’(o) ~ 0). It is a local study. One of the major results is : if X is a germ in 0 E f~ 3 of a C~° vector field and if X is not infinitely flat along a direction D then there exists a cone of finite contact around D in which four specific situations can occur. In three of these situations D is formally invariant under X (with formally we mean : up to the level of formal Taylor series) and there exists a Coo one-dimensional invariant manifold having infinite contact with D. In particular, we obtain that the existence of a formally invariant direction D always implies the existence of a « real life » invariant direction having infinite contact with D, provided that X is not infinitely flat along D. Using the blowing up method for singularities of vector fields we reduce a singularity always to either a « flow box » or to a singularity with nonzero I-jet and with a formally invariant direction. Finally we give topological models for the obtained situations. I would like to thank Freddy Dumortier for suggesting me the problem and for his valuable help. -

RESUME. dans [R3 au

Nous decrivons les singularites de champs de vecteurs Cx voisinage d’une « direction » donnee, c’est-a-dire de l’image

-

Liste de mots-cles : Vector Field.

Singularity. Invariant Manifold. Classification AMS : 34C05 Ordinary Differential Equations. Qualitative Theory. Location of integral curves, singular points, limit cycles. Analyse non linéaire 86/02.111 / 73 S 9,301 ç Gauthier-Villars

Annales de l’Institut Henri Poincaré -

Vol.

3. 0294-1449

2

?. BONCKAERT

(R3, 0),

avec 03B3’(0) ~ 0. C’est une étude locale. si particulier que X est le germe a l’origine d’un champ C" ;i X n’est pas plat dans une direction D, alors il existe un cone de contact ~rdre fini autour de D ou quatre situations distinctes peuvent se produire. ms trois d’entre elles, D est formellement invariant par X et il existe e courbe invariante C~ presentant un contact d’ordre infini avec D. utilisant la methode de blow-up pour les singularites de champs de ~teurs, nous reduisons toutes les singularites soit a un « flow box », t a une singularite au 1-jet non trivial possedant une direction forllement invariante. Enfin, nous fournissons des modeles topologiques ur les diverses situations obtenues.

03B3 : (R+, 0)

m

germe

>us

montrons en

-

,

Je remercie Freddy Dumortier pour m’avoir ur son aide.

I.

suggere

ce

probleme

et

INTRODUCTION, PRELIMINARIES AND STATEMENT OF THE MAIN RESULT

§ 1. Elementary definitions

and useful theorems.

Let X be a vector field on ~n. We (1.1) DEFINITION. s a singularity in p E f~n if X(p) 0. If we only investigate local properties of a singularity in p, ction to put p in 0, the origin. -

say that X

=

it is

no res-

DEFINITION. Two vector fields X and Y on tR" are called germuivalent in 0 if there is a neighbourhood U of 0 on which they coincide,

( 1. 2)

-

DEFINITION. The set of all vector fields on [?" which are germuivalent with X (in 0) is called the germ of X (in 0). In the same way we n define germs in 0 of functions, diffeomorphism,... The germ in 0 of a set A ci {?" is the germ in 0 of its characteristic func>n A germ will often be confused with a representative of it if this

( 1. 3)

-

without

danger.

NOTATION. lds X on ~n with

( 1. 4)

-

Gn denotes the set of all germs in 0 of ex vector 0.

X(0)

=

DEFINITION. Let X, uivalent if their derivatives in 0 up to, and X(0) D’Y(0), Vi, 0 i k.

( 1. 5)

-

X and Y are called k-jet order k are equal:

including,

=

Annales de l’Institut Henri Poincaré -

Analyse

non

linéaire

VECTOR FIELDS ON

!R 3

113

The set of all Y E Gn which are k-jet equivalent It is important to with X E G" is called the k-jet of X and denoted observe that the k-th order Taylor approximation of X in 0 belongs to we often will make no distinction between these two objects. In 1 correspondence between k-jets and vector fields X fact there is a 1 0 and with polynomial component functions of degree k. on [Rn with X(0)

(1.6)

DEFINITION.

-

-

=

(1.7) NOTATION limit of the sets Ji for the

We

mappings nlk : J?

can

take the inverse -

-

jkX(0) (1

>

k).

DEFINITION. This inverse limit is denoted J; its elements called oo-jets; the oo-jet corresponding to is denoted Elements of J~ can be regarded as n-tupels of formal power series in n variables; also j~X(0) represents the Taylor series of X at 0. In the same way we define jets of functions, diffeomorphisms...

(1.8)

-

are

(1.9) and

DEFINITION. 1 X(0) ~ 0.

X E Gn is said to

-

haveflatness

k if

=

0

Y are said to be Cr conjuif for some (and hence for all) represen1) tatives X and Y of X resp. Y there are open neighbourhoods U and V of 0 in Rn and a C7 diffeomorphism 03C6 : U ~ V such that Vx E U :

( 1.10) DEFINITION. gate (r E N u { 00, cv },

-

X(x)

=

Let

X, Y E Gn. X and

r >

ifi( 03C6(x)).

We also write:

~~X

=

Y in this

case.

Let X, Y E Gn. X and Y are said to be Cr equi(1.11) DEFINITION. valent (r E N u { ~, 03C9}) if for some (and hence for all) representatives X -

and Y of X resp. Y there are open neighbourhoods U and V of 0 in fR" and a Cr diffeomorphism h : U ~ V which maps integral curves of X to integral curves of Y preserving the « sense » but not necessarily the para[0, t ]) c U, t > 0, then metrization ; more precisely : if p E U and and q,v there is some t’ > 0 such that [0, t’ ]) h( [0, t ])). denote the flow of X resp. Y). Time preserving Cr-equivalence is called Cr conjugacy and coincides with definition 1.10 for r > 1. With C° diffeomorphism we mean a homeomorphism. =

(1.12) THEOREM (Borel) [Di, Na]. - For all such that T = j~X(0). (Or: j x : Gn ~ J) is

T e J) there exists

surjective.).

an

X E Gn

0

in ofor shortlya direction, (1point.C’-difieomorphic 13) DEFINITION. image A generalized direction diffeomorphism is

a

0. The

Vol. 3. n° 2-1986.

of the germ in 0 E of a halfline with endis assumed to preserve 0.

14

P. BONCKAERT

( 1.14) DEFINITION. - A germ in 0 of a set K m [Rm+ 1 is called a C‘ l > k, if there exists a germ of a Cj function h : ~olid) cone of contact k, oo with (~0) jkh(o) 0, ~+1~(0) ~ 0 and a germ of a C" [0, [, 0) (Rm+ 1, 0) such that iffeomorphism 03C6: (!Rm + 1, 0) -

=

-

x K is called a cone of contact k around the direction D 4>( { The intersection of a C7 diffeomorphic image of a hyperplane, through D, with K is called a Crm-dimensional subcone of K (0

[0, 00 [) passing r 1).

=

If D is a direction in [?", then there exists a germ of a map y : ([0, oo [, 0) - (~", 0) with y’(0) # 0 such that the image of y is D. Conversely, if y : ( [0, oo [, 0) - (~ 0) is Coo and if y’(0) # 0, then the image of y is a direction.

(1.15)

PROPERTY.

-

Proof 2014 Easy.

D

(1. 16) DEFINITION. - For XEGn and D a direction we say that X is nonflat along D if for some (and hence for all) Coo germ }’ : ( [0, CfJ [0) with y’(0) # 0 and image D we have. y)(0) ~ 0. In the other case we say that X isflat along D. ~

We say that X E Gn satisfies a ojasiewicz (1.17) DEFINITION. quality if there exist k~N and C, 03B4 E ]0, 00 [ such that -

PROPERTY. - If X E Gn satisfies non-flat along every direction.

(1.18) s

( 1.19) CONVENTION. or

a

-

vector field X on ~m

( 1. 20) DEFINITION.

formally

-

a

Zojasiewicz inequality

then X

We write (x, z) for an element of [Rm x; we write X (Xx, Xz). =

We say that X E Gm + 1 leaves the

invariant if for all

ine-

(0)

=

z-axis {0 }m x R

O. This is the

same as

saying

does not contain pure z-terms. 1 x [0, oo D is formally invariant under X E Gm+ A direction D ~( { ~ * 1 X leaves the z-axis formally invariant. =

f

( 1. 21 ) THEOREM (Normal Form Theorem, Poincare and Dulac). - Let (E Gn and let Xi be the linear vector field on [?" such H~ denote the vector space of those vector fields on !?" Let, for vhose coefficient functions are homogeneous polynomials of degree h. Denote [X 1, - ]h : H - Hh : Y --~ [X 1, Y ] and let Bh - Im ( [X 1, - ]h ). Annales de l’Institut Henri Poincaré -

Analyse

non

linéaire

VECTOR FIELDS ON

Choose for each h > 2

an

[R~

115

arbitrary supplementary space Gh for Bh in H~

(that is: Hh - Bh 0 Gh). Then there exists a germ of a C~ diffeomorphism such that ~,~X has an oo jet of the form

where gh E

h

Application (to

=

2, 3,

0)

-

....

be used later

G3 with Let X E 03

03C6:(Rn,

j1X(0)) (

=

on).

ax~ ~x,

a

O. If the z-axis 0.

012 0}2 R is

is

x

invariant under X, then there exists a diffeomorphism r~ : ([R3, 0) X’ has an ~ jet of the form such that

formally -

([R3, o)

=

,

Proof [Ta ]. Suppose, by induction, that for i E N, i X = X+

g2 +

...

write Rl Y E Hi with [Xi, Y]

We

can

>

1,

one can

write

with the gh~Gh and with ji-1Ri-1(0)=0. gi E Gi, jiRi(o) 0. Take an

+ gi-1 + R1-1 -1 - gi + b; with

=

bi. Taking §;= ~Y(., 2014 1 ) (the time -1 mapping of Y) one can check that + gi + Ri: (4)d*(X) == X1 + g2 + Since ji-1 ji-1 Id (0) we can apply the theorem of Borel (for diffeomorphisms) to obtain the desired diffeomorphism 03C6. =

...

=

Proof of the application.

For

forward calculation that for all p, q,

Vol. 3, n° 2-1986.

= ax ~ ax~ it follows from r

a

strai g ht-

16

P. BONCKAERT

We see that for each h > 2 the linear map natrix with respect to the basis

Hence Im [X 1, A basis for Ker

[X 1, - ]h

has

a

diagonal

[Xi, -~ Hh. [Xi, 2014 ] h is obviously Ker

=

So, applying the normal form theorem,

we

have for

4>*X

=

X’

an oo

jet

of the form

It suffices to prove that § can be chosen in such a way that it formally preserves the z-axis. Because then X’ also leaves the z-axis formally inva-

riant, and hence

cannot contain pure z-terms.

component the Y’ E Hi with

Take any [X 1, Y’== bi. If we separate the pure zi terms of o a the and components of Y’, we can write it in the form:

-

-

where Y E HI has

no

pure zi terms in

itsax~ and a components. We have ~y

.

d

as bi and [Xi, Y]don’t contain pure z1 terms in their 2014 component, ax necessarily A 0. So bi [Xl’ Y ]. As ~1 = ~ -1) (the time -1 mapping of Y) we obtain the result. 0 In chapter IV we will make extensively use of the following result. But

=

( 1. 22)

THEOREM

=

(Brouwer, Leray-Schauder-Tychonoff fixed point theoAnnales de l’Institut Henri Poincaré -

Analyse

non

lineaire

VECTOR FIELDS ON

rem) [Sm].

-

Let E be

a

locally

convex

[R~

117

topological

vector space, K a

nonvoid compact convex subset of E, f any continuous map of K into K. Then f admits at least one fixed point in K, that is : a point x E K with

/(.Y) =

~.

§ 2. One

The main result.

pose the

following question: suppose that a (generalized) formally invariant under a germ X E G3 (by formally we mean : up to the level of oo jets, or equivalently : up to the level of formal Taylor series); does there exist a Coo invariant one-dimensional manifold having oo contact with D ? The answer is yes, provided X is non-flat along D. This is one of the major ingredients of the following theorem. Let us emphasize that the results of this theorem are stated in terms can

direction D is

of germs in 0 E f~3. Let X E G3 and let D be a direction. If X is non-flat (2 .1 ) THEOREM. then there exists a Coo cone K of finite contact around D such that along D, one of the following situations occurs: -

I. all the orbits of X

hitting

K enter K and leave

K, except (of course)

{(0.0.0)~ II. D is

invariant under X ; there exists a direction D’ in K, D, which is invariant under X; if we arrange (by of X if necessary) that the orbit of X in D’ tends to 0

formally

contact with

having ~ changing the sign then either

A the only orbit of X in K tending to 0 is contained in D’ ; all the other orbits of X starting in K leave K ; B. all the orbits of X in K tend to 0 ; if we add 0 to such an orbit, we obtain a direction which has oo contact with D ; C. there exists a unique C° 2-dimensional subcone S of K such that

i ) S is invariant under X ; ii) all the orbits starting in S tend

to 0; if we add 0 to such obtain a direction which has oo contact with D; iii ) all the orbits of X starting in KBS leave K.

an

orbit,

we

Always assuming that along the invariant directions the orbits tend to 0 for t -~ oo, we find in cases II. A and II. C a unique model up to C° equivalence and in case II. B even up to C° conjugacy. The proof of this theorem will be given in chapters IV and V. (2.2)

PICTURES of the situations

Vol. 3. n° 2-1986.

occuring

in the theorem.

118

’. BONCKAERT

(2.3) re

REMARK. -

Perhaps sight.

in

some cases

the claimed results in

not evident at first

Take for

example

0

the linear vector field

1

(2.1)

0

+ -z2014 and X=x~x +y ~y time and have

) z-axis. All the orbits tend to 0 in negative ontact with the z-axis. Nevertheless one can find =

a

parabolic

of finite contact wo in this case) such that alle the orbits leave it, except of course the ne contained in the z-axis. This example indicates in which way the main leorem must be considered: once an orbit leaves the cone, we have no irther information about its future, which may be for example to tend ) zero or even to re-enter the cone. a cone

REMARK. - One can formulate and prove an analogon of theo(2 .1 ) in dimension 2, this time of course without situation II. C. On 1e other hand it is not yet clear to me how to generalize the theorem ) arbitrary dimensions; more specifically one could ask: does a formally mariant direction always hide a « real life » invariant direction? The mie question can be posed for diffeomorphisms.

