THE MIXEO PROBLEM FOR THE ELASTIC ANISQTROPIC HALFPLANE (SBESSANNAIA ZAKMGRA I&IA UPS~~OI ANIZOTROPNOI POLUPLOSKOSTI) PYM Yo1.26, No.5, f962, pp.
896-906
V.Z. SVEKLO (Kalininerad) (Received
1. Fornulation
of
Decenbet
the
a solution that is continuous tions of motion [l]
problem.
8,
1961)
ive seek a regular
up to second order
derivatives
solution, i.e. of the equa-
(1.1)
at points conditions
in an anisotropic
and the following
The right
sides
halfplane
y>O
under the following
initial
boundary conditions:
of these
2. The Green-Volterra we have the Green-x’olterra
equations
formula. formula
contain
given
functions.
Jn the general
case of anisotropy
anisotropic
The elastic
1355
halfplane
tll is a solution of Equations (1.1) corresponding to the uZJ vZ corresponds to the body Xl, YI, while the solution Y,; Tdenotes an arbitrary volume in the xyt space which is
Here ulr body forces
forces X,, bounded by the surface
S with interior
P (u, @) = a, cos (m)
normal n
+ z,, cos (ny)
p SOS at
-
(at) (2.2)
p $
Q (% 4 = z,, cos (ns) -f- a, cos (ny) This strong 3. tions
formula remains valid discontinuity
cos (nt)
even when one of the solutions
has a true
[21.
Fundamental solutions. We of the homogeneous Equations
shall
construct
(1.1).
some special
‘Ihese will
solu-
be nonzero within
a characteristic cone whose vertex is at the point (x0, y,,, t,) and will have the required singularity on its axis n = x,,, y = y,,. We call them fundamental
solutions.
Let us introduce
the functions
4j ----
1
Between ftj and hi there &jLZj 6j
We specify
U&O’= i
7 = as -
=
t0j’hj’
to
exists
-
incident
=
t -
(5
(: -
= a0,t + dljr
d)* ’
the relation
LG = dtlj8 + a;lr” -
0 -‘%I)
8
disturbances
+
(Y
-
90)
h
=
1 (3.2)
0
in the form
RS i r CEhj (E) 0; (&) dE,
vkoo = i
j=i
Re
i f Llj (E) o;(t)
d$
(3.3)
j=l
where O*
O&j
L*j
=
-
eh;
Fj” Fj”
=
0~ C%ja
Forming the solutions condition
fk= f, 2). ,~j** (Ojalo~jo
[31 for
+
hj B
= -
lj*OG”)
+
the reflected
that the boundary is stress
free,
“j”o*j’+
Lej -
L*I~tj” Pi”
Chj*
(3.4)
disturbances
and superposing
under the these solu-
tions on the corresponding incident solutions, we obtain the fundamental solutions uLo, vko. These are nonzero in the interior of a characteristic
cone and zero
on its
boundary and in its
exterior.
Upon passage
1356
V.Z.
Sveklo
throughthe pertinentcharacteristicsurface,lying either within the cone mentionedabove or comprisingits surface,the first derivativesof these solutionssuffer a discontinuity. However,as is easily shown, the kinematicand dynamicconditionsof compatibilityare satisfied. 4. Estimate of the fundamental solutions near the axis of the characteristic cone. To make this estimate,we show that it is sufficientto estimatethe function(3.3) for large values of %i, since only incidentdisturbanceshave singularitieson the axis of the cone. Taking into accountthe branch of hi to be chosen for c ==z a - d IIll, and writing out only the main terms, we obtain
whereby = 1,
M,M,
M12$M$+=-$,
(a - Mj’d) (d - Mj%)+
e2Mj2 = O (4.2)
From (3.2) we find 6, =
x‘ - iMjy’ q
t’,
2’ ==sz -
x0,
y’ = y -
7&j, t’ = t, -
t
For large ej we readilyobtain 02jo =t -
(4.4) IJj=a+(C-d)Mj*
(i = f, 2)
Hence lim (%jsCLQjo+hj*W*j”)= 0, and for large
ej
%j-+ 00
the main parts of the functionsekjo and ekjoo coincide.
