PERGAMON
International Journal of Engineering Science 37 (1999) 299±314
Two-dimensional problems for thermoelasticity, with two relaxation times in spherical regions under axisymmetric distributions Hany H. Sherief *, Fouad A. Megahed Department of Mathematics, Faculty of Science, University of Qatar, Doha, Qatar Received 4 March 1998 (Communicated by E. S. S° UHUBIÇ )
Abstract Two-dimensional (2D) axisymmetric problems are considered within the context of the theory of thermoelasticity, with two relaxation times. The general solution is obtained in the Laplace transform domain by using a direct approach without the use of potential functions. The resulting formulation is utilized to solve a problem for a thick spherical shell. The surface of the shell is taken as traction free and subjected to given axisymmetric temperature distributions. The inversion of the Laplace transforms are carried out using the inversion formula of the transform together with Fourier expansion techniques. Numerical solutions are obtained for the temperature, displacement and stress distributions in the physical domain. Numerical results are represented graphically. # 1998 Elsevier Science Ltd. All rights reserved.
1. Introduction In 1967, the theory of generalized thermoelasticity with one relaxation time was introduced by Lord and Shulman [1]. The motivation behind the introduction of this theory was to deal with the apparent paradox of in®nite speeds of propagation predicted by the coupled theory of thermoelasticity, introduced by Biot [2] in 1956. The generalized equation of heat conduction is hyperbolic and, hence, automatically ensures ®nite speeds of wave propagation. This theory was extended [3] by Dhaliwal and Sherief to anisotropic media. Among the contributions to this theory are the proofs of uniqueness theorems by Ignaczak [4] and by Sherief [5]. The state space formulation for one-dimensional (1D) problems * Corresponding author. Tel.: 00-974-419134; Fax: 00-974-835061; E-mail:
[email protected]. 0020-7225/98/$19.00 # 1998 Elsevier Science Ltd. All rights reserved. PII: S 0 0 2 0 - 7 2 2 5 ( 9 8 ) 0 0 0 7 0 - 6
300
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was completed by Anwar and Sherief in Ref. [6] and by Sherief in Ref. [7]. The state space formulation for two-dimensional (2D) problems was carried out by Sherief and Anwar in Ref. [8]. The boundary element formulation was conducted by Anwar and Sherief in Ref. [9]. Sherief and Anwar have also solved a 2D problem of a thick plate with a moving heat source and a 2D problem for an in®nite cylinder, in Refs [10, 11], respectively. Sherief and Hamza have solved a 2D problem of a thick plate under axisymmetric temperature distribution, and discussed wave propagation for this theory in Ref. [12]. Green and Lindsay [13] developed the theory of thermoelasticity with two relaxation times, which is based on a generalized inequality of thermodynamics. This theory does not violate Fourier's law of heat conduction when the body under consideration has a center of symmetry. In this theory, both the equations of motion and of heat conduction are hyperbolic, but the equation of motion is modi®ed and diers from that of the coupled thermoelasticity theory. This theory was initiated by MuÈller [14]. It was further extended by Green and Laws [15]. The ®nal form used in the present work is that of Green and Lindsay [13]. This theory was also obtained independently by S° uhubi [16]. Longitudinal wave propagation for this theory was studied by Erbay and S° uhubi in Ref. [17]. Ignaczak proved a decomposition theorem in Ref. [18]. Sherief obtained the fundamental solution for this theory in Ref. [19], formulated the state space approach in Ref. [20], and solved a thermo-mechanical shock problem in Ref. [21]. The boundary integral equation formulation was carried out by Anwar and Sherief in Ref. [22]. Solutions of thermoelastic problems for spherical regions are not as numerous as those for Cartesian and cylindrical problems. Most of the treated problems are either 1D spherically symmetric ones or axisymmetric 2D problems under simplifying assumptions. Sternberg and Chakravorty [23] have solved a thermal shock uncoupled 1D problem. Hata has solved a coupled 1D thermal shock problem for a hollow sphere, caused by rapid uniform heating, in Ref. [24]. The general solution for spherically symmetric problems, with a heat source in generalized thermoelasticity valid for short times, was obtained by Sherief in Ref. [25]. Axially symmetric steady-state 2D problems in spherical regions were solved by McDowell and Sternberg in Ref. [26] and by Ignaczak in Ref. [27]. Ignaczak [28] and Piechocki [29] have solved dynamic problems in thermoelasticity by assuming that the time variable is harmonic, which tends to obscure the transient nature of the problems considered. Tanigawa and Kosako [30] have solved a transient coupled axially symmetric thermal stress problem for an in®nite medium with a spherical cavity, by neglecting inertia terms in their solution. Tanigawa and Takeuti [31] have obtained the three dimensional (3D) solution to coupled thermolelastic problems in spherical regions, again by neglecting inertia terms.