(2.4)

m

Annales de l’Institut Henri Poincaré - Analyse

non

linéaire

VECTOR FIELDS ON

I~3

119

II. PREPARATORY CALCULATIONS CONCERNING BLOWING UP OF VECTOR FIELDS

Although the blowing up method for singularities of vector fields is known technique [Ta, Dul, Du2, D.R.R., Go ] we recall it here because it is of fundamental importance in the sequel. Especially for blowing up in a direction some specific calculations will be elaborated in full detail. Roughly spoken, blowing up a vector field is : write it down in spherical coordinates and divide the result as much as possible by a power of r (= Euclidean norm of x) such that one can take the limit for r - 0. a

§ NOTATIONS.

(1.1)

1. One We

-

spherical blowing

up.

denote, for m~N : 1m -+-1

So in fact with 03A6

we

introduced

Rm + 1 ) ( 0 }

on

a

sort of

spherical

coor-

dinates.

(1.3) PROPOSITION with X(0) 0. Then there is a Cp -1 field X =

on

Sm

If X

(or : ~~X = X). has flatness k, that is,

R such that in each q

x

C,(X(~)) =

e

S""

x

D =

0 and

~+iX(0) ~ 0,

then for the

following vector field -

we can on

S"’

take the limit tor

which

we

r

-

0 and

1 -

we

obtain

X is called the ( 1. 4) DEFINITION. X and up (once) diriding bij ~. -

Vol. 3, n° 2-1986.

a vector

held ot class

still denote X. vector field obtained

by blowing

120

?. BONCKAERT

X restricted to Sm x { 0} is a vector field tangent to Sm x {0}. The study of this vector field sometimes gives information on the asymptotic behavior of the orbits when they tend to 0 [Go ].

§ 2. One directional blowing

up.

In high dimensions the explicit calculations for spherical blowing up quickly become complicated. If we restrict our attention to one open halfsphere of S’" we use the better computable directional blowing-up. We can assume that the half-sphere has (0, 0, 0,1) as « north-pole ». x R by E Let us replace where E is an arbitrary normed vector...,

space. We do this because later on construction remains the same.

point

{0}

shall

use

this form and after all the

CONSTRUCTION.

(2.1) A

we

R.

x

(x, z)

~

of E will be denoted (x, z). With « the z-axis » we mean be the following map : T": E x R - E x ~: Let, for n E N, z). Similarly to proposition (1. 3) one proves

(2 .1.1 ) PROPOSITION. - Let X be a CP vector field with X(0) 0. Then there is a Cp-1 vector field X~1 on E such that in each q E E x ~ : if X(~’ 1 (q)) (or: X). Again jkX(0) 0 and we X 1 devide we denote the jk+1X(0) ~ 0, by resulting vector field =

=

X1

and

=

z

vectorfield

on

again we can

take the limit for

z

-

0 to obtain

a

still denoted XB

E

X1 is called the vectorfield obtained by blowing (2.1.2) DEFINITION. up X (once) in the z-direction and dividing by zk. Like in § 1, E x ~ 0 ~ is -

invariant under

(2.2)

RELATION

[R m+1 Let

so we can

consider the restriction

BETWEEN DIRECTIONAL AND SPHERICAL BLOWING UP IN THE

CASE.

denote the

insider the

ne

XB

«

upper

bijection

F:

hemisphere », that is : ST x R - Rm+ 1:i

immediately checks that ~ _ ~ 1

o

F.

Annales de l’Institut Henri Poincaré -

Analyse

non

linéaire

121

VECTOR FIELDS ON

Hence X

If

we

As

~Sm X ~

denote

and X1

F(xl ,

1

are

C~’

k is

(1+

...

r)

Z,

... ,

conjugated : FX =

an

... ,

xrn,

CALCULATIONS

(X 1,

... ,

Xm, Z) then,

the orbits

+ same

orientation.

CONCERNING ONE DIRECTIONAL BLOWING UP.

GENERAL FORMULAS.

(2 . 3 .1 )

=

X1.

everywhere positive function,

ofX~and F~X coincide. They also have the

(2.3)

r

=

write X (Xx, X~ ). It is an easy calculation to

If X is

-

a

vector field on E

x

[R

we

=

see

that

X if only if

/~

,

and thus rrom

now on we assume

(2 . 3 . 2) some

1HE

00 JET OF

X to be 1

X IN U

(CASE {Rm + 1).

(usual) multiindex abbreviations. m

For

then

we

denote

We write the oo

jet

ot X in U down as

if X has flatness k in 0. Vol. 3,~2-1986.

-

Let

us

indicate here

122

BONCKAERT

’or the

oo

jet of X1

Jsing (2 . 3 .1 ) i) a" -

and

in 0

we

write

calculating straightforward ,...,03B1m)

we

find :

for 1

m 1 _ x

i

for 1 i m 0 ii) a for iii) ~ 0 I n; i i ), ii), iii ) we may take the right hand side zero whenever it is undefined. =

=

(2. 3 . 3)

REMARK. - In

nd for each

a

with |03B1|=

in (iii) we see that for each 0. This expresses the fact that the

particular n :

c:

=

is invariant under X1or equivalently that f X 1 does not contain pure xa terms.

yperplane

§ 3. Successive directional blowing

the ~

z

=

0

component

ups.

~.1) Construction.

Let X1 be obtained by blowing up X in the z-direction and dividing by zk. Suppose that X 1 has again a singularity say in (a, 0) E E x { 0 } and that ~ 1 (a~ 0) = ~)_~ 0. Then we can blow up X 1 in (a, 0) in the z-direction in the following itural sense. Denote T : E x R - E x (x, z) - (x - a, z) ; since T*X is a singularity of flatness p in 0, we can consider the vector field T*X1 stained by blowing up T*X1 in the z-direction and dividing by zp.

i

DEFINITION. up X twice in the

(3.1.1) owing

T*X1 is called the vector field obtained by z-direction first in (0,0) then in (a, 0) and dividing

-

by z~ then by zP; we denote it X2. Of course X2 depends on the choice of the singularity of Xl. In this way, ~ can of course go on with the construction and define successively X" in some singularity. Obviously Xn depends on the I blowing up oice of the singularities in which we blow up. Let us formalize the idea ving a prescribed sequence of singularities in which must be blown up. ’st

_

Let X be a Coo vector field on E (3 .1. 2) DEFINITION. ;0) 0. A directed sequence of successive blowing ups of X is a such that triples (X~, (xn, 0), u{ X° X and i) (xo, 0) = (0, 0) ;

with

-

=

sequence

=

Annales de l’Institut Henri Poineare -

Analyse

non

linéaire

VECTOR FIELDS ON

0 _

ii )

N : Xn

n

has a singularity ot flatness kn m (xn, U) and

by blowing up X" in (xn, 0) and dividing by zkn.

is obtained

DEFINITION.

(3.1.3)

of X where dn, 0

A directed sequence of successive blowing ups N : (xn, 0) = (0,0) will for brevity be called a in 0 of X (in the z-direction). Such a sequence is

-

n

of blowing ups henceforth denoted by (Xn, 0, kn)o sequence

correspondence

n

N.

Further on we will show that there exists a 1-1 between directed sequences of successive blowing ups oo included). and N - 1 jets of directions (N

REMARK.

(3 .1. 4)

123

~3

-

=

(3.2) Calculations concerning

successive directional

blowing-ups.

We will give explicit formulas only for a sequence of blowing ups in 0. As we have already announced this is, at least for our purposes, no restriction. In this case we can define X~ in one step : LEMMA. 2014 Let Xn be obtained defined in (3.1).

(3.2.1) in 0 of X

by

a

sequence of

blowing

ups

as

== , ..,2014 ThenXnR. ~p~E

Xn where Xn has the property

=

X(03A8n(p)),

x

Proof

-

Straightforward.

D

(3.2.2) REMARK. - We see that properties of xn in a cylinder-shaped x [0, oo [ are transformed, by ~’n, to simular neighbourhood x [0, oo [. It is proporties of X in a cone of contact n -1 around { in this sense that we will obtain the results in the main theorem (1.2.1).

(3 . 2 . 3 )

FORMULAS. 2014 Just like in _

Further

on we

(3 . 2 . 4)

will need the

LEMMA.

/11

X

=

(Xx, Xz)

we

have

B

~~

following

Let X be

(2 . 3 .1 ) for

result.

Cx vector field on E x R. If X is non-flat x ~ is formally invariant, then there exists a Q E fvl and a C x function y: E with y(o, 0) ~ 0 such that + 1 the R-component of XQ + is of the form is the vector field z). obtained by blowing up X Q + 1 times in 0, in the z-direction without dividing by a power of z.)

along {OE}

x

[0,

-

oo

a

[ and if {

(XQ

Vol. 3, n° 2-1986.

.

124

P. BONCKAERT

Proof - Put X==(Xx, As, by our assumptions, the map z -~ z) has a nonzero jet, there exists a Q~N and C" maps Ao, Ai , ... , AQ : E ~ ~ with Ao(0) Al (0) == ... == A 1(0) - 0 and AQ(0) ~ 0 such that we can write =

Xz(x, z) Ao(x) + zA1(x) + The ~-component of XQ+ 1 is More explicitely : =

...

+

+

+

III. REDUCTION OF A SINGULARITY TO A SINGULARITY WITH NONZERO 1-JET BY SUCCESSIVE DIRECTIONAL BLOWING UPS

blowing up a singularity of flatness k one might hope that the atness of the resulting vector field in a singularity is not strictly bigger ian k. Up to one type of singularities, this will in fact be the case. If we consider a sequence of blowing ups (Xn, 0, we will see, Iso for that exceptional type of singularities, that after at most one step ve flatness kn becomes decreasing (perhaps constant). In fact, a vector eld which is the « blown up » of another one cannot be of that exceptional Ipe (mentioned above). Next we will prove that if the sequence kn does not decrease to zero, then ie vector field is flat along the z-axis. Let us start by showing that, up to a Coo change of coordinates, it is o restriction to assume that a directed sequence consists of blowing ups long the z-axis. When

§

1. Definitions and

properties

of directed sequences.

PROPOSITION. - Let N~N u { ~} and suppose that is a directed sequence of successive blowing ups of [hen there exists a C’ change of coordinates ~ : (p~m+ 1, 0) ich that in the new coordinates this sequence is ( ~,~(X)n, (0, 0),

0),

( 1.1 )

Proof

-

We define

inductively 1

on

as

some

1, 0) kn)o ~ ~ ~;.

transformations

follows.

Annales de l’Institut Henri Poincaré -

Analyse

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VECTOR FIELDS ON

!R 3

125

Put

Suppose

that ai,

’Ii

witn n + 1

defined tor 1

are

the singularity of ( ~n),~(X)n+ (~+i,0)e!R" (.Yn+i, 0) in the new coordinates induced by ~n’ Put

denote to

1

1

/

2014n~’ 1 -

/--

B

1

m.

We

corresponding ’B

1 ~mT 1 : (x, z) - (znx, z) denotes the « blowing up map », If qn : 1 N. n observe that ’Pn 0 Tn 03B1n o 03A8n, blown If Y E G~~ ~can be up n + 1 times in (0,0) and if ~n + 1 must be blown up in a singularity (an + 1, 0) then : =

.

~~

.

~

.

~ ~~

.

,

,

so must (the z component is not alterea by 1 n +1 nor by be blown up in (0, 0). we obtain that Applying the foregoing observation to 1 be is (which ( ~n + 1 )~c( 1 ) must blown up in (0, 0). For

(0)

’--

SO .

r or nmte

ØN -1

I

is tne aesirea

.

I

/~.....

i.,~

~).

by (1), consider the inverse limit of the ~", and theorem (I .1.12) of Borel together with the inverse function theorem [Di ] gives the desired ~. D For N

=

oo we

can,

For each directed sequence ( 1. 2) COROLLARY. (xn, 0), there exists a C~ change of coordinates (x, z) z’) and a direction D = ~ -1 (z-axis) such that if we blow up ~ * 1 X successively in 0 then points corresponding to (x, z) (0, 0) like in the proof of ( 1.1 ), are precisely (x’, z’) 0). Conversely, given a direction D = ~ -1 (z-axis), there exists a sequence ~ as above. Moreover, D is unique up to N -1-jet equivalence. In other words : there is a 1-1 correspondence between directed sequences and N -1 jets of directions. So we can speak of a sequence of blowing ups along a direction. -

==

=

==

Vol. 3. n° 2-1986.

126

.

BONCKAERT

If we blow up X successively along the z-axis it is of course possible hat after some finite time there is no singularity any more in (0, 0). Let us ~rmalize this as follows.

is called a maximal directed sequence 0, ( 1. 3) DEFINITION. >f blowing ups along the z-axis if either i) N oo ii) N EN -

=

_

Property. Such

a

sequence

always exists.

If (X",0,~)o~N is a maximal directed sequence PROPOSITION. vith N E N, then there exists a cone K of contact N - 2 around the z-axis ,uch that all orbits inside K enter K and leave K after a finite time.

( 1. 4)

-

Proof - As X~’~(O) 5~ 0, we can construct a cylinder shaped neighbourhood of 0 in [Rm x [0, oo [ of_the form C= {(~ R, : E [o, b [ } such that all orbits of XN - 1 inside C enter C and leave C after 1 finite time. Then

Let K be the germ in 0 of this set. D So from now on we will consider infinite sequences of blowing ups. Let us indicate what it means for X that a maximal directed sequence of blowing ups of it along the z-axis is infinite.