Now it is easy to estimatethe fundamentalsolutions.We obtain 2 @lo
=
-
~2
MjAj” Re %i, j=l
VI0= -i
J3j"Re if+, j=l
13j” = ?I’$
(4.5)
The
anisotropic
elastic
It is also necessary to estimate Equations (3.3) and (4.3) we find
1357
halfplane
the derivatives
for
large
0j’
l!sing
(4.7) ‘The same result may he obtained by straightforward differentiation of the expression for uIo with respect to x. The remaining derivatives can be estimated in an analogous manner. Omitting the details of the calculations, we give the final results of the estimates of the solutions and the corresponding stresses. a) First
Formulas (4.6)
fundamental solution.
are supplemented
by
(4-Q
b) Second fundamental solution 2
u2*
3=
-
~2
I’I’
Mj-‘Aj
r’2 ’
j=l
The stresses
v** = -
i;
j=l
J
are obtained
y’t’
j&f,-‘&’
(4.9)
in the form
(4.10) c) Third
fundamental solution
u30=-c j=l For the stresses
Mj A jO f$ I
,
~8’ = i Mj-‘Bj’ j=i
KJs
(4.11)
‘j
we obtain
(4.12) The main parts
are indicated
in all
of the formulas.
1358
V.Z.
5.
Solution of the Cauehy problem for the halfplane.
solve this solution of
problem,
we apply
the Green-Volterra
and to one of the fundamental
integration
we take a portion
face S’
of a characteristic
is at the point (see
plane
(x,,
to) and, on the other S,
t = 0, and finally,
by a portion S, of
stood of
of
that S’
is
It
is
that portion
is just
on this
mental solutions that
the latter
-
portion
to a variation
l/da < 0, < l/da. that
vanish.
all
that at present
of the aforementioned
eXpreSSiOnS
for Bk have the form
+
u$bs
(nx)
-
+
surfaces
Zxy*%OS
(ny)
into
consideration
solutions,
we obtain
(up to passage
to the limit),
that depend on E Sre used. ‘Ihe
-
&4,o pa,
cos(~t)
u
+
1
(~,,Ocos(ns)
-
hand, taking
to zero body-force
the portion
(
It
of the funda-
On the other
correspond
where the index a indicates
B*-
E that cuts to be under-
of the surface
the cone that corresponds
of 0, in the interval
of the
of the
radius
the cone.
S,
of the plane
cylindrical out the axis
Uk”, Vk”’ For the region
by the sur-
by a portion
y = 0, and a portion surface
solutions
TO
to the sought
cone whose vertex
ya,
the figure),
formula
of the space
which is bounded on the one side
side
Sveklo
(\ a, cos (nx) f
7q co9 (nx)
+
$/;cos
+
2,
(lay) -
cos (ray) -
+ 6, cos (ng) -
p =C$-eos(,t))
v-
pg
cos (R&t)) l&k0-
p g
cos flat)) VkO
(5.2)
All of the integrals in Formula (5.1) are known, with the exception of the integral over S,. lhe integral over S’s is zero as a consequence of the fact that the kinematic and dynamic compatibility conditions are satisfied for the solutions uIo and uto. The integrals over S,, and S,, are known by virtue of the initial and boundary conditions. We next show that the integral over Sa, in the lirait as a - 0, is equal to a certain linear combination of the derivatives of the unknown functions u and v. On the surface
S, we have
The elastic
setting
cos (ny) =
)
=
\
[ @XkO COS cp +
11
rf2 = 5’9 +
$2
=
&l
Gykosin
and E vanish
q(~)
cp) U +
(Zyxkocos cp+ UykoSinrp) u +
i,
+ kh COScp + Gu sin cp) &to -
Since
-$ ,
w 6
where
1359
halfplane
x’ = E cos 9, y’ = E sin Q, we obtain k-n
BkdS
$-
cos (nz) =
cos (rat) = 0,
anisotropic
cos ‘p -i- uy sin cp) vk’l
and LE is a circle
together,
the unknown solution
(h
is regular,
we have,
u (z, y, t) = u (x0 + E cos y, y. +
E
dl
of radius
I
dt
E.
for example,
sin ‘f, t) =
=a(z,,y,,t)+E-~~os~+~sinp]+... 1 ux (z, y, t) = ur (2, + 8 cos cp, y. + E sin cp, t) z-
ux (20, $!o, t) +
=
1
zsincp
E
+...