2. Formulation of the problem We consider a homogeneous isotropic thermoelastic solid under axisymmetric conditions. The axis of symmetry is the z-axis, and the origin of the system of coordinates is at the center of the sphere. We denote by (r, W, j) the spherical polar coordinates, and by t the time variable. Let T(r, W, t) be the axisymmetric temperature distribution throughout the solid. The
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
equations of motion in the absence of body forces have the form: @ 2 ui @T;i ; r 2
l 0 m 0 uj;ij m 0 mi;jj ÿ g T;i @t @t
301
1
where u i = (u, v, 0) are the components of the displacement vector, r is the density, l 0 and m 0 are Lame's moduli, is a constant that acts as a relaxation time, and g is a material constant given by g = (3l 0 + 2m 0 ) at, where at is the coecient of linear thermal expansion. The constitutive equations are given by: @T 0 0 dij ; sij l ekk dij 2m eij ÿ l T ÿ T0
2 @t where sij are the components of the stress tensor, eij are the components of the strain tensor and dij is Kronecker's delta symbol. The energy equation in the absence of heat source has the form: kT;ii rcE
@T @2 T @ui;i rtcE 2 gT0 ; @t @t @t
3
where k is the thermal conductivity, cE is the speci®c heat for processes with invariant strain tensor, t is a constant that acts as another relaxation time, and T0 is a reference temperature chosen such that v(T ÿ T0)/T0v W 1. Using the non-dimensional variables: r 0 c1 Zr;
u 0 c1 Zu;
0 c1 Z;
t 0 c21 Zt;
sij
T ÿ T0 ; y ; 0 T0 m p where Z = rcE/k and c1 =
l 0 2m 0 =r is the speed of propagation of isothermal waves. Eqs. (1)±(3) takes the following form (dropping the primes for convenience): 2 1 @ @ @u @ @y 2@ u 2 @e ÿb ; b 2 b ÿ sin W
rv ÿ y @t @r r2 sin W @W @r @W @r @t t 0 c21 Zt;
0 c21 Z;
s 0ij
4
@2 v b2 @e 1 @ @ @u @ @y b 2
rv ÿ ÿ br y ; @t @W @W @t r @W r @r @r
5
@y dij ; sij
b2 ÿ 2edij 2eij ÿ b y @t
6
2
@y @2 y @e t 2 g ;
7 @t @t @t where g = g/kZ, b 2 = (l 0 + 2m 0 )/m 0 , and b = gT0/m 0 . In the above equations e = u i,j is the r2 y
302
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
cubical dilatation given in spherical polar coordinates by: @u 2u 1 @
v sin W ;
8 @r r r sin W @W and H 2 is Laplace's operator, given in spherical polar coordinates for the case of axisymmertic distributions by: e
@2 2 @ 1 @ @ sin W : r 2 r @r r2 sin W @W @W @r 2
Eqs. (4) and (5) can be combined to give: @2 @y 2 2 r ÿ 2 e cr y ; @t @t
9
where c = b/b 2. We introduce the Laplace transform de®ned by the relation: Lf
t f
s
1
eÿst f
tdt:
0
Assuming homogeneous initial conditions, then in the Laplace transform domain, Eqs. (7) and (9) can be written as:
r2 ÿ s ÿ ts2 y gse;
10
r2 ÿ s2 e c
1 sr2 y:
11
Eliminating e between Eqs. (10) and (11), we obtain the following equation for y: fr4 ÿ s2 s
1 ts es
1 sr2 s3
1 tsgy 0;
12
where e = cg is the coupling coecient. Eq. (12) can be factorized as:
r2 ÿ k21
r2 ÿ k22 y 0;
13
where k 21 and k 22 are the roots of the characteristic equation: k4 ÿ s2 s
1 ts es
1 sk2 s3
1 ts 0;
14
because of the linearity of Eq. (13), its solution is the sum of the solutions of the equations:
r2 ÿ k21 y 0 and
r2 ÿ k22 y 0: Solving the above two equations, we obtain Y in the form: y y 1 y 2 ; where