(1. 5)

PROPOSITION.

sequence of are

blowing equivalent :

Let ups of X -

along

be a maximal directed the z-axis. The following statements

i) N ii) the z-axis is formally invariant under X (see definition (1.1.20)). Proof i) ==> ii). Let us write down the oo jets as follows -

0 for all K > ko + 1 and i E Ve must prove that afo he formula in (II.2.3.2) ii) we find that for all K =

Annales de l’Institut Henri Poincaré -

>

ko

Analyse

+ 1 and non

linéaire

VECTOR FIELDS

i

1,....m}:

==

ON R3

and turther

aki,0

127

induction

by

on n we

get,

ato. using Suppose, by contradiction, that aKi,0 ~ 0. Then -k0-1 ~ 0 so k 1 + 1 K - ko - 1 (remember the choise of kin definition (II . 3 .1. 2)) 2 ; further by induction K - ko with always, as it should be, 0 kn _ 1 - n. kn _ 1 - n for some n. Certainly sooner or later 0 K - ko the

same

formula, for all n

=

...

=

-

...

-

m

X"(0) =

But then

ii)

~

i ).

ko diately ai,0 K >

Let

+ 1

~ 0, contradicting N

oo.

notations. We have ...,~1}. The formula (11.2.3.2) and f ~{ 1, ...,m} whence

the

us use

and 1, 0 for all n 0

=

the result.

=

§ 2. Reduction

to

same

a

singularity

with

nonzero

The main purpose of this section is to prove the

0, for all gives imme0, dn and =

1-jet.

following :

If is a maximal directed sequence (2 .1 ) THEOREM. of blowing ups of X E Gm+ 1 along the z-axis { 0 }m x [0, oo [ and if X is non-flat along the z-axis then there exists a N~N such that has flatness zero The proof of this theorem will be a consequence of the following propositions (2.2), (2.3), (2.4), (2.6), (2.7) and (2.8). D -

(2 . 2)

PROPOSITION.

-

Let X E Gm + 1 have flatness k. If X 1 has flatness n

As

0 ~x ~ k

=

1, 1

U we

i

~

only have

to look at the

a1 x 1

and the

1,

Out of (11.2.3.2) Üi) we obtain for each n k and a with = n -1: 0 with 1 _ n 1g = ci ~ ~ ~ ~ " ~ ~=c~ ~so~~ ~ =0, for each x with 0 ~ | 03B1| k. (2) From (I I . 2 . 3 . 2) i ) we get for each n with 1 n k + 1 and a with x = n and 1 xl : +

m.

=

But by 0 ~ x

(2) above those c’s ( _ k + 1 and 1

Vol. 3. n° 2-1986.

are zero.

xi.

Consequently

==

0 for each

oc

with

128

In the same way, using (11.2.3.2) ii), we obtain that all the coefficients in jk+ iX(0) vanish except possibly c~ ~1 with = k + 1. D

(2 . 3) PROPOSITION. has flatness

-

and if X~1 has flatness k, then X‘

If

k.

Proof Suppose that jk+ 1X2(4) that imply -

=

0. Then

proposition (2.2)

would

_

By our assumptions one of the ( = k + 1, must be different from zero. But this is impossible because of the remark (II. 2.3.3) (invariance of the z = 0 hyperplane). Q If XEGm+1 has flatness k and (2.4) PROPOSITION. then X 1 has flatness k + 1. -

Proof - We must show

and from jk+1X1(0)

=

0

we

that

~+2X~(0) 5~

0. From

proposition (2.2)

get

Because X has flatness k, there exists Using (II . 2 . 3 . 2) iii ) we observe that

an a

-k+2 - ~+2+~-~-1 _

# 0.

= k + 1 and

with |03B1| 1 .

D if (2 . 5) COROLLARY. - If sequence of blowing ups in 0 of X in the z-direction if X has flatness k then either.

is

(N

a

u{

directed oc }) and

i ) Xhas flatness smaller than or equal to k and for all n with 0 11 N -1I the flatness of Xn +is smaller than or equal to the flatness of Xn ; 1 ii) X has flatness k + 1 and for all n with 1 - n N - 1 the flatness of is smaller than or equal to the flatness of X~. Let X E Gm + 1. Suppose that there exists an (2 . 6) PROPOSITION. of blowing integer k > 1 and an infinite directed sequence (Xn, 0, -

X~ has flatness k and at each

ups in 0 of X in the z direction such that Vn

step

divide by zk. Denote i: R ~ Rm+1:z

we

-

(0,

...,

0, z).

Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS ON

is

II$3

129

Proof - Let us write again X for its formal part. Then jk- i(X)(0,..., 0, z) formally determined by

We

use

the notations

"

2014t~_2014

,

as

in

(II.2.3.2) and obtain 00

Hence the terms

n

playing

a

role in

o

i)(O)

are

1

we look at what these terms

give when blowmg up

We use qn:(Rm+1 ~ the formula in (II.3 .2) which becomes here m

For the

2014 component C,Y,



~

Vol. 3, n° 2-1986.

~--i

we

obtain

as In tne

proposition. and

30

a nd for

the - component we have

~ irst look at

(4). If this construction is possible for each

n E N then

Thus the second EE in (3) vanishes. For the same reasons as 0 for all N >- k + 1,0 z m, 0 - ~ tioned we must have Th is means 0 1 (X) f)(0) = 0.

c~

=

0

just men-

=

_

o

Let be non-flat along the z-axis. (2 . 7) PROPOSITION. Let xn be obtained from X by n successive blowing ups in 0 in the z direction. -

Then X~ is non-flat

along

the z-axis.

Let ~n : ~m + 1 ~ ~m + 1 ; (x 1 ~ ... , .xm ~ Z) -~ Proof z) the blowing up mapping leading to X~. Then for some analytic function Gn we have and X o ~I’n= ~~ X". Denote i : [0, oo[ ~- p~m + 1: z (0, ... , 0, z). Suppose that j~(Xn f)(0) 0. Then j~(Xn f)(0) 0 and hence j~(X f)(0) 0. But i = i. This would imply that j~(X i )(0) 0, contradicting 3ur assumptions. D -

...,

Je

o

-

o

0

=

=

0

0

=

o

=

Suppose that X E Gm+ 1 is non-flat along the (2 . 8) PROPOSITION. z-axis. Then it impossible that there exists an infinite directed sequence of blowing ups in 0 of X in the z-direction with Vn > 1: kn > 1. -

Proof - Suppose that there exists such a sequence. Then there exist integers k > 1 and N > 1 such that Vn > 0 : XN + n has flatness k. Hence proposition (2 . 6) ~)(0) = 0 contradicting proD position (2.7). This completes the proof of theorem (2 .1). o

IV. TREATMENT OF ALL THE FLATNESS ZERO CASES AND PROOF OF THE MAIN THEOREM, WITH EXCEPTION OF THE C° RESULTS

study germs in 0 of vectorfields which i ) leave the [R~ x { 0 } hyperplane invariant ii) leave the z-axis { formally invariant iii ) have a nonzero 1-jet. (Sometimes we will only consider the case m 2.)

We

=

Annales de l’Institut Henri Poincaré -

Analyse

non

linéaire

131

VECTOR FIELDS

The

1-jet of such

a

vector field has a rA

matrix of the form

AI

m

with A E f~’~ " and where Cô has the same meaning as m (11.2. 3 . 2). Such vector fields appear as a result of the reduction by successive blowing up in part III. Even if the 1-jet is nonzero, we will sometimes blow up the vector field some more times in order to obtain situations like in the main theorem (1.2.1); also in some cases the proof of the existence of the Cx 1-dimensional invariant manifold is made easier by making extra blowing ups.

We must show that all possibilities for C6 and A (both not simultaneously a situation as in the main theorem (I .2.1). 0. This turns out to be fairly easy. We first distinguish in § 1 the case If C6 0, (§ 2) we restrict ourselves to the case m 2. The possibilities are :

zero) lead to =

=

i ) A is hyperbolic : see (2 .1) ii) A has eigenvalues ( « the rotation case » ) : see (2. 2) iii ) A has eigenvalues a, 0, a E tRB { 0 }: see (2 . 3) iv) both eigenvalues of A are zero : see (2 . 4). .

§

1. The

eigenvalues

in the z-direction is

nonzero.

satisfies : Suppose that ( 1.1 ) PROPOSITION. is formally invariant under X i ) the z-axis { 0 (see the notations of (11.2.3.2) or above). ii) -

Then

a) there exists a Coo germ h : ([0, oo [, 0) 0) whose graph (germ) I z E [0, oo [} is invariant under X and with j~h(0) 0 ; { (h(z), z) E Rm R b) supposing c10 0 change the sign of X if necessary there exists a cone K of finite contact around the z-direction x [0, oo [ such that the only orbit of X in K tending to 0 is contained in {(h(z), Z)E ~m ze [0, oo [} ; -~

=

all the other orbits

Proof ko ki1 =

a

starting in K leave K after a finite amount of time. If we use the formulas in (II.3.2.3) (with of course ... = kn-1 0) we find that for all n > 1 the 1-jet of X’~ has

-

-

=

matrix of the form

() l

Notice that 5. is

Vol. 3, n° 2-1986.

an

eigenvalue of A

if and

only

if

is

an

eigenvalue

132

P.

BONCKAERT

Hence for large n, X~ is a hyperbolic saddle for which we can apply the (un-) stable manifold theorem (see for example [H.P.S., Ke ]) to obtain the results. D

(1.2) REMARK. - The methods we develop further on for the delicate situations would also work here; the calculations would be much simpler here.

( 1. 3)

REMARK. - In

§ 2. From

(2.1)

The

( 1.1 )

eigenvalue

~3,

work in

now on we

THE HYPERBOLIC

we

may

replace

~

by

in the z-direction is

more even

any Banach space.

zero.

thus: m = 2.

CASE.

(2.1.1) PROPOSITION. Suppose X E G3 satisfies z-axis the is i) formally invariant under X -

3

8

iii )

a, b > 0

by

ii) X is non-flat

Then there exists

along the a cone

z-axis.

K of finite contact around the z-axis, a a COO germ h : ( [0, oo [, 0) -

C°2-dimensional subcone S of K and such

a) b) c)

that j~(0)

=

unique (fF~2, 0)

0 and :

S is invariant under X the graph of h, ~ (h(z), z)z E [0, oo [ }, is invariant under X and lies in S in K we have situation II. C of the main theorem (1.2.1).

8

Proof - By

lemma

(II.3.2.4)

we

may

assume

that the

- component

of X is of the form zQy(x, y, z) with y(0, 0, 0) # 0 and Q > 2. We may, and do, assume that y(0, 0, 0) > 0, because if not, replace X by - X which is of the same type. If we use the center manifold theory such as in [H.P.S., Ke] we obtain the existence of a unique center-unstable-manifold. Although it is general not necessarily CX, here we can use the uniqueness of the center-unstable manifold as well as the fact that X is non flat along the z-axis to obtain that the center-unstable manifold is in this case, as follows. For each In E N there exists a C7" center-unstable manifold Wm defined on some neighbourhood Um of 0 ; we can take care that U m +1 c Um for all By uniqueness of the center-unstable manifold we have Annales de l’Institut Henri Poincaré -

Analyse

non

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[R3

VECTOR FIELDS ON

1

If

=

holds for fixed

we

take U 1 small

.

enough

then the

133

following

m.

Since ~(0,0,0)

>

0 and since a

>

0 there is a T > 0 such that

denotes the flow of X). So Ui1 n Wi is a Cm manifold. But as m is arbitrary, we obtain that U1 n Wi is C ~. The behavior of X restricted to this center-unstable manifold found in full detail in [D.R.R. ]. D

(4)x

can

be

The methods to obtain invariant manifolds, deve(2.1.2) REMARK. further on for the more delicate cases, could also be applied here. lopped -

(2 .1. 3) defined

PROPOSITION.

-

Let E be

Banach space, X

a

a

Coo vector field

with X(0) 0. Suppose that neighbourhood U of 0 E E the z-axis is invariant under i) X; formally is a hyperbolic contracii) E x { 0 } is invariant for X and D(X IE tion or expansion, that is : the spectrum of this linear operator is contained on a

=

x

in a subset of C of the form { z for some i~ e R, h > 0 ; iii ) X is non flat along the z-axis. iv ) X is bounded on U together with all its derivatives. Then there exists a cone K of finite contact around the z-axis and a C ~ germ h : ( [0, cxJ [, 0) - (E, 0) with a) the graph of h, ~ (h(z), z) z E [0, oo [ }, is invariant under X b) in K we have situation II. A or II. B of the main theorem (1.2.1).

Proof - Let us write X (Xx, XZ). By lemma (II . 3 . 2 . 4) we may assume =

’2014 ~- ~

,

0 and Q >_ 2. There exist A e Lc(E, E) and B: (E x R, 0) - (E, 0) such that

that

A,/~

XZ is of the form : ,

with 7(0, 0) #

and such that

(E

x

~, 0)

-

(Lc(E, E), 0) and Rx:

(up to changing the sign of X).

r Re z i ) the spectrum of A lies in { 0} ii ) B and Rx are Cx germs; especially B(O,O) 0 0) = 0. iii) =

is

This because the z-axis is formally invariant. We also may assume that R x flat along E x { 0 } because if not, blow up once.

Vol. 3, n° 2-1986.

x

134

P. BONCKAERT

The existence of the invariant graph follows from the center manifold Its smoothness follows from the fact that y(0, 0) # 0. If y(0, 0) > 0 then we have situation II. A and if y(0, 0) 0 then we have situation II. B; this can be proved by standard techniques like in [D.R.R. ] or like further on in the more delicate cases. D

theory.

(2.2)

THE

ROTATION CASE.