etc. The omitted terms are of order ~~ and higher. Substituting Equation (5.3) and taking into account that dl = E+, we obtain
\\
Bk ds =
“in e {u (zo,yo, t) 7(G~COSq + ii
Sk
+
v
(%
Yo,
tl
p
(%~~cos
cp +
2n az” cl
+ au8
aY0
u,isincp)
dcp +
0
824
+
rxy~sin cp) dq +
6
(%k°COs2cp
i-
zxyo
sin cpcoscp) dcp +
s
0 2x s
(&,“sin
cp cos cp + %xykosin2cp) dq +
0 2x
i- -$y 8 \ (%~~~Cos~cp -k uykosin tp cos cp) dq 0 276 + au 8 s (%,xkosin cp cos cp+ uyhosin’ cp) dq aYkl 0
+
-
into
(5.3)
1360
-
V. 2.
8
\
Sveklo
[@x0COS Cp + ?x,,‘SinCp)ukO + (rxll COS Cp+ Uyosin
Ii G
0
=%(h,yO
cp) ufi’j dq] dt
tj,...
Terms which vanish when E vanishes need the integrals
(5.4)
have been omitted.
In the sequel,
we shall 2% l
s 0
sin rpcosqdq~ r.2 N
2x
* sin cpcoscpctg,
=
\
‘jG
0
2%
sin rpco9 qr
ZZZ c
4
2x
dq =
c
‘ii,
i;
6
cos cpsins g,
drp = 0
‘Z
2s 5
cos4
fp -
2n
sin2 4 g, ~09 9,
Mj2
da,=
” (1
‘jv
0
+
MjP
sin2cpCO@9 - Mi2 sin4q (5.5)
dT=
r.4 3’p
s 0
It is easy to convince oneself that in Equation (5.4) the coefficients of n(x,,, yo, t) and v(no, y,,, t) are equal to zero for all of the fundamental solutions. In addition, as a consequence of Fquation (5.5)‘ the following integrals are zero for the first and second f~d~ental solutions 2% 0
s
(a,,“sin Q,cos fp + zwk‘sin2 tp) drp = ‘{ (z~~~%os~ cp + uv&%in cp cos cp) dcp = 0 (k =U*,
Conversely, solution.
the following
2)
integral
vanishes
for
the third
fundamental
an
s(~x*ocos2 rxy, 9 +
0
“sin q coscp) dcp = 1 (zyx3%in cp costp + q,,0sin2 cp)dtp = 0 U
Let us carry out the calculation of the first fundamental solution more detail. Ibnoting the known quantities by Dls, we write
in
The
On the circle
elastic
1361
halfplane
anisotropic
L, we have
(5.7)
dli
j,f.n.A.e2 a I 1 1 x?4’= F j=l From Hcsoke’s law it
follows
sin4, ~0s rp&I - 0 4
‘j9
that
ox(5a,Yort)=u~~+(c-d)~~, 59 (rip y,, t) = G, (G Y,, tf = d (& + &) We indicate
next the values
eiy the use of Equations
Analogous
calculations
2x
K
2
=
s6
E2
0
,,%A
(5.5)
(c- 4
E$_Ua& (5.8)
of ulo and ulo on L,
and (5.7)
we obtain
give
2
‘M .-wjAj”
cp cos cp+ q,,* sin2 ‘p) drp = 2nd ~--J-
j+
’ + Mj
(43- t)
(5.11)
1362
V,Z.
Sveklo
We turn now to the third and fourth terms of Equation (5.6). We separate and compute the coefficients of &,&I, and &Jay,, which are contained in these terms. On the basis of Equations (5.51, WC obtailt
(5.12)
Equation
(5.6)
can
be rewritten
in
the
form
We have
diIj J.fj2d +
a-
= Zi-c~dui j=~‘-
-h
n.