15a
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
303
1 2 X X y1 p1 Pn
m
k2i ÿ s2 Ani In12
ki r; r n0 i1
15b
1 2 X 1 X Pn
m
k2i ÿ s2 Bni Kn12
ki r: y 2 p r n0 i1
15c
In the above equations, In and Kn denote the modi®ed Bessel functions of the ®rst and second kinds of order n, respectively. Pn is the Legendre polynomial of degree n of argument m = cos W, and A ni, B ni are parameters depending on s only, that will be determined using the boundary conditions. The function y1 is bounded at the origin, while y2 is bounded at in®nity. Eliminating y between Eqs. (10) and (11), we obtain:
r2 ÿ k21
r2 ÿ k22 e 0:
16
The solution of Eq. (16) that is compatible with Eq. (10), has the form: e e1 e2 ;
17a
where e1
1 2 X c
1 s X p Pn
m k2i Ani In12
ki r; r n0 i1
1 2 X c
1 s X e2 p Pn
m k2i Bni Kn12
ki r: r n0 i1
17b
17c
As before, e1 denotes the part of e that is bounded at the origin, while e2 denotes that part that is bounded at in®nity. In order to obtain the displacement component u, we shall use the Laplace transform of Eq. (4), namely: 2 @u 2u 2 @e @y 2 ÿ b2 s2 u e
1 ÿ b2 b
1 s : r @r r r @r @r Substituting for e and y from Eqs. (15) and (17) into Eq. (18), we obtain: r2 u
r2 u
1 2 @u 2u c
1 s X 2 ÿ b2 s2 u Pn
mf1
r f2
r: 3 r @r r r2 n0
where f1
r
2 X i1
f2
r
2 X i1
Ani frki
k2i ÿ b2 s2 In32
ki r
n 2k2i ÿ nb2 s2 In12
ki rg; Bni fÿrki
k2i ÿ b2 s2 Kn32
ki r
n 2k2i ÿ nb2 s2 Kn12
ki rg:
18
19
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H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
In obtaining the above expressions, we have used the following properties of the modifed Bessel functions [32]: d n 1=2 In1=2
kr kIn3=2
kr In1=2
kr; dr r d n 1=2 Kn1=2
kr ÿkKn3=2
kr Kn1=2
kr: dr r
20b
The solution of Eq. (19) can be written as: u u1 u2 ;
21a
where u1
u2
( 1 c
1 s X 3
r2
Pn
m
2 X
n0
i1
( 1 c
1 s X
2 X
3
r2
n0
Pn
m
i1
Ani rki In32
ki r nIn12
ki r
1 X n1
Bni ÿrki Kn32
ki r nKn12
ki r
) Cn Pn
mIn12
bsr ;
1 X n1
21b )
Dn Pn
mKn12
bsr ;
21c
where C n and D n are parameters depending on s only. In obtaining the above solutions we have made use of the following properties of the modi®ed Bessel functions [32]: d n 3=2 In3=2
kr KIn1=2
kr ÿ In3=2
kr; dr r d n 3=2 Kn3=2
kr ÿ kKn1=2
kr ÿ Kn3=2
kr: dr r
22a
22b
In order to obtain the displacement component v, we shall use the Laplace transform of Eq. (8), for the cubical dilatation, namely: e
1 @ 2 1 @
r u
v sin W; 2 r @r r sin W @W
23
which implies that: @ @u 2
v sin W r u ÿ e : @m @r r
24
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
305
Substituting on the right-hand side of Eq. (24) for u and e from Eqs. (21) and (17), then integrating the resulting euation with respect to m, we obtain: v v1 v2 ;
25a
where ( ) 1 2 X c
1 s X bsr I 3
bsr ; v1 3 mPn
m ÿ Pnÿ1
m nAni In12
ki r Cn In12
bsr n 1 n2 r2 sin W n1 i1
25b ( ) 1 2 X c
1 s X bsr K 3
bsr : mPn
m ÿ Pnÿ1
m nBni Kn12
ki r Dn Kn12
bsr ÿ v2 3 n 1 n2 r2 sin W n1 i1
25c We have used the following integral relation of the Legendre polynomials [32] in obtaining Eq. (25)a)±(25c)
mPn
m ÿ Pnÿ1
m :
26 Pn
mdm n1 It can be easily shown that v is bounded at W = 0, p, 2p. In fact: lim v lim v lim v 0:
W40
W4p
W42p
From Eq. (2), it follows that the stress components in the Laplace transform domain have the following form: @u