We study germs in 0 of vector fields on R3 which leave the z-axis R2 0 formally invariant and for which the 1-jet has eigenvalues here E Such a vector field is (/. fRB { 0 } ). completely non-hyperbolic, so the « classical » theorems about invariant manifolds as in [Ke, H.P.S. ] are not applicable. First of all, such a vector field has, up to a linear change of coordinates preserving x {0} and {0}2 x R, a 1-jet of the form -

In

[B.D.]] we obtained

the

(2. 2 .1) PROPOSITION. i ) the z-axis { 0}2 /

iii)

A is non nai

x

along

-

following

result :

Suppose X E G3 satisfies is

formally

invariant under X

x 1

me z-axis

then

a) there exists a Coo germ h : ( [0, oo [, 0) (~2, 0) whose graph (germ) { (h(z), z) e [0, oo [} is invariant under X and with jooh(O) 0 b) there exists a cone K of finite contact around { 0}2 x [0, oo [ such that in K we have situation II. A or II. B of the main theorem (1.2.1). -

=

(2.3)

ONLY

ONE NONZERO EIGENVALUE.

Here we will meet all situations II.A, II. B, II. C of the main theorem. In situation II. C we will have to construct invariant surfaces. Sometimes we could make use of the classical center manifold theory, but for other cases, where the requested invariant manifold is not a stable, center-stable, center, center-unstable or unstable manifold, we will have to apply our own methods. But if we set up the whole machinery anyway it can effortlessly be applied to the « classical » cases. The methods to obtain smooth invariant manifolds developped in this section, can also be used to obtain the results in (2.1) and (2.2). Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS ON

IF$3

135

Up to a linear change of coordinates preserving (~2 x ~ 0 ~ and { O}2 may assume that the 1-jet is of the form

x

R,

we

(2 . 3 .1)

PROPOSITION.

the z-axis is

i)

-

formally

Suppose X E G3 satisfies invariant under X

a

ii)

= ax

a ~ 0

X is non-flat

iii )

then there exists a germ h : ([0, oo [, 0)

along

the z-axis

K of finite contact around the z-axis and (~2, 0) with /~(0) 0 such that

cone -

a

Coo

=

a) the graph (germ) ~ (h(z), z) z E [0, oo [} is invariant under X b) in K we have situation II. A or II. B or II. C of the main theorem (1.2.1).

Proof. - We may assume that Because X is non-flat along the

z-axis,

and hence we assume that there exists of X is of the form

with

fl/(0, 0, 0) #

So X

can

in (I.1.21). apply lemma (II.3.2.4)

has the form

a

we can

Q e

as

N such that

the ~ component oz

O.

be written

as

follows:

where

0 i) fl~~~ 0) == ii) 0, o) ~ 0 i) S , is a vector field which is

oo

flat

along

the

z

=

0

plane

and with

c

zero

-,--component c~

(we absorbed

it in 7;

we

also assumed

at

least

one

blowing up) it;) Q > 2. We only pay attention Vol.

3,

n° 2-1986.

to the upper half space

[R2

x

[0,

oo

[. If we blow

136

P. BONCKAERT

up X n times, without dividing is nonzero, then we get

by

a

power of

z

of

course

since the

1-jet

;=)

0 plane. for some S~ which is oo flat along the z Because y(0, 0, 0) ~ 0 we can assume that X", denoted again X, has the following expression (new fl , y, ... ) provided that n is big enough : =

~-) /,(0,0,0)=0 it) /(0, 0,0) = ~ ~

0

P E { 1, ..., Q - 1}

~

is (X) flat along the z 0 plane and has zero ic) component. ~ V) y(0,0,0)=c~0. Furthermore, in order to make the calculations a bit simpler, we divide X ==

by

1 1 + -

The

a -

/

resulting

vector

-

field, again denoted X, is of the form

,

(new f; ... ) :

where f, y, S x satisfy the same properties (ff) to (v) as above. The foregoing manipulation is not essential. If we look back to the expression for X~ hereabove, we see that in case P Q - 1 we may assume that b. c 0 provided n is chosen big enough. So up to a change of the sign of X the four following situations can occur : =

I. II. III. IV. Annales de l’Institut Henri Poincaré -

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137

VECTOR FIELDS

Here

we

already

theorem, II treat

that I will lead to situation II. B of the main situation II. C and IV to II. C. We We will refer to some lemmas which will be

announce

to situation II. A, III to

each case separately. after this proposition.

proved

In order to detect invariant graphs for X we consider the graph transformation defined by the time one mapping of X (precise definitions will follow). Roughly spoken this is: take a graph of a map (x, y) h(z) and transform it by the time one mapping of X. First we modify X, without modifying its germ in (0,0,0), with a Coo =

« bump » function r : [0, on [1, oo [ as follows. For all 8

>

0

we

oo

[

-

[0,1 ], where i(u)

=

1

on

-0, -

-

and z(u)

=

0

define / 7X

Then XG has the same germ in 0 as X can be defined on a neighbourhood of the form (x, [0,00[, with B(0~)== { (x, y) E }. Moreover the z)| z ~ 8 } is invariant under - X~. We can modify X to XG in such a way that the (new) f, y satisfy satisfy inequalities like ~

-

r,__

-.

~B

~

~

-

A

neighbourhood B(o, ,u) x [o, oo [, where al, a2, bl, b2 can be independent of E (for this reason we don’t attach an index E to f or y).

on some

chosen Let

us

show that the

«

fiatness condition

»

of the

is independent of E, that is : for all r, S E N there exist b such that for all E > 0 and for all (x, y, z) E B(o, ~) x 1

Let in tact r,

Vol. 3. n° 2-1986.

,.

i

i v

W e have :

, ,

E

term 03C4(z ) >

S x (x, y, z)

0 and

[o, 3] :

>

0

138

P. BONCKAERT

There exists a ð > 0 such that for all p E ~ 0, there exists a constant Li,p > 0 such that

...,

,

- ~ --

z

The time

1-£)= mapping

~ ~:

one

z) =

(1

0

+ s ~ and all i E { 0, B(o, /1) x [o, ~ ] :

...,

s}

,

Furthermore for all j e fil there exists I T~(M)) ~ K~ . Hence for all z 6:

and for all

r

on

so

the

of xE

can

+

y,

a

K~

>

0 such that for all

[0, oo [:

Me

problem is trivial there. be written down

z))y, z

+

y,

as :

z))

+

y,

z)

where

i)

is oo-flat

along [R2 x { 0 }

and the flatness condition is

indepen-

dent of 8

has zero z-component (we absorbed its z-component in g) ; ii ) iii ) there exist constants b2 and a neighbourhood

independent

of ~, such that

on

V:

We write Fe We will show in lemma (2.3.5) that there (Fx,e, Fy,e, > 0 and 03B4 E ]0, 5i[such that if h : [0,5]] - [R2 satisfies h(0) 0 and for all ze [0~]: [ h’(z) ( [ 1 then Z : [0, 5]] z z) is a diffeomorphism onto (at least) [0, ðl]. Let z(Z) denote the inverse. We define, for 0 8 61, the following =

exist 03B411

=

function spaces :

[0, ð] -+ [R2

F?,. = ~ h

is Cm,

h( [~~ ~ ])

c

B(0,

1, h ~ - o

and for all

[0,5]]

-

[R2 is Cm, h(0)

I Define H

=

as

H(Z) =

=

0} [s,5]: ~(z)==0} i E ~ 0, m~~. ze

[a,3]: h(z)

=

0 and for all z E

[

for all

z(Z)),

...,

z(Z))) if Ze[0, ð1]]

Annales de l’Institut Henri Poincaré -

Analyse

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VECTOR FIELDS ON

ana

=

U lI L E

L~$

139

is a wen defined

1E

map

iium

into

tsE-

is small and Fg is continuous for the C"" topology. From lemma (2.3.6) we will obtain that for all m > 1 there exists an c Fm. E > 0 such that for the Let Fm be the closure of F7 in topology. Each Dth for h E Fm and Lipschitz function with a Lipschitz constant independent of h ; this is still true for h E Fm. The space Fm is hence compact for the topology, as a consequence a theorem of Ascoli-Arzela [Di ]. of F~ is also convex. =~ As F is continuous on F~ for the topology, we still have

provided 8

Fr. Hence it follows from the Leray-Schauder-Tychonov fixed point theorem (1.1.22) that F has at least one fixed point in F~. We hence obtain for each m an Em > 0 and a C"" map hm: [0, 6 ] - [R2 with jmhm(0) 0 whose graph is invariant under =

z) (0, 0, 0) hm(z) 0 on [~m, 03B4 ] and because lim in z the estimates we is on obtain ceo outside 0. uniformly (see g) that hm In lemma (2 . 3 . 7) we will prove that if h : [0, 5 ] is C1 on [0, 5] B(0, p) and COO on ]0, 5]] and if the graph of h is invariant under then h is ceo 0. on [0,5]and jh(O) Hence hm will be So we can consider for example F~and hi. As a matter of fact we want hl to be invariant under XE1. To see this, observe that for all t E [0, 1 ] : ~xEl((0, £5), t) lies on the z-axis denotes the flow of Xe1) since ~1 5i; for all t’ > 0 we write t’ = n + t where t E [0,1 ] Because