(to-
t) = 2na (to -
t)
(5.14)
= 2n (c + d) (to -
t)
(5.15)
j
Analogously
=-2&i
rIj(C,--a) j=l
Equation
(5.13)
takes on the form
where qI(s) and E vanish si~ltan~~l~. tain in the limit the first auxiliary fundamental solution
&zf’ SC
u~+(c+d$&--t)dt=4
0
Here
Letting E tend to zero, we obequation corresponding to the first
(5.16)
The elastic
anirotropic
1363
halfplane
(5.17) In an analogous manner, by applying the Green-Volterra required solution and the remaining fundamental solution, second and third auxiliary relationships
2n*’ (c+ d)&+ S[
formula to the we obtain the
a a$] (t, - t) dt = Da
0
(5.18) 0
ulO, where D, and D are obtained from D, by a change of the functions d and u30, vSo, respectively. v* To complete the problem we O to uzo, VI rewrite Equations (1.1) in the form
Differentiating Fquations (5.17) and (5.18) with respect to the corresponding arguments, collecting terms, and integrating by parts, we obtain, with the aid of Equations (5.19)
u @09 Yo* to) = uo(% Yo)+ uo’ (501 Yo)to+
+5x (50,yo, t) (to -
t) dt +
0
+2&(as+$) vh
Yo* 43)=
vo6% Yo) + v’o(209Yo) to +
$ \Y(501Yo, q (to -
(5.20) t) dt +
0 +
‘(EL2)
2nP
allo
These formulas give the solution of the problem that has been posed in closed form. Furthermore, they generalize the known result of Sobolev k?] relating to th e isotropic body. Analogous results may also be obtained in a more general case of anisotropy - for example, in the case of four elastic constants [3] .
1364
Svek 1o
V. Z.
6.
Effect
of
point
sources.
the
effect
of
various
the
action
of
an instantaneous
Fe assume
that
sorts
up to
the
of
onset
We turn
in accordance
with
the
of
impulse
on an unbounded
of
the
oscillation,
disturbance
uo ($1 Y) = vo (x9Y) = 09 Then,
now to
sources
investigation
of
in particular, anisotropic
the medium is
to plane.
at rest
u’o (x9Y) = 8’0(4 Y) = 0 we obtain
(S. 20),
for
an unbounded
(6.1) plane
where
Dk = -
sss
vko = vkoO(6.3)
ulr’== uk“‘,
(Xuko + Yvko) dxdy dt,
T
I!ere
T is
a portion
of
the xyt
bounded
space,
by the
large
surface
of
at the point (n,, yO, t,), and the the characteristic cone, constructed plane t = 0. Because of the singularities uko, vkoj It is not possible in
(6.2)
tion
to directly
sign
in
insert
the differentiation
the calculation
and yO. IIowever,
in order
of
the
sign
derivatives
to compute
these
of
under
nk with
derivatives,
the integrarespect
to x0
we may represent
D, in the form
\\s(
Xuko + Yv,$‘) dxdydt
& = -
(A-Q” + Y2)h-O) dx dy dt
-
(6.4)
T’LT’,
where
T’ E is
in the
first
a circular integral,
cylinder of the interior
radius E and height t0 - q(~) . I!ence, boundary of the region of integra-
tion does not depend on x,, and yO. (3n the other ary of this region can also be made independent ments
by virtue
in the
of
the properties
differentiation
of
the
first
y0 the derivative may be inserted be rewritten in t!le form
of
the
fundamental
term of under
the
‘”
u (20, yo, to) =
*x $1 0
+($$+f$)Y]dr-&
hand, the external boundof the indicated argu-
(x0, yo, t) (to - t) dTY-
(6.4) integral
solutions.
with
respect
sign
Hence, to x0 and
and (6.2)
2&-ss\ [(tg + c$) x T-T’,
a Xu,“da+&\\Xu,“ds+ azo. Q at GE
may
4
The
elastic
t.
u (x0, y,, t,) = +
5Y (x0,
Y,,
1365
halfplane
anisotropic
t) (to- t) dt -
(6.5)
sss K- -
aua~ aus0
&
0
1x +
x
aY0
T-T,
We calculate next the terms containing an integral over uE. For small E the functions uko, vko can be replaced by the estimates (4.6), (4.9), and (4.11). This allows one to use certain results from the theory of the logarithmic potential in the calculations. ‘Ihe functions x’ I r’2
I’
are
harmonic
on the
a
ax
y; / r?,
yi'
plane
where
xyj,
=
ss
a
aYjo a22"
sider
yj
= Mjy.