b2 ÿ 2e ÿ b
1 sy; @r 2 @v 2u
b2 ÿ 2e ÿ b
1 sy; s WW r @W r 2 cot W 2u s ff v
b2 ÿ 2e ÿ b
1 sy; r r 1 @u v @v ÿ ; s rW r @W r @r s rf s Wf 0: s rr 2
27a
27b
27c
27d
27e
Substituting from Eqs. (15), (17) and (21), into Eq. (27)a), we obtain: s rr s rr1 s rr2 ; where
28a
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H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
s rr1
1 2c
1 s X 5
r2
1 X n1
Pn
m
n0
2 X
Ani
i1
1 n
n ÿ 1 b2 s2 r2 In12
ki r ÿ 2rki In32
ki r 2
Cn Pn
m
n ÿ 1In12
bsr bsrIn32
bsr ;
28b
and s rr2
1 2c
1 ÿ s X 5
r2
1 X n1
n0
Pn
m
2 X
Bni
i1
1 2 2 2 n
n ÿ 1 b s r Kn12
ki r 2
Dn Pn
m
n ÿ 1Kn12
bsr ÿ bsrKn32
bsr :
28c
Substituting from Eqs. (21) and (25) into Eq. (27)d), we obtain: s rW s rW1 s rW2 ;
29a
where s rW1
s rW2
X 1 2 2c
1 s X mP
m ÿ P
m nAni
n ÿ 1In12
ki r ki rIn32
ki r n nÿ1 5 r2 sin W n1 i1 Cn 1 2 2 2 2
n ÿ 1 b s r In12
bsr ÿ bsrIn32
bsr ; 2
n 1
X 1 2 2c
1 s X 5 mPn
m ÿ Pnÿ1
m nBni
n ÿ 1Kn12
ki r ÿ ki rKn32
ki r r2 sin W n1 i1 Dn 1
n2 ÿ 1 b2 s2 r2 Kn12
bsrKn32
bsr ; 2
n 1
29b
29c
where we have used the relation [32]: dPn
cos W n cos WPn
cos W ÿ Pnÿ1
cos W: dW sin W
30
The remaining stress components can be obtained in a similar manner. Eqs. (15), (21), (25), (28) and (29) give the general solution of the problem in the Laplace transform domain in terms of the parameters A ni, B ni, C n and D n. These parameters can be obtained from the boundary condition of the particular problem under consderation.
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
307
3. Application In order to illustrate the above results, we shall solve a problem for a thick spherical shell whose surfaces are spheres with centers at the origin and of radii a and b (a < b). The surfaces of the shell are assumed to be traction free. The inner and outer surfaces of the shell are in contact with media of known axisymmetric temperatures F1(m, t) and F2(m, t), with heat transfer coecients of L1 and L2, respectively. The conditions that the inner and outer surfaces are traction free, give, in the Laplace transform domain, the four equations: s rr
a; W; s 0;
31
s rr
b; W; s 0;
32
s rW
a; W; s 0;
33
s rW
b; W; s 0:
34
The thermal boundary conditions, give, on the inner and outer surfaces, respectively: qr
a; W; t L1 F1
m; t ÿ y
a; W; t;
35
qr
b; W; t L2 y
a; W; t ÿ F2
m; t;
36
where qr is the heat ¯ux in the radial direction. Using Fourier's law of heat conduction, which is valid for the theory of thermoelasticity with two relaxation times [13], namely: qn ÿk
@T ; @n
where qn is the component of the heat ¯ux vector in direction of the outward normal n. Using the non-dimensional variables used earlier, together with the non-dimensional heat ¯ux vector q 0 n = qn/kT0c1Z and dropping the prime, we obtain: qn ÿ
@y : @n
Eqs. (35) and (36) in the Laplace transform domain, thus, take the following form: W; s @y
a; W; s ÿL1 F1
m; s; ÿ L1 y
a; @r
37
W; s @y
b; W; s L2 F2
m; s: L2 y
b; @r
38
308
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
Expanding the functions F1(m, s) and F2(m, s) in a series of Legendre polynomials, we obtain: Fi
m; s
1 X
fni
sPn
m;
i 1; 2;
39a
n0
where 2n 1 fni
s 2
1
Fi
m; sPn
mdm;
i 1; 2; n 0; 1; 2; . . .