=

=

-

=

and n

we

have I

~~~

C~B

t

tB

/

t

///1

C*B

B B

B

nence me

grapn 01 ni is invariant under 03C6x~1(.,J tor an t’ > u. in Finally lemma (2 . 3 . 8) we show that in some neighbourhood of(0,0,0) all orbits tend to (0,0,0) and that those outside [R2 x { 0 } (in the blown up situation) are graphs of maps h satisfying the hypothesis of lemma

(2.3.7). Hence

we are

in situation II. B of the main theorem

Here the graph transformation can be defined mapping of X is again of the form

where

is oo tlat

Vol. 3. n° 2-1986.

along

the

z

=

U

plane

as

(1.2.1).

follows. The time

and has a zero

one

z-component.

140

P. BONCKAERT

and

This time there exist constants (0, 0, 0) such that on V we have ~-

~

Here

we I" -

-

_

0 is

8 >

_

-

_

(Fx, Fy, sufficiently

.,

_

~m

~

"

,

n

--~-

small and if h E

~

then the map

(at least) [0, e]. To

~

~

.

~

prove

D20141/7/ B B .

this, remark first that

/

estimate the first order derivatives of of h E F~. Second observe that for small

we can

independent

Denote

~.~

=

is a diffeomorphism onto for small z:

because

..

V of

take the function spaces

Denote F

If

../~

neighbourhood

a

the inverse of Z ; put H

rtB

g and

h

by constants

s:

I1 h where

H(Z) = (Fx(h(z), z), Fy(h(z), z)). Again : i ) r : Fm B~ is well defined if 8 is small and r is continuous for the C"’ topology c ii ) for all m > 1 there exists an 8 > 0 such that proof see lemma (2. 3. 9) hereafter iii ) r has a fixed point in Fm (the closure of Fm for the topology). z

=

-

_

In order to prove that hQ is Cx we will show in lemma_(2.3.10) that there exist > 0 such that is a sequence in B(0, p) x [0, s] ~Z, with lim and for i ~ 1 (0, 0, 0) (xi-1, Yi- 1, y,, z,) y,, z; ) then this sequence must lie on the graph on hQ. This implies that for all m > Q there exists an ~’m > 0 with ~’m ~ min { 8m, 8Q } such that h,~ and hQ coincide on [0, s~ ]. As a consequence of the movement of F in the z-direction (see the estimates on g above) we see that hQ is C7" 0. Hence hQ is Cy and jx h(0) on [0, GQ]] and that 0. Because of the unicity of hQ. in the sense of lemma (2.3.10), we see as follows that the graph of hQ is also invariant under X. Let q ~ N/{0}. Then, by similar arguments as above, we find an E E ]0, 8Q [ and a C x map h : =

==

=

=

Annales de l’Institut Henri Poincaré -

Analyse

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VECTOR FIELDS

[0, I ]

---

fR2 with jx h(o)

(the time 1 q must.

by

mapping

lemma

of

(? . 3 . 10),

=

0 whose

X). lie

Take

on

the

ON R3

141

graph is invariant under 03C6x(1 q,.) z E

[0, ~].

Then the sequence

graph of ,

(l )

So h hQ z ] . Hence the graph of hQ is invariant under ] q / for each q. Thus under X.. lemma it will II. A from follow that we in situation are (2 . 3 .11) Finally of the main theorem. ==

Case

I I I : P Q - 1, ~ 0, b > 0,

,

c > 0.

Let us first search for an invariant surface tangent to the yz-plane. This will be a so-called center manifold. If we would apply the « classical » center manifold theorem, we would obtain for each r the existence of a C7 center manifold : see for example [Car, Gu, H.P.S., Ke, M.M. ]. But we will show that in this particular case the center manifold is Coo, at least in a blown up situation. Further we will show that the orbits starting in some neighbourhood of 0, but starting outside the invariant surface, will leave the neighbourhood. The behavior of X restricted to this invariant 2-dimensional manifold tangent to the yz-plane is well known and is as follows: there exists an invariant direction D’ having oo contact with the z-axis ; all the orbits starting in the invariant surface tend to 0 in negative time and have oo contact with D’. So we will be in situation II. C of the main theorem. But let us now come to the proof of all this. First we prove the existence of the invariant ex surface. For reasons which will become clear later in the lemmas we first perform a rescaling of the z-axis as follows. We want in fact that P > 2. Let R : [R2 x ]0, oo [ - [R2 x ]0, oc [: (x, y, u) - (x, y. u2). We have that R*X’ == X if and only if for

Vol. 3. n° 2-1986.

142

Here in

P. BONCKAERT

particular :

instead 01 M, A instead 01 X .

Let us write again

z

We obtain

vector

again

a

field of the form

(new P, Q,f, ...). ~

~

~

with this time P > 2 and still P Q - 1. Let us already remark here that such a rescaling will have no influence on our result, since it is our aim to construct an invariant graph of a Coo function z) with for all y: jxh(y, 0)=0: it is easy to show that then also a C x function of (x, u) oo-flat along the y-axis. Also all the other results we shall obtain are preserved by this rescaling. The time one mapping of X can be written as

~==/!(~~/M) is

F(x, y, z) = (eax, (1 + where a(0, 0, 0) > 0, g(0, 0, 0)

z))y, z + zQg(x, y, z)) + 0, Roo is oo flat along the z

>

=

has zero z-component. There exist constants al, a2, such that on V:

bi, b2 and

n / n

We look for

a

Ceo invariant ,.

~..

,

,

*~

>

graph ...

I

,

,

’7

a *~

z) 0 plane and R

neighbourhood

V of

~

(0, 0, 0)

n-

of the form -

,

,,

> 0 will be rechosen some times for our purposes. If , 3 > 0 c V. small then VÓ,Jl:= [- /1, p] x [-~/~]] x [0,5] ci V and Let us define some function spaces for ~ ~ 3 :

The

are

and FI = Fx, F2 Let us write F (Fx, Fy, (Fy, F,). We would like that the surface determined by ( y, z) - F(h( y, z), y, z) is again the graph of some function. For that purpose we shall prove in lemma (2.3.12) =

=

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143

[R~

sjJ small /1, 8 > 0 and h~F10,~ the map (Y, Z) : [- , ] [0, onto a is ~c ] x [0,8]. /1, (at least) [ diffeomorphism F2(h( y, z), y, z) ( y, z) In that case we can take the inverse of (Y, Z), and denote it ( y, z). So ( y, z) is defined on (at least) [ - ~c, ~c] x We put H rh where -

that for

-

=

H is defined on (at least) [ - /1, /1]] x [0, e]. So, for 8 small, r is a map defined on and takes values in B~. r is Moreover continuous for the em topology. In lemma As Fm c for small 8, r is defined and continuous on we that there a shall exists > that 0 such for each (2. 3 .13) prove (fixed) ~ > 1, there exists an 8 > 0 such that c Fm. From this fact, from the theorem of Ascoli-Arzela and from the Leray-

Schauder-Tychonoff fixed point theorem (I.1.22) we derive, in an analoguous way as in case I, that for all m E N there exists an 8m > 0 and a C"" map R with jmhm(y, 0) = o for all YE [ - , ] whose graph hm : [- , ] [0,~m ] is invariant under F. In lemma (2. 3 .14) we shall show that there exists 0 such that if (xi, yi, is a sequence in [ -,u, ,u] x [ /1, /1] x [0, 8] with and F(x;, yi, 1 ) then this sequence must lie on the graph of hQ. Again this uniqueness of the invariant graph and the movement in the z-direction (see the estimates on g) imply that hQ is in fact ceo and that its graph is invariant under the vector field X. Also j~hQ(y, 0) 0 for all y E [ - ,u, ]. -

-

=

Next we consider the restriction of X to this invariant C°° 2-dimensional manifold obtained above (always restricted to the upper half space). This 2-dimensional situation is treated in full detail in [D.R.R. ], and is hence omitted. Finally, from the expression of X we can now easily show that we are in situation II. C of the main theorem (1.2.1).

Here

we

also look first tor

an

invariant

surface, this time tangent

to

the xz-plane and passing through the x-axis. In contrast with case III this surface is not a center manifold. But nevertheless we will prove that we are in situation II. C of the main theorem, that is: the orbits starting outside the invariant surface and starting in some small neighbourhood of 0 leave this neighbourhood, on the other hand the orbits in the invariant surface just mentioned tend to 0 in negative time and have Jo contact with the z-axis. One can observe in the sequel that in this case it is crucial that the xz-plane is formally invariant, thanks to the normal form. If this were not the case, our method wouldn’t work. Vol. 3, n° 2-1986.

144

P. BONCKAERT

The time one mapping F of X has the same form as in case III with this time (x(0, 0, 0) 0 and g(0, 0, 0) > 0. Hence there exists constants al, a2, bl, b2 and a neighbourhood V such that on V : 17

If

0 are small then F(V,,,) V. We define for E 3 :

/1, ð

>

V J-l,ð

~==

[- /1, /1]]

x

[-

]

x

[0, (5]c

V and

c

Again: see i ) for small 8 we can define the graph transformation r on lemma (2. 3.15) here after. B~ is continuous for the Cm topology; ii ) there a (fixed) ,u > 0 such that for each m E exists >- 1, there iii ) exists an 8 > 0 such that Fm : see lemma (2 . 3 .16) ; iv) applying the theorems of Ascoli-Arzela and of Leray-Schauderthe existence of an 8m and a C"’ map hm : Tychonoff yields for all m 0 for all x E [ - ~c, ,u] whose [2014~,~]] x [o, Em ] ~ R with graph is invariant under F; v) the uniqueness in the sense of lemma (2.3.17), and the movement of F in the z-direction (see the estimates on g) imply that hQ is in fact Cx and invariant under the vector field X. 0) 0, for all x E [ 2014 ~ ,u] ; vi ) the results of [D.R.R.]] concerning the behavior of X restricted to the invariant surface together with lemma (2.3.18) hereafter imply that we are in situation II. C of the main theorem. D =

=

Lernmas used in the

proof of proposition (2 . 3 ..1 ),

(? . 3 . 5) LEMMA. 2014 There exist 6 > B(0, p) satisfies h(0) 0 and !! [0, 6] -

0 and

case

I.

a 1 E ]0,5[[ such that if h : on [0, 5]then for all 8 > 0

1

=

the map v.

is a

diffeomorphism

1

_

onto at least

FTD . -,

. 17

/ L/ ~B-B

[0, 03B41J

Annales de l’Institut Henri Poincaré -

Analyse

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ON R3

VECTOR FIELDS

Further Z’(z) > ð11 = 5 + D (independent of h). Put

LEMMA.

(2 . 3 . 6) such that

Proof we

+

0(zQ)

>_ 21 for small ð

1, there exists

an 8 E

]0,~i[[

Fm.

c

-

QzQ-1b1

1 +

For each

-

145

Let h E

Fm and put

H

=

reh.

For

z

=

z(Z) and (x, y)

=

h(z)

have

0 and P Q - 1 and a 0. induction for all on i, . that Suppose, by II and Let us abbreviate ... , F1 h(z) := (h(z),z ) :=(Fx~E, j E ~0, 1, 2014 1 }. and F2 :== times and obtain for We differentiate the equality the left hand side, using the higher order chain rule [A.R., Ya ] :

since a2

_

_

where

is some « universal summation over

C10)

properties jl

+

+

...

jk

isolate the term with k :>

(F2 h))(z) :>

=

=

i and

jp

>

1 for all

WIth tne

Let

us

i in the summation : :>

=

...,7~

/?e { 1, ...,~c}.

h)~Z)~

...,

i- 1

There exist C x functions

D’(H (F2 ~))(’) ç

0

=

Ak, k E ~ 0,1, ...,i DIH(FZ(h(Z))) - (D(F2

ç

;-1

Vol. 3. n° 2-1986.

- 1

},

such that ...,

we can

h)(z))

write

146

P. BONCKAERT

For the

right hand side we get

Intermezzo:

If E is a normed space, if L : E ~ E is an invertible SUBLEMMA. E is a continuous i-linear map then continuous linear map and if B : -

I

where B

(L,

...,

L)

I -r.. "

-

I -

T ’I. I 1

/T

is tne i-linear

map

1

1 T - ~1 II 7

aennea

oy

~’roof : 2014 Ubvious./. If

Let

we

us

apply this

make

an

in the

equality

estimate tor each term or tactor

separately

Annales de l’Institut Henri Poincaré -

Analyse

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VECTOR FIELDS ON

As

we

already

saw

in lemma

(2 . 3 . 5) :

symbol, as well as

Remark that this 0

R3

147

,

the

following,

ones

are

independent

1») because of the induction hypothesis ; this 0-symbol is Dih(z), by a independent of h since we can bound the II h E of constant independent F;’. =

...,

2. + 1k = In each term ot this summation we have j1 + So there must be 1, 2, ... , k ~ with jp f - 1. Hence, except for the case that ji1 jk = 1 and k = i, each term contains a j2 1 ~)_ factor Dkh(z) with k E {0,1, ...,f - 1 }; such a term is Suppose that ji = j2 = ... = jk 1 and k i. We can write ...

=

=

=

...

=

as a sum

of terms

containing Dh(z) as a factor, except the terms ot the torm

if

which is

=

we

replace (x, y) by h(z)

w e nave :

So if

write h =

(h 1, h2) ~ ( DF’Oh(z)) - h~i~(z) ~ ~_ ~ ~ we

Vol. 3, n° 2-1986.

we

get, since (x, y)

(1

+

~~x~ Y~

must be

replaced by h(z) :

148

P. BONCKAERT

e) Finally We end at : il1 i

because P

I

Q -

(2 . 3 . 7) LEMMA h(0) 0, if

1

0.

and a2

. - If h :

[0,5]] +

=

[0,5] Proof

on

D

00

-

B(o, ,u) is invariant under on ]0, ð] ] then h is

and if h is

if C x

0.

=

For all Z E ]0, ð]] we consider the sequence The invariance of the graph of h implies that we can write -

z. for alli E N, with in particular zo(z) z E ]0, zb] is of the form zi(z) then If Za E ]o, ~] and zb each zl(za) for some z E In order to prove the lemma it hence suffices to show the following: > 0 such that for all zo E [Zb, za ] for all j, s there exist za E ]0, 5 ] and and all i =

=

II

we can abbreviate this

shortly

zi

B B II ----

by writing

Let j,

=

From the

~~/1)/-/-

se

B1

>

=

Let us write

formula

recurrence

on

F~m we derive the existence of za

>

U

then for alli >_ 1 :

0 such that if

lor small za since a

/-/-

~J.

tor alli > 1 and from the estimates

and

v

u.

Applying this successively

we

get

~-11

Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS ON

[R~

149

On the other hand

II

," I

If

then for

Q - 1 ).

P Thus in that

(remember :

case II

1 /

B ) )

Choosing

we

have for

can find for all f =

We

constant

a

Ls such that for all

ze

[zb, za]:

~n(z)~ ~ Ls. ~~

t-1

From

+ t-i1

Vol. 3. n° 2-1986.

~2~ ~)

we

derive 2014~~~~ ~ "

so

So

150

P. BONCKAERT

We obtain :

for all i E Thus the case j 0 is done. Now by induction on j we prove that differentiate the equality =

for all

=

We

s e

j times (where h(z) _ (h(z), z)). Proceeding for that like in the proof of lemma (2 . 3 6) -

~

!!’B

. ~

_.

_._

we

find for the left hand side :

_..

__

where Ak is some ceo function; it is important to observe that Ak is linear with respect to the variable For the right hand side we get :

where the terms in the last summation +

oo we see I ir.

never

contain

Since

that

i_m _

’B I -

i

~

1I

AI - 0 - 1B

exactly like in the proof of lemma (2. 3. 6) which a priori might be unbounded ; which is, by the induction hypothesis, an

For the other terms we proceed but collect the terms containing