Oje
‘I;
= 2’2 f
On this
plane
ss
CT. is
l\p’(x, -1
p%?Tdxdyi+-$
10 ss
I
a region t h’e sum
bounded
by the
of
(4.6)
and (4.11)
we have
(6.7)
yj) ydxdyj 3 (x0, yj0)
J
(6.8)
x2 + yj2/hfj 2 = e2. We con-
ellipse
Xu,“dxdy %
(6.6)
dx dyi
p” In 7, dz dy, = - 2xp”
ajr
y’;
3
pis
-I
On the basis
yio,
Ojr
yj)ln+dxdyj=
l\p’(x,
Oj.5
where
-
P” (‘9 Yj) In $ dx dyi = \ 1 P” (X, yi) x2
Ojz
a=
yj
+ & \ \ Xu3’dx dy . . as
we have
(6.9)
V.Z.
Svcklo
+-$\\X(x,~,t)ln~dxdyj]=2neX(zo,Yo,
~iO=2Jw%~Yo*t)
t,j
Ojc
We next compute the
(to -
(6.10) sum
t)Nr’
=&\\Yvl”dxdy w OL
(6.11)
+ &llYv,‘dxdy %
We have
Mj-‘Bc[&SSY
Intdxdyj-&[[Y
j=l
lntdxdyj]=O *jc
Ojc
(6.12) Hence, by means of the results a passage
to the limit
Analogously
2,(x0,Yo,
that have been obtained,
we find
after
that
we obtain
to) = -
aus0 w-$$)X+(!$-g)Y]dxdydt s&SSSK T
(6.13) The problem of an applied
concentrated
impulse
is now solved
in the
same way as in the case of an isotropic medium. We consider the sequence from zero in a certain small of functions X,, and Y,. These are different
T, whose dimensions go to zero with increasing
region further
that
US X,
for
arbitrary
(x, y, t) dxdydt
n. b require n there should occur the equalities =
Q
(6.14j
wn
-r,
where P and Q are independent sequence
un(x0,yo,4y)= -
Y, (x, y, t) dxdydt
= P,
of n. Correspondingly,
we have a second
&4,o kpQSK azoff?$)X,a+($$+z)Y”]dxdydt ‘T*
The
anisotropic
elastic
1367
halfplane
(6.15)
Making use of the theorem of the mean and letting n tend to infinity, in the limit, the solution of the problem we obtain,
where
If,
u (50,Yo, to)=
-w
zJ (50’
-
Yo, GJ) =
P &lo -+$.J-&(Z+f$) 2np ( ax0 P &
(
&k1o aye _?g)__&!&!w)
w6)
all of the functions on the right are to be taken at n = y = t = 0. for example, Q = 0, then by using the values of uko, vVkowe find
iRe
i&A.
u (Zor Yo9 to) =
25p
*
. 1=1
where one should take into &j
=
to
-
BjSo
+
i&J..
2 Re + j=l
consideration hj (ej) y* =
-
hj02;‘)
(6.17)
2
V (20, ~0, to) = - &
(OjOl;”
(Ajo,; + W3;‘)
j
the equations
0,
6’J =
-
20 +
X’j (ej)
YO
It is easy to verify directly that the functions (6.17) satisfy the equations of motion in the absence of body forces. Hence they give the solution of the problem of the action of an instantaneous impulse applied to an anisotropic plane along the direction of the x-axis. That is, Formulas (6.16) give the solution of the problem of the action of an instantaneous impulse, with components P and Q, applied at the origin of the reference axes on an anisotropic plane. It is easy to show that the inequality c < a - d is not essential. However, these constants should satisfy the inequality c < a t d. ‘he latter is the condition of hyperbolicity of the system of Equations (1.1). Setting c = a - d, we arrive at the solution for the isotropic medium which was found by Sobolev.
BIBLIOGRAPHY 1.
V. A., K resheniiu dinamicheskich gosti dlia anizotropnogo tela (On the in the plane theory of elasticity for Vol. 25, No. 5, 1961.
Sveklo.
zadach ploskoi teorii uprusolution of dynamic problems an anisotropic medium). PMM
V.Z.
1368
2.
Frank,
F. and Mises,
ratematicheskoi Mathematical
3.
Sveklo, tions 1949.
R.,
fiziki Physics).
Sveklo
Differentsial’nye (Differential
i and
integral’nye
Integral
uravneniia
Equations
of
ONTI, 193’7.
V. A. , Uprugie kolebaniia of an anisotropic body).
anizotropnogo Uchen.
zap.
tela
(Elastic
Leningr.
un-ta,
Translated
vibra1’7,
No.
by
E.E. 2.