39b
ÿ1
Dierentiating both sides of the equations and using Eq. (20a) and (20b), we obtain: 1 2 nn o X @y 1 1 X Pn
m Ani
k2i ÿ s2 In12
ki r ki In32
ki r ; p r @r r n0 i1
40a
1 2 nn o X @y 2 1 X Pn
m Bni
k2i ÿ s2 Kn12
ki r ÿ ki Kn32
ki r : p r @r r n0 i1
40b
Using Eqs. (28), (40) and (15), Eqs. (31), (32), (37) and (38) give upon equating coecients of P0(m) on both sides: 2 X p
k2i ÿ s2 fA0i L1 I12
ki a ÿ ki I32
ki aB0i L1 K12
ki a ki K32
ki ag L1 af01
s;
41
2 X p
k2i ÿ s2 fA0i L2 I12
ki b ki I32
ki bB0i L2 K12
ki b ÿ ki K32
ki bg L2 bf02
s;
42
i1
i1
2 X fA0i b2 s2 a2 I12
ki a ÿ 4aki I32
ki aB0i b2 s2 a2 K12
ki a 4aki K32
ki ag 0;
43
2 X fA0i b2 s2 b2 I12
ki b ÿ 4bki I32
ki bB0i b2 s2 b2 K12
ki b 4bki K32
ki bg 0:
44
i1
i1
Eqs. (41)±(44) are a set of four linear equations in the four unknown parameters A 01, A 02, B 01 and B 02, which can be easily solved to give the four unknowns. We will omit the details here.
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
309
For n > 0, Eqs. (15), (28), (29) and (40), together with Eqs. (31)±(34), (37) and (38), give upon equating coecients of P n(m) on both sides: 2 X i1
1 2 2 2 Ani n
n ÿ 1 b s a In12
ki a ÿ 2aki In32
ki a Cn
n ÿ 1In12
bsa bsaIn32
bsa 2
2 X
Bni
i1
1 n
n ÿ 1 b2 s2 a2 Kn12
ki a 2aki Kn32
ki a 2
Dn
n ÿ 1Kn12
bsa ÿ bsaKn32
bsa 0; 2 X i1
45
1 2 2 2 Ani n
n ÿ 1 b s b In12
ki b ÿ 2bki In32
ki b Cn
n ÿ 1In12
bsb bsbIn32
bsb 2
2 X
Bni
i1
1 2 2 2 n
n ÿ 1 b s b Kn12
ki b 2bki Kn32
ki b 2
Dn
n ÿ 1Kn12
bsb ÿ bsbKn32
bsb 0; 2 X i1
h i nAni
n ÿ 1In12
ki a ki aIn32
2 X i1
46
Cn 1
n2 ÿ 1 b2 s2 a2 In12
bsa ÿ bsaIn32
bsa 2
n 1
nBni
n ÿ 1Kn12
ki a ÿ ki aKn32
ki a
Dn 1 2 2 2 2 n ÿ 1 b s a Kn12
bsa bsaKn32
bsa 0; 2
n 1 2 X i1
Cn nAni
n ÿ 1In12
ki bIn32
ki b
n 1
2 X i1
47
1 2 2 2 n ÿ 1 b s b In12
bsb ÿ bsbIn32
bsb 2 2
nBni
n ÿ 1Kn12
ki b ÿ ki bKn32
ki b
Dn
n 1
1 2 2 2 n ÿ 1 b s b Kn12
bsb bsbKn32
bsb 0; 2 2
48
310
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
h 2 i hn i X n 2 2 ÿ L1 In12
ki a ki In32
ki a Bni ÿ L1 Kn12
ki a ÿ ki Kn32
ki a
ki ÿ s Ani a a i1 p ÿL1 afn1
s;
49
2 n hn i hn io X L2 In12
ki b ki In32
ki b Bni L2 Kn12
ki b ÿ ki Kn32
ki b
k2i ÿ s2 Ani b b i1
p L2 bfn2
s:
50
Eqs. (45)±(50) are a set of six linear equations in the six unknown parameters A n1, A n2, B n1, B n2, C n and D n, which can be solved to give the six unknowns. We will omit the details here. Actually, both linear systems are solved numerically during the process of the numerical inversion of the Laplace transform. This completes the solution of the problem in the Laplace transform domain.