those terms contain a factor for any N E fil. Also -

So

we

-

_

n

v

.

T’Bo

v

_i v

v

find that tor all

Choose N

=

Q

+ s ; then we can find constants al

0 and B

j

>

0 such that

Annales de l’Institut Henri Poincaré - Analyse

non

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!R

VECTOR FIELDS ON

This estimate is of identical type the case j = 0. Now we may go obtain the desired result. D

as

the

on

151

started from when solving in the same way in order to

one we

exactly

(2 . 3 . 8). LEMMA. - There exists a neighbourhood V of (0,0,0) such that all orbits in V tend to (0,0,0) and those outside 1R2 x { 0 } are graphs of maps h satisfying the hypothesis of lemma (2. 3 . 7).

Proof - By means of the obtained Coo invariant graph f (h(z), z)z E [0, ð] ] ~ define the Ceo coordinate change

we

....

Put X G*X and write X riant we observe that =

From the

-

Since

Xy,

=

_

X

leaves the

inva-

expression of X we calculate that, for the standard inner product

[R2:

on

-

Because G does not alter -~

~ "-

......

oo

-

-

jets in (0, 0, 0) we can write for X : -"’"

_n

~.-

-.

-.

~

.

~

.20141

b 0 Let us write again (x, y, z) instead of (x, y, z). Since /(0, 0, 0) a and constant a we V of and since a can find 0, (0, 0, 0) neighbourhood c > 0 such that on V : =

~

^-

From this the result is Lemmas used in the

(2. 3 . 9) that

LEMMA. c

~......-

...... _

easily derived.

D

proof of proposition (2 . 3 ..1 ),

-

For each

>

case

II.

1, there exists

an 8 >

F§l’.

Proof The differences with the proof of lemma (2 . 3 . 6)

for

b) :

Vol. 3. n° 2-1986.

are :

0 such

152

P. BONCKAERT

for

e) :

LEMMA. There exist ~,~ > 0 such that if x in (0, 0,0) and j~, zi) B(0,~) [0, £ ] with lim sequence

(2.3.10)

is

-

a

=

.

graph of CQ coordinate change

then this sequence must lie

Proof -

we

With the

obtain for F

=

on

(Fx, Fy, FZ)

the

:=

G*F

that

0 on some neighbourhood of(0,0,0). for some a 2 Denote the transformed sequence (Xi, yi, Zi)iEN. We haveI ( xi + 1, Yi + ~ ) II if 8 is small. So then for all i : 1 1 1 .. ~ _ IIl 1 ~ 0 form -~ oo. Thus Xi Yf= 0, that is: the sequence lies on the z-axis, which is the transformed of the graph of hQ by G. D

( x_i,

=

(2 . 3 .11 ) LEMMA. - There exists a neighbourhood V of (0,0,0) on which all orbits of X starting outside the invariant graph leave V for t

-

-

Proof and

on

oo.

Precisely like in lemma (2.3.8) some neighbourhood V: -

~ rom this s a

we

obtain for

some

B

that the function V : ~3 -+ [R: (x, y, z) -~ ~(x, > 0, whence the result.

we see

Lyapunov function for X in the region z

emma used in the

proof of proposition (2 . 3 .1 ),

case

>

0

y) ~ ~ 2 D

III.

the map (Y, Z) : (2 . 3 .12) LEMMA. - For small /1,8> 0 and h E R2 : (y, z) F2(h( y, z), y, z) is a diffeomorphism onto [0,8]] - , ] at least) [2014~,~]] x [0, 8]. -

-

Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS ON

F’2~~ Y~ Z)~ Y~ z) _ « 1 +

z)~ Y~

Y~

where Roo is 00 flat along the So, in a short notation : ~

-

We have:

153

+

Y~

and has

z-plane

T.~

..,.

)R~

~ _...

Z)~ Y~ z)) +

zero

~--

Y~

z)~ Y~ Z)

z-component.

D1

D"",

D ~ ........

W

D(Y,Z)(0,0) Identity. Because of the inverse function theoand because for all h E > 0 such 1 there exist [[D h(y, that for all h E the map (Y, Z) is a diffeomorphism on [2014~,~] x [0, a]. Put Roc 0). If 8 is small enough we have for all y E [- ~c, /1] : =

rem

=

C

and tor all ze ~it

As

there exists

Proof -

..

-- B

~B

~~ P

.. n

x

is

simply connected,

LEMMA. - There exists a J1 an 8 >

We

0 such that

=

rh. For i )

ims

t

impnes

1

> U such that tor all

c

(2. 3 .12) holds. and ( y, z) ( y, z)(Y, Z) we

such that lemma

choose ~

Let h E F~, H

T

Suppose, by induction

lUl

m

~U, 8j:

...Pwi~ I ~ .

(Y,z~[2014~~jJ

(2 . 3 .13)

~~

17

=

0

r’""7"B. II

on

1, ... ~2014 1- J

=

II

B

n7 i

)).

have:

AI nDB

i, that

1

tlllU

=2014

1.

A ’ LJ1

brevity put

and put also Vol. 3, n° 2-1986.

Fi1

=

Fx, f’2 =

It

we

differentiate the

equality

154

P. BONCKAERT

H

i times then

F2 0 h (2.3.6) that

=

We estimate

as

we

obtain in the

same

way

in lemma

as

follows :

h)( y, z) expression for a) From we see that we can write (2.3.12) the

=

D(Y, Z)( y, z) obtained

lemma

where Mh( y, z) is some matrix with M~(0,0) 0 ; this because Q see the rescaling construction. Moreover we can choose > 0 such that for all m E and all ( y, z) E [ - ,u, ,u ] x [0, e]: =

-1 > P > 2 : m

>

1, all

Then

because of the induction on the llAk(h( y> Z» > y> ...,

hypothesis z) II.

and because of the uniform bounds

1

because here the same here in particular

reasoning

as

in lemma

(2. 3. 6) applies and because

for

each q E ~0, ...,~ } d ) From tnnales de l’Institut Henri Poincaré -

Analyse

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linéaire

VECTOR FIELDS ON

we

1R3

155

obtain

e) r many :

ii s is small we nave ior an t

E l u, ... , m j :

~~a .I

I

n/-11; -

Hence

(2 . 3 .14) LEMMA. - If E is small and if (xt, y~, [2014~,/~]] x [- /1, /1]] x [0,8]] with lim (~,Zf) (0, 0) =

v

T2014’/

is and

a

sequence in

B/’~~B v

/

Proof. Similar to the proof of lemma (2.3.10) with this time the coorchange -

dinate

r

Lemmas used in the

(2 . 3 .15)

is

a

~- 20142014 TT 20142014 ~~Yl7 7~

proof of proposition (2.3.1),

LEMMA . - For

sufficiently small 8

diffeomorphism onto at least [2014 ~ /1]] We have (X, short notation :

Proof so, in

a

1 for

As [[

independent

of h.

Vol. 3, n° 2-1986.

z)(x,

z +

x

>

case

IV.

0 and for h

E

the map

[0, 8].

h(x, z), z)) + R ~(x,

remark that the last matrix is

z), z)

an

156

P. BONCKAERT

ea

D(X, Z)(0,0) =

We have:

0

.

Because of the

remark

foregoing

> 0 independent and the inverse function theorem there exist small is a diffeomorphism. such that (X, Z)[ on For all x E [- /1, /1]: 8 + EQg(x, h(x, 8),8) > 8 if ~ is small because of the estimates on g on V. + Also for all ze [0, s] and 8 small h(,u, z), z) > /1 and X

~(- /1)

h( - ~c, z), z)

+

-

,u.

Hence, since (X, Z)( [ - ,u, ~c ] x [0,6]) is simply connected,

LEMMA.

(2.3.16) m >

1, there exists

Proof

a)

We

an

Copying

-

We put F

-

=

can

There exists a J1 8 > 0 such that

0 such that for each

>

c

the scheme of lemma

(Fx, Fy, F )~ Fi = Fy~ FZ

=

(2. 3. 6) this

time

one

has :

F~).

write :

hence

b) and c) : d ) here :

the

same

so

for small

z

since

0 and

bi

>

0.

D

Annales de l’Institut Henri Poincaré -

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157

VECTOR FIELDS

~~ . ~ .1 i ~J

LEMMA.

-

11 8 is Small ana 11

lim

yi,

IS a

sequence

ill

and

(Y~~ z,) (0, 0) F(x;, y~~ z,)=(~-i, y~~ Z-~) [0, s] with [ - p, /1]] > the then must lie on this (i 1) sequence graph of hQ. the to of lemma 0 proof Proof - Analogous (2.3.10). x

(2. 3 .18)

LEMMA.

-

which all orbits of X t

-

=

There exists a neighbourhood V of (0,0,0) on outside the invariant surface leave V for

starting

DC.

-

Proof

- After the coordinate

change

r -

-

obtain a vector field X GX whose y and form (write again x, y, z instead of x, y, z) : we

:=

,

D

.

anu

wnerc j

Take a bounded such that on V :

are

of the

~.. ,

neighbourhood ~l

V

of(0,0,0) and constants a2, b 1, b2 > 0 -

Now the lemma easily follows. D This completes the proof of proposition ALL

components

u.

v

(2.4)

z

(2.3. 1).

THE EIGENVALUES ARE ZERO.

Here we will meet all situations II. A, II. B, II. C of the main theorem. Since we work with germs X of flatness zero, that is: 0, and since the z-axis must be formally invariant under X, we can assume, up to a linear change of coordinates preserving [R2 x {0} and {0}2 x [R, that the

1-jet

lines of this

is y~ ;equivalently: the matrix A introduced in the first c.~

chapter

IV is:

fo ana

Co

=

u.

Vol. 3. n° 2-1986.

it

158

P. BONCKAERT

of the previous and (2 . 3 .1 ). With (2 .1.1 ), (2 .1. 3), (2 . 2 .1 ) « reducing » we mean : to deform the vector field by means of (sometimes degenerate) coordinate changes which do not alter the nature of results such as for example « having oo contact », « being a cone of finite contact », etc. In fact all the cited cases will occur. We will try to reduce, in in propositions ( 1.1 ),

sense, this

some

case

to one

cases

(2 . 4 .1 ) PROPOSITION. Suppose X E G3 satisfies i ) the z-axis { 0 } 2 x [R is formally invariant under X -

ii) X is non-flat

Üi)

along

the z-axis

then

[R2 whose graph (germ) a) there exists a Ceo germ h:([0,oo[,0) z oc E is invariant under X and with j~(0) 0 { (h(z), z) [0, [} a exists cone K of finite contact there b) around { 0}2 x [0, oo [ such that -

=

in K

we

have situation II. A, II. B

or

II. C of the main theorem.

lemma (11.3.2.4) of X is of the form

Proof - Applying nent

0 0, 0 0 with y(0, 0)

where

is

fi, f 2,

~

0. Since j1 X

gi, g2,

hi, h2,

(0) == y~y 2014 ~x

y and

we

we can

S~

are

vi ) S, is a germ of a vector field with oo flat along [R2 x { 0 }. Let

me

explain

and y ; property

this

a

may

little bit. First

we

assume

that the z-compo-

in the ffollowing 11 win form : write X m

Cx germs and

zero 2014 -component and which az collected all terms linear in x that the z-axis is formally

ii ) together with vi ) reflects

Annales de l’Institut Henri Poincaré -

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159

VECTOR FIELDS ON

invariant; property iii) simply means that hl and h2 don’t contain terms linear in x and y; property vi) indicates that we « absorbed » the ~ terms of the component of X in y. cz Allthough it is not crucial, we can spare some ink and calculations if we observe that we may assume 0. Because if not, we replace X by .

-

this germ is Ceo equivalent with X put the matrix

by means of the identity

map. We want

to

r~/-B

i i

handy form by means of a coordinate change. fl + g2 denote the trace of this matrix. This important role in the sequel. in

a more

Let T

If

we

=

play

an

put r

then

trace will

one

n 1

1

easily checks that

Note, by the way, the characteristic

that 1 (f1 - g2)2 4

equation

+ g1

is 1 4

times the discriminant of

of M. All this suggests the

following coordinate

change : /

As

Vol. 3, n° 2-1986.

1

~



160

P. BONCKAERT

straight forward calculation that the new vector in a point (x, y’, z) = ~(x, y, z) can be written in the following from : obtain from

we

a

where hl, h2, y, S ~ satisfy analogous properties as ii), For brevity we write

we can

write down

iii), iv) and vi) above.

~

~

Then

~,~X

in the form

which will become clear in

(new h2) :

perform

For

reasons

z

u~ of the z-axis, just like in the proof of proposition (2. 3. 1)

=

by

means

we always restrict our Calculating straightforward we find

us

a

moment we

a

rescaling case

III,

of the map

Remember that

Let

field

attention to the upper halfspace. if and only if that R*X’ =

simplify the notations by writing again X, y, z,

h2, Q, y, S x instead

Annales de l’Institut Henri Poincaré -

Analyse

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VECTOR FIELDS 0~

of respectively X’,y’, u, h1o R,

put v(u)

=

T(u2~.

Then _

we

h2 R, 2Q - 1, o

something

obtain ,

161

!R 3

1 2 o R, S x

R ; let

a

us

also

of the form: ,

~.

_

where, for the sake of clearness, the following properties hold : /1""’Io.’B.

..... ,.. ~ -...

’"

..

v) Q > 2 a and which is vi) S~ is a vector field with zero --component az along ~2 x {0 }. Let me explain why it is no restriction to assume that

oo

flat

perform a blowing up idea similar to the one in the proof 01ofprothe position (1.1) as follows. Blowing up X n times gives a vector field

We

can

form r /i

1 ~

Sx satisfying similar properties as ii ), iii ) and ri) above. 0, The fact that y(0, 0, 0) # 0 should explain our assumption exist there ..., Q 1} which we take for granted from now on. So

for

h2,

some

and

such that

Vol. 3, n° 2-1986.

162

P. BONCKAERT

~

The to

«

«

strongest »

term in the

~

~

~

expression of X

is

of

y- . We want

course

C/~L weaken » it with respect to the other entries in the matrix

This situation is comparable with the problem : diminish the entries « 1 » emerging in the Jordan normal form of a square matrix. Inspiring ourselves on this, we consider for each P~N the coordinate change

P will be chosen in

is

a

we

For

for

sort

of partial

a

according

moment,

to the

occuring

cases.

In fact ap

blowing up.

have

our

vector

some

field here this

gives :

satisfying property u~)

above.

Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS ON

!R~

163

Intermezzo.

Let

me

indicate here

why it was necessary to rescale the z-axis. Take the

example : rr.l

Since the only allowed choices for P are here P 0 and P 1, we cannot weaken the entry « 1 » without creating a similar problem. However after the rescaling we have =

rA

and

by taking P

=

1

we are

End of the intermezzo. We distinguish the cases Case jP1g(0)

Choose P

Here

Since

we

=

lead to the matrix

=

Pi. We distinguish Pi

Q have

=

Vol. 3, n° 2-1986.

11

0.

0 and

0.

=

Subcase Pi

=

0

Q -

1 and

Pi = Q -

1.

(write again x, y, z instead of x, y’, z)

we

may write that

1.

164

P. BONCKAERT

by zP. We can write :

We devide the vector field 03B1P*X 2014 /,

_

2014t ~

B

1

In order to get rid of the possible unboundedness of the terms P hl(x, yzP, z) z 1 and 2P h2(x, yzP, z) it suffices to blow up the latter vector field 2P times z

(without dividing of course); indeed: thanks

to the

property iii) above

we

have ,

if we blow up 2P

P...

,

...11")...

í"B./II

times, the formulas in (II . 3 . 2. 3) imply that

factor z2P. This blowing up construction does not alter the This 1-jet is :

there appears

a

B

i,

,

1

1-jet

in 0

of ~

~

.

Since a 1 # 0, we clearly have a vector field satisfying the assumptions of proposition (2.1.3). The conclusions of proposition (2.1.3) remain valid for our original vector field because of the following reasons :

a) 03B1-1P 1( { (h(z), z) z E ]0, of a

b)

map

oo

if we have

tangent

a cone

oo

[ } ) u { (0,0,0) }

to the

z-axis in 0,

as

is the germ of the well as

graph

K of the form

then 03B1-1P 1 transforms it into r

I

This set contains the __

.

,

.

cone _

_1

Annales de I’Institut Henri Poincaré -

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!R 3

VECTOR FIELDS ON

rn wnicn we nave

or

165

ui the mam theorem

the case; finally the rescaling R transforms this last

accoramg

to

f/.~ .. -B2014m)2 ..

Subcase With

field

P1 = Q a same

rn - -

cone

rI

7

into

.

7

IB. B. ’")

/

D ,

1.

construction

z ( ~ Y~ )

as

in the subcase above

with this time

we

2014component p oz

a

obtain

a

After

’Y( ~ Y

up 2P times (in order to get rid of unbounded terms) field satisfying the assumptions of proposition (1.1). We can conclude just like in the subcase above.

blowing

vector

we

obtain

a vector

Case jP1

g(o) ~

There exist

0.

P2 E ~ 1,

and ~2 ~ 0 such that

...,

_i _2~

Choose P

=

-

~2Po .

I

~/_2Po+2B

P2 . We distinguish three subcases : P2

Pi1

Q - 1,

or

Subcase P2

P1 ~ Q -

1.

We have B

w e aeviae inis vector neia

Vol.

3,

we can

n° 2-1986.

oy

i ~

1

z- ana obtain :

c

1

Agam

.

get

nd ot the unboundedness ot some terms

by blowing up

166

2P

P. BONCKAERT

times, just like above.

Y. The

Denote the result of this

blowing up construction

by

1-jet

of Y is

’"’

-,

0, then the eigenvalues

If a2

I and 0. Hence

are

apply proposition (2 . 2 .1) to obtain the situations II. A or II. B 0» of the main theorem. The same remarks a) and b) in « case jplg(O) hold. If a2 > 0, then the eigenvalues are 0. So up to a linear Y satisfies change of coordinates preserving ~2 x { 0 } and {0}2 the assumptions of proposition (2 .1.1 ). Blowing down this situation, we still have a Cx cone K of finite contact and a 2-dimensional C° subcone S like in situation II. C of the main theorem. Next contains 4 C x 1 cone K’ of finite contact just like in the foregoing case; observe also that 03B1-1P ag preserves the property «having 00 contact with the z-axis » ; S’ is a C° 2-dimensional subcone of K’ ; the rescaling R also preserves the property « having oc contact with the z-axis in 0 » ; R(K’) contains a C’~ cone of finite contact and R(S’) is a C° 2-dimensional subcone of R(K’). All this shows that, for our original vector field, we are in situation II. C of the main theorem.

we can

=

a2 , - ~/~2,

:=

Subcase

P2

We have

Dividing

=

Pi

Q ~

1.

,

this vector field

,

,

by zP r

i

we

obtain : ,,--,

-

Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS

mow tms

vector

up

zr times to

field has

a

get

ON R3

167

na 01 ine unoounaea terms,

i ne

resuitmg

1-jet /1

/

v-_,

1

B

~

Since the trace of the matrix

is

a1(~ u)

according Next

we nave ai least one nonzero

we can

Subcase

P2

With

eigenvalue.

rience we can

to the case,

=

propositions (2 .1.1 ), (2 .1. 3), (2 . 2 .1 ) conclude just like in the previous subcase.

(2 . 3 .1 ).

vector field

1z (Xp*X

P1 = Q - 1.

a same

construction

as

above

we

obtain

a

~ with So

a

apply,

or

P

2014- component zy(x, yzP, z).

we can

apply proposition (1.1).

§ 3 . Proof

D

of the main theorem (1.2.1) with of the C° result.

exception

This is merely a summary of all the foregoing. Take a maximal directed sequence of blowing ups of X along D (definition III.1.3). If this sequence is finite, then apply proposition (III.1.4) to obtain situation I. If this sequence is infinite, then, using proposition (III.1.5), D is formally invariant under X. Theorem (111.2.1) implies that, after a finite number of blowing ups, we are led to a vector field (germ) of flatness zero. Now the theorem follows from propositions (1.1), (2.1.1), (2 .1. 3), (2 . 2 .1 ), (2 . 3 .1 ) and (2 . 4 .1 ), since these contain all the possible cases of flatness zero and since we assume that X is non-flat along D. D V. PROOF OF THE C° RESULT IN THE MAIN THEOREM (1.2.1)

§ 1. Definitions

and notations.

We want to provide « universal models » for the situations II. A, II. B and I I . C obtained in the main theorem (1.2.1). For that purpose we introduce : Vol. 3. n° 2-1986.

168

P. BONCKAERT

( 1.1 )

DEFINITION.

-

The

following

germs of vector fields

called the standard models for situation II. A resp. II. B resp. II. C of the main theorem (I . 2 .1 ). are

( 1. 2)

DEFINITION.

-

is called the standard

The germ of the set

cone

around the z-axis.

§ 2. Let us state here in a more the main theorem (I.2.1).

The C° result.

precise

way the assertation announced in

Let X E G3, let D be a direction such that X (21) PROPOSITION. leaves D formally invariant and such that X is non-flat along D. Then there exists a cone K of finite contact around D, a C° cone K’ K~ containing K such that the germ XK’ is C° equivalent with either or SBKS or Sc Ks, according to the fact that X is in situation II . A resp. II. B resp. II. C of the main theorem (1 . 2 . I). Moreover in situation II. B we have C° conjugacy. -

Proof this).

We may

assume

that D is the z-axis

(see part

III for comments

on

know that, after a finite number of blowing ups, after possibly rescaling of the z-axis, after possibly a partial blowing up and after putting in normal form, we are always lead to a vector field Y of one of the following types : (change the sign of X if necessary; with « flat terms » 0 plane) we mean terms Jo flat along the z From part IV

we

a

=

1) the eigenvalue of Y along the z-axis is to

the

z

=

0

plane

is

a

0 and the restriction of Y

hyperbolic expansion; Annales de l’Institut Henri Poincaré -

Analyse

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169

VECTOR FIELDS

with

a>0, b>0, /i(0,0,0) ==~(0,0,0) 0, y(0,0,0)

0;

=

3) the restriction of Y to the z and the z-component of Y is 4) the restriction of Y to the z and the z-component of Y is

=

f(O,O)

=

6)

Y has the

7))

Y

0, g(0, 0, 0) same

3~

form

y, z)y 2014

10)

Y

=

same

y,

form

0;

in 5 but with this time

.f ( ~ Y~

+~

/(0,0,0)>0~(0,0,0)0; 8) Y has the same form 7(0,0,0)0; 9) Y has the 1’(0, 0, 0) 0 ;

0, y(0, 0, 0)

>

as

0

~B

/ ~

with

plane is a hyperbolic expansion z) with y(0, 0, 0) 0, Q > 2 ; 0 plane is a hyperbolic contraction z) with y(0, 0, 0) 0, Q > 2 ;

=

+

y( ~

g(0, 0, 0)

y, z) 2014 + flat +

0;

terms with a >

as

in 7 with this time a

0, f (0, 0, 0)

as

in 7 with this time a

0, f(O, 0, 0)

z)x ~ ~x

+

+

y,z) ~ ~z

0, 0,

>

0,

+ flat terms with

0, a > 0, y(0, 0, 0) 0 (nota bene : we have interchanged the and y compared with the situation in proposition (IV. 2 . 3 .1 )). One has the following table :

j(O, 0, 0) role of

x

Note that the operations (blowing up, rescaling, etc.) are homeomorphisms of [R2 x ]0, oc [ with the property that a sequence tending to the = - 0 plane is transformed into a sequence tending to the z 0 plane. =

Vol. 3, n° 2-1986.

170

P. BONCKAERT

Roughly spoken, the idea is to construct in the origin a local C° equivalence with the corresponding standard model blown up once. Moreover we take care that the homeomorphism, realizing the C° equivalence, transforms sequences tending to the z 0 plane into sequences tending to the z 0 plane. When returning back the whole way this will assure the continuity in (0, 0, 0) of the desired C° equivalence for our original vector field X. We assume that for each considered situation there has been blown up at least once. =

=

Situation II . A. We blow up

This

blowing

once

the standard model SA and get

up transforms the standard

cylinder { (x, y, z) x2

+

y2 - 1, z

>

cone

KsB{ 0 }

into the

(full)

0 }.

out just like in lemmas (IV. 2. 3. 8), (IV. 2 . 3 .10) we can that the z-axis is invariant under Y. We can find a small cylinder B(0, ~c) x ]0, 5 ] around the z-axis such that { (x, y)I X2 + y2 - ,u2 ~ x ]0, 5]] is transversal to the orbits of Y: for types 1 and 3 this is clear from the hyperbolicity (provided decent coordinates are chosen) ; for types 5 and 7 we’ consider the function G(x, y, z) = x2 + y2 and observe that for type 5:

- By flattening

assume

:=

y, z) + flat terms and for type 7 : ( VG(x, y, z), Y(x, y, z) ~ ==2(x~ + 2ax2 + + flat terms ; VG(x, y, z), Y(x, y, z) > == f(.r, ~.7, in both cases we have VG(x, y, z), Y(x, y, z) > > 0 on V/l-,ð provided ~ and 6 are small; hence the orbits of Y are transversal to the level surfaces of G in

Moreover, if 6 is the planes z zo, 0 between Y |V ,03B4 and chosen such that =

To

see

this

we

small, then the orbits in

are also transversal to 03B4. Now it is easy to construct a C° equivalence SA |{x2+y2~ 1 and 0z~03B4}; the homeomorphism h can be

proceed

as

follows. Take the

homeomorphism

Annales de l’Institut Henri Poincaré -

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VECTOR FIELDS ON

Extend n to

171

as follows: u

then its

positive

orbit for Y intersects {(x,y, z) |x2 + y2 /12, 0 z 5} a first time in a point, say, define y 1, yo, zo) to be the intersection of the of orbit the plane z for with negative SA z1) Zo; finally define for 0 ð. 0, 20) = (0, 0, zo) zo =

N

=

Situation 77. B. We blow up the standard model

SB and get ~

N

1 nis vector neia is transversal to tne 1-1 _ 7 ~v

1x .

,1

.,

I v-2

-

nanspnere.

-v-2 _J ,,2 ,I

,,2

....L

transversal 10 me orons 01 Y : ior

....L

type

-2 _ A

no...

’7~ 2014 ~~ ~~, 4 tms ciear from the

hyperbolicity

and from y(0,0,0) 0 (provided decent coordinates are types 6 and 8 we consider the function G(x, y, z) = x2 + observe that for type 6:

m both

~BB

..

~,

_

1_

~t100

/~~ /

Consider the

homeomorphism .

--

--

I

y2

’)....0+ 1...~~....

+

z2 and

_B

U on a small set

cases ( VCJ(x, y, z), Y(x, y, z) > ~~

,.,.B

w

chosen) ; for

.. .

~~

...

2

, "’B

..

Extend h to Vð as follows. Let and 03C6B denote the flows of Y resp. SB’ For each (x, y, z) E Va there exists a t >_ 0 such that ~y(2014~ (x, y, z)) ~ Hi. We force the conjugacy to be true on Va by defining LI - -

we cnecK me

-

-B B

JL

required property

/.

1_l 1 /~l__ __ _B111 B

ior

yi,

oe a

sequence

m

v03B4

denote the sequence 0). Let (ti times » such that ~(2014f~ Suppose by contradiction y~ the z-components of a subsequence would stay

tending to the z of « that

-

Vol. 3, n° 2-1986.

=

0 plane (that is :

lim zl

=

172

I

P. BONCKAERT

M

>

0 for

some

constant M. This

implies

that sup tik

+

Hence

~6~

ie

z-components of ~y(2014~ (x~k, ylk,

o we

have

a

decent

conjugacy

h between

tend to zero. A contradiction. and

preimage h 1( ~ (x, y, z) + y2 1 and z > 0}) still contains a ylinder around the z-axis in Va. Returning this situation the whole way ~ack to our original vector field X this gives us the desired cones and onjugacy. .’he

ituation II . C. We blow up the standard model

Sc and get

1 the level surfaces of g are transversal to the Hence in the region z of orbits Sc. Take 0 b~ 1. Take a2 > 0 so small that the intersections of the level surface G-1( - ~2) with the planes y a2 and y a2 are circles C2 z the 1. See inside 2 from on. now figure region resp. D2 =

FIG. 2.

-

=

-

Sketch of the first octant. Annales de l’Institut Henri Poincaré -

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173

VECTOR FIELDS

We also consider the level surface G ~(1); this is a two-leaved hyperboloid. Next we consider the surface obtained by letting flow all the points of the circle C2 until they hit the level surface G - l( 1 ). We do the same x ]0, x [ a region R2. thing for the circle D2. In this way we enclosed in we that the out assume 0 By flattening may y plane is invariant under Y. We want to make an analogous construction as above for Y. We have for type 2: =

and for type 9:

ana tor

type

1U:

/ K7/U/,,

..

_B

So for all three types we can find in V:= W n ([R2 x ]0, t [ ) :

a

neighbourhood W

of (0,

0, 0)

such that

miniature version of the construction for Sc. 0 we can make the following construction inside V. Consider the level surface G - 1( ð 1)’ The intersections of it with the planes

we

want to

make

For small

5i

a

>

-

~ v

=

5i

and y = -03B42 03B12

surface obtained

by letting

hit the level surface

are

circles

flow all the

G-1(03B41 03B42).

Ci

resp.

points

We do the

Di. Consider also the

of the circle C i until

same

r

Second

we

Vol. 3. n° 2-1986.

extend h to

for the circle Di.

thing

In this way we enclosed a region Ri in V. Now we try to make an equivalence between define the homeomorphism

and ~

ç:

Ras follows. Require that

a

they

Sc

First

we

Î

level surface 7

174

P. BONCKAERT

(a1 e 2014 5i, 2014 )

is

mapped

onto the level

(x, y, z) E Ri lying in a level surface where the negative integral curve of time the level surface

of

G-1 (03B42 03B41 ai

we

surface

,

for

y 1, Z1)

consider the point

through (x, y, z) hits for the first we define G"~(2014 5i); h(x, y, z) to be the intersection

with the

Y

yB zl .

positive integral curve of Sc through

We check the required property for h. 0. sequence in Ri with lim zi

Suppose

that

(xi,

is

yi,

a

=

Let (xI

, y1i, z1i) be the point where the negative integral curve of Y through

hits for the first time the level surface G’~(2014 tends to the y 0 plane, we get that sequence (xl, yl, 0 plane. tends to the z D

~i).

Since the

=

yi,

=

(2 . 2) [Cam ] .

REMARK. - We have used

VI. SOME

some

ideas

comparable

to

those in

EXAMPLES, COUNTEREXAMPLES QUESTIONS

AND SOME

§

1. A

counterexample

and

some

questions.

might pose the question whether every germ in 0 E [R3 of a Cx satisfying a ojasiewicz inequality (see definition I.1.17) one-dimensional invariant manifold, or equivalently, possesses a whether it possesses an integral curve tending to 0 (in positive or negative time) in a Ceo way (by tending to 0 in a Cr way we mean : if we add the origin to the integral curve, we obtain a C~ invariant manifold). The answer is no. We give an example of a germ for which no integral curve can tend to zero in a C2 way; the germ has nonzero 1-jet. One

vector field

(1.1)) fies

EXAMPLE.

-

Let X

=

+

+

ojasiewicz inequality. No orbit of X Proof - a) Blow up X in the x-direction: a

x2 ~ ~z. can

Observe that X satis-

tend to 0 in

a

C2 way.

Observe that

Annales de I’Institut Henri Poincaré -

Analyse

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VECTOR FIELDS ON

has

just

one

singularity

in

(0, 0).

!4°

175

Blow up X in the x-direction : ,

-,

,

Observe that

nas no

singularities. up X in the

h) Blow

y-direction : ~

Observe that

has 11U

sing

c) Blow

up X in the z-direction : ,

Observe that