4. Inversion of the Laplace transforms We shall now outline the numerical inversion method used to ®nd the solution in the physical domain. Let f(r, W, s) be the Laplace transform of a function f(r, W, t). The complex inversion formula for Laplace transforms can be written as: 1 f
r; W; t 2pi
di1
W; sds; est f
r;
dÿi1
where d is an arbitrary real number greater than all the real parts of the singularities of f(r, W, s). Taking s = d + iy, the above integral takes the form: edt f
r; W; t 2p
1
W; d iyy: eity f
r;
ÿ1
Expanding the function h(r, W, t) = exp(ÿdt)f(r, W, t) in a Fourier series in the interval [0, 2 T], we obtain the approximate formula [33]: f
r; W; t f1
r; W; t ED ; where 1 X 1 f1
r; W; t c0
r; W; t ck
r; W; t; 2 k1
for
0RtR2T;
51
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
311
and ck
r; W; t
edt W; d ikp=T; Reeikpt=T f
r; T
k 0; 1; 2
52
ED, the discretization error, can be made arbitrarily small by choosing the constant d large enough [33]. Since the in®nite series in Eq. (51) can only be summed up to a ®nite number N of terms, the approximate value of f(r, W, t) becomes: N X 1 fN
r; W; t c0
r; W; t ck
r; W; t; 2 k1
for
0RtR2T:
53
Using the above formula to evaluate f(r, W, t), we introduce a truncation error ET that must be added to the discretization error to produce the total approximation error. Two methods are used to reduce the total error. First, the ``Korrecktur'' method [33] is used to reduce the discretization error. Next, the e-algorithm is used to reduce the truncation error and, hence, to accelerate convergence. The Korrecktur method uses the following formula to evaluate the function f(r, W, t): f
r; W; t f1
r; W; t ÿ e2dT f1
r; W; 2T t E 0D ; where the discretization error vE 0 DvWvEDv [33]. Thus, the approximate value of f(r, W, t) becomes: fNK
r; W; t fN
r; W; t ÿ eÿ2dT fN 0
r; W; 2T t;
54
N 0 is an integer such that N 0 < N. We shall now describe the e-algorithm that is used to accelerate the convergence of the series in Eq. (53). Let N be an odd natural number, and let: sm
r; W; t
m X
ck
r; W; t
k1
be the sequence of partial sums of Eq. (53). We de®ne the E-sequence by: e0;m 0; e1;m sm
Table 1 The constants of the problem k = 386 m 0 = 3.86 1010 b2=4 E = 0.0168 L1 = 1
at = 1.78 10 ÿ 5 l 0 = 7.76 1010 T0 = 293 t = 0.02 L2 = 2
cE = 383.1 r = 8954 b = 0.042 = 0.02 a= 1
Z = 8886.73 c1 = 4.158 103 g = 1.61 c = 0.01 b= 2
312
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
Fig. 1. Temperature distribution.
and ep1;m epÿ1;m1 1=
ep;m1 ÿ ep;m ;
p 1; 2; 3; . . .
It can be shown that [33] the sequence e1;1 ; e3;1 ; e5;1 ; . . . ; eN;1 converges to f(r, W, t) + ED ÿc0/2 faster than the sequence of partial sums sm ; m 1; 2; 3; . . . The actual procedure used to invert the Laplace transforms consists of using Eq. (54) together with the e-algorithm. The values of d and T are chosen according to the criteria outlined in Ref. [33].
Fig. 2. Displacement distribution.
H.H. Sherief, F.A. Megahed / International Journal of Engineering Science 37 (1999) 299±314
313
Fig. 3. Radial stress distribution.
5. Numerical Results The copper material was chosen for purposes of numerical evaluations. The constants of the problem are shown in Table 1. The normalized temperatures of the inner and outer surroundings were taken, respectively, as: Fi
m; t m2 ; F2
m; t m3 : We thus obtain from Eq. (39)a) and (39b): f01
s 1=3s; f21
s 2=s; f11
s f31
s f41
s 0: f12
s 3=5s; f32
s 2=5s; f02
s f22
s f12
s 0: The in®nite series in all the above solutions thus terminate after n = 3. The computations were performed for three values of non-dimensional time, namely t = 0.05, t = 0.1 and t = 0.2. The numerical technique outlined above was used to obtain the temperature, the displacement, and the radial stress distributions as functions of r for W = 0. In all the ®gures, solid lines represent the fuction when t = 0.05, lines with an asterisk marker represent the function when t = 0.1, while lines with a dot marker represent the function when t = 0.2. The normalized temperature increment, y, is represented by the graph in Fig. 1. The displacement u is shown in Fig. 2. The radial stress component s n is shown in Fig. 3. The phenomenon of ®nite speeds of propagation is manifested in all these ®gures. For the smallest values of time considered we see that the heat eects of the surrounding media is localized in a region adjacent to the walls. This region expands with the passage of time to ®ll the whole cylinder for large values of time. This region corresponds to the propagation of wave fronts from the surfaces of the shell. This is not the case when using the coupled equation of heat conduction, where the thermal eects extend to ®ll the whole shell immediately.
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