~~~-~

Now

we are

by blowing

able to describe the vector field X on S2 spherically (see for example II. § 1 or [Ta,

up X

obtained Du2] for defi-

nition and construction). The only singularities of X IS2 x {0} are (1, 0, 0) and ( - 1,0,0). If an orbit 811 of X tends to 0 in a C2 way, then X must have an orbit 82 which tends in 1 a C~ way to ( 1, 0, 0) or ( -1, 0, 0) since these are the only singularities on S2 x { 0 }. If we blow up X in (1, 0, 0) or ( - 1,0,0) we don’t have a singularities any more, except in the « corner » : see figure 3. This contradicts the fact that 82 tends C1 to (1, 0, 0) or ( -1, 0, 0). Q

( 1. 2) REMARK. - The vector field X in example ( 1.1 ) must have an orbit in the first octant(.v, y, ~) E [R3I x >_ 0, y >- 0, z > 0 } tending to 0 in a C° way. One can see this as follows. Denote Vl = {(x, y, z) E [R3 (x 0 or y 0 or z 0) and x > 0 and and and and z > 0 r > 0 x+y+z 1} V2 == { (x, y, z) e ~ ! jc > 0 =

and y > 0 and Vol. 3, n° 2-1986.

z >

=

=

0 }. V3 is the first octant. See figure 4.

176

P. BONCKAERT

FIG. 3.

-

Blow up X in

(1,0, 0).

FIG. 4.

Each t

-

point of vl B ~ 0} +00. This follows

the function

G(x,

y,

enters the first octant

from the Since

immediately

z) x + y + z. VG(,r, y, z), X(x, y, z) ) = =

V3 and

y +

z

leaves it for of X. Consider

never

expression + x2

Annales de l’Institut Henri Poincaré -

Analyse

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177

VECTOR FIELDS

the

positive

consider the

orbit of

a

point

.-........-

""""’4.""""’’’’’’------

T(u) _ -

V1 B { 0 } intersects V2 L,)f 0 } of a point

negative orbit {

£

If

of

‘,.~, .. ~ J

’JJ, then

T/,.B _

.

lim

necessarily

r) leaves V3 in negative time in

some

’B1 in t ~

a

point

or

V2

v E

to 0 if

to the

lim

u)

-

r E

-.---......

point,

---"’’’’’’’’’0

0. If

=

Conversely,

V~. Put

..~- 1 - n

I

-v-

L --, ..&. s...1..~,..__J

once.

----

T(v)

---------------

> - ex)

~_.

then

say,

r.- 1,; ,

point of Vi where the negative orbit through v hits Vi v) 0. Certainly ViB { 0 } since the positive =

orbit of each point of V1B{ 0 } hits V2. Since V2 is compact and since V1B{ 0 } is not compact, necessarily h(V2) V1. Hence there must be a point in V2 tending to 0 for t - - 00. =

I don’t know whether this vector field X possesses (1 . 3) QUESTIONS. orbit tending in a C~1 way to 0. I generalize this question : does there exist a germ in 0 E [R3 of a Cx vector field satisfying a xojasiewicz inequality without an orbit tending I to 0 in a C° way? in a C~ way? (in positive or negative time). -

an

vector fields having a Coo dimensional invariant manifold.

§ 2 . Examples of one

A very

general observation from

the

chapters

III and IV is :

OF THE PROOF OF THE MAIN THEOREM. If X E G3 D direction leaves formally invariant (that is: invariant by the oc jet) and if X is non-flat along D then there exists a C x one-dimensional invariant manifold x tangent to D. D If we consider germs in 0 E [R3 of vector fields satisfying a Mojasiewicz inequality, it hence suffices to look for conditions which guarentee the existence of a formally invariant direction. In general it may be a difficult task to investigate whether a given vector field has a formally invariant direction. Some tools for this can be : apply the normal form theorem (which we will do in some examples hereafter); or: try to blow up the vector field until you find a singularity having a formally invariant direction by the normal form theorem. An important result in this sense is :

(2.1) CONSEQUENCE a

(2.2) THEOREM [B. D. ]. - If X E G3 satisfies a ojasiewicz inequality DX(0) has eigenvalues 0, i i~. - i i ( i E (1~ B ~ 0 } ) then X has a C x

and if A

:=

3. n ~-1 y~b.

178

P. BONCKAERT

one-dimensional invariant manifold D tangent in 0 to the rotation axis of etA, t # 0. Moreover there exists a cone of finite contact around D in which we have situation II. A or II. B of the main theorem (1.2.1). In the same spirit we can apply the normal form theorem to other types of singularities with nonzero 1-jet. For many cases the result is well known, but let us list them for the sake of completeness :

(2 . 3)

MORE

EXAMPLES.

-

Let X e G, Xi = DX(0).

Annales de l’lnstitut Henri Poincaré -

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VECTOR FIELDS ON

Proof.

179

2014 Denote _

where

I~$3

A,

are

_

(~

.

real constants r~

_

~

(zero rv

is

1

allowed).

Put

i

where h > 2 (see formulation of normal form theorem also denote, for h >_ 2, 0 j h, 0 i _ j :

(I. 1 21 )).

Let

us

i ms is a oasis ior n .

After

a

trivial calculation

one T I

finds that B

where

So D has On Hh

a

diagonal matrix with respect to this basis. put the standard inner product with respect

we

Vol. 3. n° 2-1986.

to

this basis.

180

P. BONCKAERT

For as

O? c002 ~ 0. example 1 we see that complementary space (Im D)1; an element

2014

contain the terms e001 = zh

nor

3.B’

e002 = zh

e002 ~ Im D. Take

so

(Im D)1

of

2014

cannot

since

~y

Hence in the normal form the z-axis is formally invariant. For example 2 the same reasoning applies; for example 5 we see that ehn3 E Im D and we can follow an analoguous reasoning. A similar method works for examples 3, 4, 6. Next we calculate that

so

S 1 has a matrix of the form

where A is an upper triangle matrix with zero diagonal elements is nilpotent). Then one easily calculates that S 1 must be nilpotent. So for examples 7, 8, 9 we can write

(so A

where D is semi-simple and Si is nilpotent. The fact that Im D c Im [X 1 - ]~ implies, in the same way as above, the results claimed in examples 7, 8 and 9. Concerning example 10 we find that the matrix of S2 is of the form

where B is an upper has a matrix

triangle matrix r

and

one

easily

..

-

with vi

calculates that S3 must be

zero

diagonal

elements. So 83

/~ ~)

nilpotent.

Annales de l’Institut Henri Poincaré -

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181

VECTOR FIELDS

[X 1, - ]~ D + S3 again reasoning as above can be made. For examples 11 and 12 we find As

=

,

so

e001, e002~ Im

[Xi, 2014 ]h

1m D

c

1m

[7(1, - Jh

and

the

same

that ’B

~

and

we can reason

like before.

D

In case j1X(0) 0 there is, as far as I know, very (? . 4) REMARK. little known on normal forms. But as already said, blowing up may sometimes help. This is the case for a C x gradient vector field X = grad f : F. Takens 0 then X has showed me, using a blowing up argument, that a ex invariant manifold, in all (finite) dimensions. In example (1.1) 0 was not an isolated zero of the first nonvanishing jet. Even the assumption that 0 is an isolated zero of the first nonvanishing jet (which implies that the radial eigenvalue in a singularity of X IS2 x {0} is nonzero) is not enough to have an invariant direction : =

-

EXAMPLE.

(2.5)

Observe that 0 is

-

an

Let

isolated

zero

of J2X(0). No orbit of X

can

tend to 0

in a C2 way

Proof - a)

Blow up X in the x-direction : a

i

i

nas

just

one singularity

m

(U, UJ.

Blow up Xx in the x-direction :

and observe that

has

no

singularities.

3. n° 2-1986.

~

,

182

?. BONCKAERT

b) Blow up X in the y-direction : and observe that

has

no

c)

singularities.

Blow up X in the z-direction : ~

nd observe that

has no singularities. Now we can conclude

just

like in

(2.6) .REMARK. This example This can be seen from the expression

example (1.1).

D

to 0 in a C~ way. is a hyperbolic expansion.

has orbits tending

(2. 7) SOME FINAL REMARKS. - a) Concerning the main theorem (1.2.1): when X is analytic, it is not necessary that (one of) the obtained invariant manifold(s) is also analytic, as was pointed out to me by the referee: for X

=

x - + ((yY - z2 a ~+ z"2014OZ

the z-axis have

an oo

all the invariant directions tangent to g

jet in 0 of the form

b) Concerning proposition (V . 2 .1) about C° equivalence with standard (but cannot prove) that « C° equivalence » can be « C° replaced by conjugacy ». models: I presume

REFERENCES [Ar] [A. M.] [A. R.] [B. D.]

[Be]

V. ARNOLD, Équations différentielles ordinaires, Éditions Mir, Moscou, 1974. R. ABRAHAM and J. E. MARSDEN, Foundations of Mechanics. Benjamin, London, R. ABRAHAM and J. ROBBIN, Transversal Mappings and Flows. Appendix by Kelley, Benjamin, New York, 1967. P. BONCKAERT and F. DUMORTIER, Smooth Invariant Curves for Germs of Vector Fields in R3 whose Linear Part Generates a Rotation, to appear in

Journal of Differential Equations. G. R. BELITSKII, Equivalence and Normal Forms of Germs of Smooth pings. Russian Math. Surveys, t. 33, 1978, p. 107-177. Annales de l’Institut Henri Poincaré -

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non

Maplinéaire

VECTOR FIELDS ON

~3

183

H. W. BROER, Formal Normal Form Theorems for Vector Fields and some Consequences in the Volume Preserving Case, in: Dynamical Systems and Turbulence, Warwick 1980, Lecture Notes in Math., t. 898. 1981. [Cam] M. I. T. CAMACHO, A contribution to the Topological Classification of Homogeneous Vector Fields in R3 (preprint). [Car] J. CARR, Applications of Centre Manifold Theory, Springer Verlag, New York, 1981. [Di] J. DIEUDONNÉ, Foundations of Modern Analysis, Academic Press, New York, 1969. [Du1 ] F. DUMORTIER, Singularities of Vector Fields on the Plane. Journal of Diff. Eq., t. 23, 1977, p. 53-106. [Du2] F. DUMORTIER, Singularities of Vector Fields. Monografias de Matematica, t. 32, IMPA, Rio de Janeiro, 1978. [D. R. R.] F. DUMORTIER, P. R. RODRIGUES and R. ROUSSARIE, Germs of Diffemorphisms in the Plane. Lecture Notes in Math., t. 902, 1981. [Go] R. E. GOMORY, Trajectories tending to a Critical Point in 3-space. Annals of Math., t. 61, 1955, p. 140-153. [Gu] J. GUCKENHEIMER and P. HOLMES, Nonlinear oscillations, Dynamical Systems and Bifurcations, Springer-Verlag, New York, 1983. [Ha] P. HARTMAN, Ordinary Differential Equations. Wiley and Sons, New York. [H. P. S.] M. W. HIRSCH, C. C. PUGH and M. SHUB, Invariant Manifolds. Lecture Notes in Math., t. 583, 1977. [Ir] M. C. IRWIN, Smooth Dynamical Systems, Academic Press, New York, 1980. [Ke] A. KELLEY, The Stable, Center-Stable, Center, Center-Unstable, Unstable Manifolds. Journal of Diff. Eq., t. 3, 1967, p. 546-570. [M. M.]J. E. MARSDEN and M. McCRACKEN, The Hopf Bifurcation and Its Applications, Springer-Verlag, New York, 1976. [Na] N. NARASIMHAM, Analysis on Real and Complex Manifolds, North-Holland, Amsterdam. 1968. [N. S.] V. V. NEMYTSKH and V. V. STEPANOV, Qualitative theory of Differential Equations. Princeton, Princeton University Press, 1960. [P. M.] J. PALIS and W. DE MELO, Geometric Theory of Dynamical Systems, SpringerVerlag, New York, 1982. [Sh] D. S. SHAFER, Singularities of Gradient Vectorfields in R3. Journal of Diff. Eq., t. 47, 1983, p. 317-326. [Sm] D. SMART, Fixed point theorems. Cambridge University Press, 1974. [Ta] F. TAKENS, Singularities of Vector Fields. Publ. Math. IHES, t. 43, 1974, p. 47-100. [We] J. C. WELLS, Invariant Manifolds of Non-Linear Operators. Pacific Journal of Math., t. 62, 1976, p. 285-293. [Ya] S. YAMAMURO, Differential calculus in topological linear spaces. Lecture Notes in Math., t. 374, 1974.

[Br]

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n° 2-1986.

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--.-r

-

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--

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/